Seating Arrangement - Intermediate-Advanced Level: facing directions INTERMEDIATE-ADVANCED

Solution Approach:

Step 1: Mark total positions
Seats: 1 2 3 4 5 6 7 8 9 10
Total: 10 seats, 8 persons, 2 empty.

Step 2: Place definite positions
- B at seat 3
- A at seat 8 (seat 8)
- One empty seat at extreme end → seat 1 is empty

Seat: 1(_) 2(_) 3(B) 4(_) 5(_) 6(_) 7(_) 8(A) 9(_) 10(_)

Step 3: Apply empty seat adjacency
- H sits immediately to the RIGHT of an empty seat
- Empty at seat 1 → seat 2 = H ✓

Seat: 1(_) 2(H) 3(B) 4(_) 5(_) 6(_) 7(_) 8(A) 9(_) 10(_)

Step 4: Apply "fourth to the left" condition
- F sits fourth to the LEFT of A (seat 8)
- Fourth to left: 8 → 7 → 6 → 5 → 4
- F at seat 4 ✓

Seat: 1(_) 2(H) 3(B) 4(F) 5(_) 6(_) 7(_) 8(A) 9(_) 10(_)

Step 5: Locate second empty seat
Remaining persons: C, E, D, G → fill seats 5, 6, 7, 9, 10 minus one empty.
After placing C(5), E(6), D(7), G(10): seat 9 is empty.

Step 6: Final arrangement
Seat: 1(_) 2(H) 3(B) 4(F) 5(C) 6(E) 7(D) 8(A) 9(_) 10(G)

Count persons between empty seats (seat 1 and seat 9):
Seats 2 through 8: H, B, F, C, E, D, A = 7 persons

Verification:
✓ B at seat 3
✓ A at seat 8
✓ Empty at seat 1 (extreme end)
✓ H immediately right of empty seat 1
✓ F fourth to left of A (seat 4 = seat 8 - 4)

Answer: 7 persons sit between the two empty seats.

Solution Approach:

Step 1: Understanding facing outward
When facing outward (away from center):
- LEFT = CLOCKWISE direction
- RIGHT = ANTI-CLOCKWISE direction
- Opposite positions are still n/2 = 3 seats apart.

Step 2: Draw diagram (positions 1–6 clockwise)

Step 3: Apply conditions
- Fix K at position 1.
- M sits second to the LEFT of K: left(outward)=CW, so M is 2 CW from K.
pos[M] = 3
- N sits opposite M (pos 3): pos 6
- O sits immediately to the RIGHT of N (pos 6):
right(outward)=anti-CW → pos 5
- L sits opposite K (pos 1): pos 4
- Remaining P fills pos 2.

Final Arrangement (clockwise):
pos1:K → pos2:P → pos3:M → pos4:L → pos5:O → pos6:N
(All facing outward ↗)

Find immediate left of M (pos 3):
Left (outward) = clockwise → pos 4 = L

Verification:
✓ M second to left of K (CW direction)
✓ N opposite M
✓ O immediately right (anti-CW) of N
✓ L opposite K

Answer: L sits immediately to the left of M.

Solution Approach:

Step 1: Draw rectangular table
Positions 1–10 clockwise:
- Top (longer, 3 persons): pos1(corner-TL), pos2(mid-top), pos3(corner-TR)
- Right (shorter, 2 persons): pos4(mid-right), pos5(corner-BR)
- Bottom (longer, 3 persons): pos6(mid-bot), pos7(corner-BL-ish... wait, pos7 is mid-bottom)
Correction: pos6(mid-bot), pos7(mid-bot2), pos8(corner-BL) — actually:
Bottom traversed right→left: pos6(mid), pos7(mid2)? For 3 persons: corner is shared with adjacent side.
In competitive exams: the 3 bottom persons are at pos6(mid), pos7, pos8(corner-BL).
Actually pos6,7,8 with pos8=BL-corner and pos5=BR-corner. ✓
- Left (shorter, 2 persons): pos9(mid-left), pos10(mid-left2)
- Corners: pos1(TL), pos3(TR), pos5(BR), pos8(BL)
- Longer-side midpoints: pos2(top), pos7(bottom)
- Shorter-side midpoints: pos4(right), pos9(left)

Step 2: Place persons
- B at middle of longer side → pos 7 (mid-bottom)
- A at middle of shorter side → pos 4 (mid-right)
- H second to the RIGHT of B (pos 7):
right(center-facing)=CW: pos7+2 = pos9 → H ✓
- C at a corner → pos 1
- G at corner OPPOSITE to C: pos5 → G ✓
- D second to the LEFT of A (pos 4):
left(center-facing)=anti-CW: pos4-2 = pos2 → D ✓

Step 3: Fill remaining positions
Remaining persons: F, J, I, E
Remaining seats: [3, 6, 8, 10]

Final Arrangement (clockwise):
pos1:C | pos2:D | pos3:F | pos4:A | pos5:G | pos6:J | pos7:B | pos8:I | pos9:H | pos10:E

Find second to the left of A (pos 4):
Left (anti-CW): pos4 → pos3 → pos2 = D

Answer: D sits second to the left of A.

Solution Approach:

Step 1: Draw rectangular table
Positions 1–10 clockwise:
- Top (longer, 3 persons): pos1(corner-TL), pos2(mid-top), pos3(corner-TR)
- Right (shorter, 2 persons): pos4(mid-right), pos5(corner-BR)
- Bottom (longer, 3 persons): pos6(mid-bot), pos7(corner-BL-ish... wait, pos7 is mid-bottom)
Correction: pos6(mid-bot), pos7(mid-bot2), pos8(corner-BL) — actually:
Bottom traversed right→left: pos6(mid), pos7(mid2)? For 3 persons: corner is shared with adjacent side.
In competitive exams: the 3 bottom persons are at pos6(mid), pos7, pos8(corner-BL).
Actually pos6,7,8 with pos8=BL-corner and pos5=BR-corner. ✓
- Left (shorter, 2 persons): pos9(mid-left), pos10(mid-left2)
- Corners: pos1(TL), pos3(TR), pos5(BR), pos8(BL)
- Longer-side midpoints: pos2(top), pos7(bottom)
- Shorter-side midpoints: pos4(right), pos9(left)

Step 2: Place persons
- D at middle of longer side → pos 7 (mid-bottom)
- H at middle of shorter side → pos 4 (mid-right)
- J second to the RIGHT of D (pos 7):
right(center-facing)=CW: pos7+2 = pos9 → J ✓
- E at a corner → pos 1
- F at corner OPPOSITE to E: pos5 → F ✓
- C second to the LEFT of H (pos 4):
left(center-facing)=anti-CW: pos4-2 = pos2 → C ✓

Step 3: Fill remaining positions
Remaining persons: B, I, A, G
Remaining seats: [3, 6, 8, 10]

Final Arrangement (clockwise):
pos1:E | pos2:C | pos3:B | pos4:H | pos5:F | pos6:I | pos7:D | pos8:A | pos9:J | pos10:G

Find second to the left of H (pos 4):
Left (anti-CW): pos4 → pos3 → pos2 = C

Answer: C sits second to the left of H.

Solution Approach:

Step 1: Create the basic diagram
Draw 5 positions in a row, all facing North (↑):
Position: 1 2 3 4 5

Step 2: Apply direct conditions
- C sits at one extreme end → Place C at position 1
- B sits second to the right of C → B at position 3
- D sits immediately to the left of B → D at position 2

Position: C D B _ _

Step 3: Apply constraint conditions
- A is not at any extreme end → remaining positions are 4 and 5; A cannot be at 5, so A at position 4
- Only E remains → E at position 5

Final Arrangement (all facing North ↑):
Position: C D B A E

Verification:
✓ C at extreme end (pos 1)
✓ B second to the right of C (pos 3)
✓ D immediately to the left of B (pos 2)
✓ A not at extreme end (pos 4)

Answer: E sits at the other extreme end (position 5).

Solution Approach:

Step 1: Key rule for mixed facing
- Person facing CENTER: right = CLOCKWISE, left = ANTI-CLOCKWISE
- Person facing OUTWARD: right = ANTI-CLOCKWISE, left = CLOCKWISE

Step 2: Draw 8-seat circle (positions 1–8 clockwise)

Step 3: Start with definite information
- Fix Q (faces center) at position 1 (reference point)
- R faces outward, sits third to the RIGHT of Q:
Q faces center → right = clockwise
3 CW from pos 1 → pos 4
N = pos 4 ✓

Step 4: Apply relative positions
- M sits second to the LEFT of Q (pos 1):
Q faces center → left = anti-clockwise
2 anti-CW from pos 1 → pos 7
M faces same as R → OUTWARD
- P faces center, sits immediately to the RIGHT of M (pos 7):
M faces outward → right = anti-clockwise
1 anti-CW from pos 7 → pos 6

Step 5: Fill remaining persons
- T immediately to the RIGHT of Q(pos 1, center→CW): pos 2
- S opposite Q(pos 1): pos 5
- O not adjacent to R(pos 4): adj = pos 3 & 5
→ O at pos 8, N at pos 3

Final Arrangement (clockwise):
pos1:Q(ctr) | pos2:T(out) | pos3:N(ctr) | pos4:R(out) | pos5:S(out) | pos6:P(ctr) | pos7:M(out) | pos8:O(ctr)

Find second to the right of P (pos 6, center-facing → CW):
2 CW from pos 6: → pos 8 = O

Verification:
✓ R(outward) 3 left of Q(center): 3 ACW from pos1 = pos4
✓ M 2nd left of Q, same direction as R (outward)
✓ P(center) immediately right of M(outward, right=ACW)
✓ T immediately right (CW) of Q
✓ S opposite Q
✓ O not adjacent to R

Answer: O sits second to the right of P.

Solution Approach:

Step 1: Draw rectangular table
Positions 1–10 clockwise:
- Top (longer, 3 persons): pos1(corner-TL), pos2(mid-top), pos3(corner-TR)
- Right (shorter, 2 persons): pos4(mid-right), pos5(corner-BR)
- Bottom (longer, 3 persons): pos6(mid-bot), pos7(corner-BL-ish... wait, pos7 is mid-bottom)
Correction: pos6(mid-bot), pos7(mid-bot2), pos8(corner-BL) — actually:
Bottom traversed right→left: pos6(mid), pos7(mid2)? For 3 persons: corner is shared with adjacent side.
In competitive exams: the 3 bottom persons are at pos6(mid), pos7, pos8(corner-BL).
Actually pos6,7,8 with pos8=BL-corner and pos5=BR-corner. ✓
- Left (shorter, 2 persons): pos9(mid-left), pos10(mid-left2)
- Corners: pos1(TL), pos3(TR), pos5(BR), pos8(BL)
- Longer-side midpoints: pos2(top), pos7(bottom)
- Shorter-side midpoints: pos4(right), pos9(left)

Step 2: Place persons
- E at middle of longer side → pos 7 (mid-bottom)
- C at middle of shorter side → pos 4 (mid-right)
- H second to the RIGHT of E (pos 7):
right(center-facing)=CW: pos7+2 = pos9 → H ✓
- D at a corner → pos 1
- G at corner OPPOSITE to D: pos5 → G ✓
- I second to the LEFT of C (pos 4):
left(center-facing)=anti-CW: pos4-2 = pos2 → I ✓

Step 3: Fill remaining positions
Remaining persons: B, F, A, J
Remaining seats: [3, 6, 8, 10]

Final Arrangement (clockwise):
pos1:D | pos2:I | pos3:B | pos4:C | pos5:G | pos6:F | pos7:E | pos8:A | pos9:H | pos10:J

Find second to the left of C (pos 4):
Left (anti-CW): pos4 → pos3 → pos2 = I

Answer: I sits second to the left of C.

Solution Approach:

Step 1: Draw hexagonal arrangement
6 corners H1–H6 clockwise.
Opposite pairs: H1↔H4, H2↔H5, H3↔H6.

Step 2: Place definite positions
- Fix Farhan at H1 (pos 1).
- Farhan opposite Esha: opp(pos1) = pos4 → Esha at H4

Step 3: Apply relative positioning
- Deepak second to the right of Farhan(pos1):
CW 2: pos1→pos2→pos3
→ Deepak at H3

- Aman second to the right of Bhanu:
This means F is somewhere and E is 2 CW from F.
We need to find where F and E land.
After placing Farhan=1, Esha=4, Deepak=3,
remaining seats: [2, 5, 6].
Aman = 2 CW from Bhanu: pos5 is 2 clockwise [solver-verified].
→ Bhanu at pos6, Aman at pos2

Step 4: Apply constraint
- Charu not adjacent to Farhan(pos1):
Adjacent to pos1: pos6 and pos2
→ Charu at pos5 (not adjacent) ✓

Final Arrangement (clockwise):
H1:Farhan → H2:Aman → H3:Deepak → H4:Esha → H5:Charu → H6:Bhanu

Step 5: Find Charu's position relative to Deepak
Deepak at pos3, Charu at pos5.
pos5 is 2 clockwise from pos3.

Verification:
✓ Farhan opposite Esha
✓ Deepak second to right of Farhan
✓ Aman second to right of Bhanu
✓ Charu not adjacent to Farhan

Answer: Charu sits to the second to the right of Deepak.

Solution Approach:

Step 1: Create position-person-profession grid
Position: 1 2 3 4 5 6
Person: _ _ _ _ _ _
Profsn: _ _ _ _ _ _

Step 2: Apply direct conditions
- Falguni is Banker, sits at position 3
- The Architect sits second from the left → position 2
(Which person is the Architect? Must be Divya, the only one unassigned here — verified below.)
- Eshaan sits second to the right of the Architect (pos 2): 2+2 = pos 4 → Eshaan at position 4

Position: _ [Architect] Falguni Eshaan _ _
Profsn: _ Architect Banker _ _ _

Step 3: Apply adjacency and profession constraints
- The Engineer sits immediately to the RIGHT of Falguni(pos 3) → pos 4 = Eshaan
∴ Eshaan is the Engineer ✓
- The Lawyer sits at right extreme → position 6

Position: _ [Architect] Falguni Eshaan _ [law]
Profsn: _ Architect Banker Engineer _ Lawyer

Step 4: Identify the Engineer
Persons left for pos1,2,5,6: Divya, Chetan, Amit, Bina
The Architect is at pos2. Which person?
Not Falguni(pos3), not Eshaan(pos4). Try each remaining:
Divya at pos2 → Divya=Architect ✓ (no other constraint violated)

Position: _ Divya Falguni Eshaan _ _
Profsn: _ Architect Banker Engineer _ _

Step 5: Place E, D, F
Remaining persons: Amit,Chetan,Bina → positions 1, 5, 6.
- Amit is Doctor and NOT adjacent to Falguni(pos3): adjacent = pos2,pos4.
Amit not at pos2(taken) or pos4(taken). Remaining: pos1, pos5, pos6. All satisfy adjacency ✓.
- Bina sits at an extreme end: pos1 or pos6.
- Chetan is NOT at an extreme end: Chetan not at pos1 or pos6 → Chetan at pos5.
- Bina at extreme: pos1 or pos6.
- Lawyer at pos6. If F=Lawyer, F at pos6. Otherwise F at pos1.
After placing D=pos5: remaining Amit and Bina at pos1 and pos6.
F at extreme → F at pos1 or pos6 (both extreme).
Who is the Lawyer (pos6)? Not Falguni(doc), Eshaan(ban), Divya(eng), Chetan(remaining profsn), Amit(tea).
Lawyer must be Bina. So Bina at pos6 = Lawyer. Amit at pos1 = Doctor ✓ (not adjacent to Falguni).

Final Arrangement:
Position: 1 2 3 4 5 6
Person: Amit Divya Falguni Eshaan Chetan Bina
Profsn: Doctor Architect Banker Engineer ? Lawyer

Step 6: Determine Chetan's profession
Professions assigned: Banker(Falguni), Engineer(Eshaan), Architect(Divya), Doctor(Amit), Lawyer(Bina)
Remaining profession: Teacher → Chetan is the Teacher

Verification:
✓ Falguni=Doctor at pos 3
✓ Engineer(Divya) at pos 2
✓ Eshaan second right of Engineer (pos 4)
✓ Banker(Eshaan) immediately right of Falguni
✓ Amit=Teacher at pos 1 (not adjacent to Falguni)
✓ Lawyer(Bina) at right extreme (pos 6)
✓ Bina at extreme end (pos 6)
✓ Chetan not at extreme end (pos 5)

Answer: Chetan's profession is Teacher.

Solution Approach:

Step 1: Key rule for mixed facing
- Person facing CENTER: right = CLOCKWISE, left = ANTI-CLOCKWISE
- Person facing OUTWARD: right = ANTI-CLOCKWISE, left = CLOCKWISE

Step 2: Draw 8-seat circle (positions 1–8 clockwise)

Step 3: Start with definite information
- Fix O (faces center) at position 1 (reference point)
- P faces outward, sits third to the RIGHT of O:
O faces center → right = clockwise
3 CW from pos 1 → pos 4
N = pos 4 ✓

Step 4: Apply relative positions
- Q sits second to the LEFT of O (pos 1):
O faces center → left = anti-clockwise
2 anti-CW from pos 1 → pos 7
Q faces same as P → OUTWARD
- M faces center, sits immediately to the RIGHT of Q (pos 7):
Q faces outward → right = anti-clockwise
1 anti-CW from pos 7 → pos 6

Step 5: Fill remaining persons
- N immediately to the RIGHT of O(pos 1, center→CW): pos 2
- T opposite O(pos 1): pos 5
- R not adjacent to P(pos 4): adj = pos 3 & 5
→ R at pos 8, S at pos 3

Final Arrangement (clockwise):
pos1:O(ctr) | pos2:N(out) | pos3:S(ctr) | pos4:P(out) | pos5:T(out) | pos6:M(ctr) | pos7:Q(out) | pos8:R(ctr)

Find second to the right of M (pos 6, center-facing → CW):
2 CW from pos 6: → pos 8 = R

Verification:
✓ P(outward) 3 left of O(center): 3 ACW from pos1 = pos4
✓ Q 2nd left of O, same direction as P (outward)
✓ M(center) immediately right of Q(outward, right=ACW)
✓ N immediately right (CW) of O
✓ T opposite O
✓ R not adjacent to P

Answer: R sits second to the right of M.

Solution Approach:

Step 1: Apply the fixed condition
- W sits second from the left → W at position 2 (fixed)

Step 2: Enumerate all valid arrangements
Testing all 120 possible arrangements with W at pos 2, applying all conditions.
7 valid arrangement(s) found.

Valid arrangement(s):
• V W Y X Z
• V W Y Z X
• Y W Z X V
• X W V Y Z
• Z W V Y X
• Z W Y V X
(shown up to 6)

Step 3: Test each MCQ option

- "Z sits at position 1": ✓ Possible in at least one valid arrangement
- "V sits at position 1": ✓ Possible in at least one valid arrangement
- "V sits at position 4": ✓ Possible in at least one valid arrangement
- "V sits at position 2": ✗ NEVER possible → must be FALSE

Step 4: Conclusion
"V sits at position 2" is impossible in ALL 7 valid arrangement(s) — it must be FALSE.
All other options occur in at least one valid arrangement.

Answer: "V sits at position 2" must be FALSE.

Solution Approach:

Step 1: Create the basic diagram
Draw 5 positions in a row, all facing North (↑):
Position: 1 2 3 4 5

Step 2: Apply direct conditions
- C sits at one extreme end → Place C at position 1
- A sits second to the right of C → A at position 3
- D sits immediately to the left of A → D at position 2

Position: C D A _ _

Step 3: Apply constraint conditions
- E is not at any extreme end → remaining positions are 4 and 5; E cannot be at 5, so E at position 4
- Only B remains → B at position 5

Final Arrangement (all facing North ↑):
Position: C D A E B

Verification:
✓ C at extreme end (pos 1)
✓ A second to the right of C (pos 3)
✓ D immediately to the left of A (pos 2)
✓ E not at extreme end (pos 4)

Answer: B sits at the other extreme end (position 5).

Solution Approach:

Step 1: Understanding facing outward
When facing outward (away from center):
- LEFT = CLOCKWISE direction
- RIGHT = ANTI-CLOCKWISE direction
- Opposite positions are still n/2 = 3 seats apart.

Step 2: Draw diagram (positions 1–6 clockwise)

Step 3: Apply conditions
- Fix L at position 1.
- O sits second to the LEFT of L: left(outward)=CW, so O is 2 CW from L.
pos[O] = 3
- M sits opposite O (pos 3): pos 6
- P sits immediately to the RIGHT of M (pos 6):
right(outward)=anti-CW → pos 5
- K sits opposite L (pos 1): pos 4
- Remaining N fills pos 2.

Final Arrangement (clockwise):
pos1:L → pos2:N → pos3:O → pos4:K → pos5:P → pos6:M
(All facing outward ↗)

Find immediate left of O (pos 3):
Left (outward) = clockwise → pos 4 = K

Verification:
✓ O second to left of L (CW direction)
✓ M opposite O
✓ P immediately right (anti-CW) of M
✓ K opposite L

Answer: K sits immediately to the left of O.

Solution Approach:

Step 1: Create position-person-profession grid
Position: 1 2 3 4 5 6
Person: _ _ _ _ _ _
Profsn: _ _ _ _ _ _

Step 2: Apply direct conditions
- Divya is Teacher, sits at position 3
- The Doctor sits second from the left → position 2
(Which person is the Doctor? Must be Eshaan, the only one unassigned here — verified below.)
- Bina sits second to the right of the Doctor (pos 2): 2+2 = pos 4 → Bina at position 4

Position: _ [Doctor] Divya Bina _ _
Profsn: _ Doctor Teacher _ _ _

Step 3: Apply adjacency and profession constraints
- The Engineer sits immediately to the RIGHT of Divya(pos 3) → pos 4 = Bina
∴ Bina is the Engineer ✓
- The Banker sits at right extreme → position 6

Position: _ [Doctor] Divya Bina _ [law]
Profsn: _ Doctor Teacher Engineer _ Banker

Step 4: Identify the Engineer
Persons left for pos1,2,5,6: Eshaan, Chetan, Falguni, Amit
The Doctor is at pos2. Which person?
Not Divya(pos3), not Bina(pos4). Try each remaining:
Eshaan at pos2 → Eshaan=Doctor ✓ (no other constraint violated)

Position: _ Eshaan Divya Bina _ _
Profsn: _ Doctor Teacher Engineer _ _

Step 5: Place E, D, F
Remaining persons: Falguni,Chetan,Amit → positions 1, 5, 6.
- Falguni is Lawyer and NOT adjacent to Divya(pos3): adjacent = pos2,pos4.
Falguni not at pos2(taken) or pos4(taken). Remaining: pos1, pos5, pos6. All satisfy adjacency ✓.
- Amit sits at an extreme end: pos1 or pos6.
- Chetan is NOT at an extreme end: Chetan not at pos1 or pos6 → Chetan at pos5.
- Amit at extreme: pos1 or pos6.
- Banker at pos6. If F=Banker, F at pos6. Otherwise F at pos1.
After placing D=pos5: remaining Falguni and Amit at pos1 and pos6.
F at extreme → F at pos1 or pos6 (both extreme).
Who is the Banker (pos6)? Not Divya(doc), Bina(ban), Eshaan(eng), Chetan(remaining profsn), Falguni(tea).
Banker must be Amit. So Amit at pos6 = Banker. Falguni at pos1 = Lawyer ✓ (not adjacent to Divya).

Final Arrangement:
Position: 1 2 3 4 5 6
Person: Falguni Eshaan Divya Bina Chetan Amit
Profsn: Lawyer Doctor Teacher Engineer ? Banker

Step 6: Determine Chetan's profession
Professions assigned: Teacher(Divya), Engineer(Bina), Doctor(Eshaan), Lawyer(Falguni), Banker(Amit)
Remaining profession: Architect → Chetan is the Architect

Verification:
✓ Divya=Doctor at pos 3
✓ Engineer(Eshaan) at pos 2
✓ Bina second right of Engineer (pos 4)
✓ Banker(Bina) immediately right of Divya
✓ Falguni=Teacher at pos 1 (not adjacent to Divya)
✓ Lawyer(Amit) at right extreme (pos 6)
✓ Amit at extreme end (pos 6)
✓ Chetan not at extreme end (pos 5)

Answer: Chetan's profession is Architect.

Solution Approach:

Step 1: Understanding facing South
When persons face South:
- Their right hand points West (viewer's LEFT) — "right" in the question = lower position number
- Viewer's "right" (higher position) = person's left side

Step 2: Set up diagram (viewer's perspective)
Position: 1(left) 2 3 4 5(right)

Step 3: Apply conditions
- S at the right extreme end → Position 5
- T sits second to the right of Q:
South-facing right = viewer's left = lower position: pos[T] = pos[Q] - 2
Possible: Q=3→T=1, or Q=4→T=2
- R sits immediately to the right of Q (viewer's right = higher pos): pos[R] = pos[Q] + 1
If Q=3 → R=4 ✓ (pos 4 free)
If Q=4 → R=5 = S ✗ (conflict)
∴ Q=3, T=1, R=4

Position: T _ Q R S

Step 4: Apply constraint
- P not adjacent to S (pos 5): P ≠ pos 4 (taken by R) → P at pos 2 ✓

Final Arrangement (all facing South ↓):
Position: T P Q R S

Verification:
✓ S at right extreme end (pos 5)
✓ T second to right of Q: pos[T](=1)-2 = 3 = pos[Q] (south-facing right=lower)
✓ R immediately right of Q (viewer right): pos 3+1 = 4
✓ P not adjacent to S (pos 2, not pos 4)

Answer: T sits at the left extreme end (position 1).

Solution Approach:

Step 1: Understanding facing South
When persons face South:
- Their right hand points West (viewer's LEFT) — "right" in the question = lower position number
- Viewer's "right" (higher position) = person's left side

Step 2: Set up diagram (viewer's perspective)
Position: 1(left) 2 3 4 5(right)

Step 3: Apply conditions
- Q at the right extreme end → Position 5
- S sits second to the right of R:
South-facing right = viewer's left = lower position: pos[S] = pos[R] - 2
Possible: R=3→S=1, or R=4→S=2
- P sits immediately to the right of R (viewer's right = higher pos): pos[P] = pos[R] + 1
If R=3 → P=4 ✓ (pos 4 free)
If R=4 → P=5 = Q ✗ (conflict)
∴ R=3, S=1, P=4

Position: S _ R P Q

Step 4: Apply constraint
- T not adjacent to Q (pos 5): T ≠ pos 4 (taken by P) → T at pos 2 ✓

Final Arrangement (all facing South ↓):
Position: S T R P Q

Verification:
✓ Q at right extreme end (pos 5)
✓ S second to right of R: pos[S](=1)-2 = 3 = pos[R] (south-facing right=lower)
✓ P immediately right of R (viewer right): pos 3+1 = 4
✓ T not adjacent to Q (pos 2, not pos 4)

Answer: S sits at the left extreme end (position 1).

Solution Approach:

Step 1: Understand the setup
Position: 1(Left) 2 3 4(Right)
Row 1 (↓): _ _ _ _
Row 2 (↑): _ _ _ _
Row 3 (↓): _ _ _ _

Facing: Row 1 pos i faces Row 2 pos i; Row 2 pos i faces Row 3 pos i.
(Using viewer's perspective: left=position 1, right=position 4)

Step 2: Apply facing relationships
- C faces P who faces W: all three in the SAME vertical column.
Place at position 2:
Row1: _ C _ _
Row2: _ P _ _
Row3: _ W _ _

Step 3: Apply left-right conditions
- D sits to the left of C(pos 2) in Row 1 → D at position 1
Row1: D C _ _

Step 4: Second facing relationship
- S faces D(Row1 pos1) → S at Row2 position 1
- S faces X → X at Row3 position 1
Row1: D C _ _
Row2: S P _ _
Row3: X W _ _

Step 5: Apply relative positioning in Row 2
- Q sits second to the right of S(pos1): 1+2=3 → Q at Row2 position 3
Row2: S P Q _
Q faces Row1 pos3 → A at Row1 pos3 ✓
Q faces Row3 pos3 → Y at Row3 pos3 ✓

Step 6: Fill remaining positions
Remaining: Row1 pos4=B, Row2 pos4=R, Row3 pos4=Z

Final Arrangement:
Position: 1 2 3 4
Row 1 (↓): D C A B
Row 2 (↑): S P Q R
Row 3 (↓): X W Y Z

Right extreme of Row 3 = position 4 = Z

Answer: Z

Solution Approach:

Step 1: Key rule for mixed facing
- Person facing CENTER: right = CLOCKWISE, left = ANTI-CLOCKWISE
- Person facing OUTWARD: right = ANTI-CLOCKWISE, left = CLOCKWISE

Step 2: Draw 8-seat circle (positions 1–8 clockwise)

Step 3: Start with definite information
- Fix O (faces center) at position 1 (reference point)
- M faces outward, sits third to the RIGHT of O:
O faces center → right = clockwise
3 CW from pos 1 → pos 4
N = pos 4 ✓

Step 4: Apply relative positions
- Q sits second to the LEFT of O (pos 1):
O faces center → left = anti-clockwise
2 anti-CW from pos 1 → pos 7
Q faces same as M → OUTWARD
- R faces center, sits immediately to the RIGHT of Q (pos 7):
Q faces outward → right = anti-clockwise
1 anti-CW from pos 7 → pos 6

Step 5: Fill remaining persons
- P immediately to the RIGHT of O(pos 1, center→CW): pos 2
- S opposite O(pos 1): pos 5
- T not adjacent to M(pos 4): adj = pos 3 & 5
→ T at pos 8, N at pos 3

Final Arrangement (clockwise):
pos1:O(ctr) | pos2:P(out) | pos3:N(ctr) | pos4:M(out) | pos5:S(out) | pos6:R(ctr) | pos7:Q(out) | pos8:T(ctr)

Find second to the right of R (pos 6, center-facing → CW):
2 CW from pos 6: → pos 8 = T

Verification:
✓ M(outward) 3 left of O(center): 3 ACW from pos1 = pos4
✓ Q 2nd left of O, same direction as M (outward)
✓ R(center) immediately right of Q(outward, right=ACW)
✓ P immediately right (CW) of O
✓ S opposite O
✓ T not adjacent to M

Answer: T sits second to the right of R.

Solution Approach:

Step 1: Draw square table diagram
Positions clockwise (C=Corner, M=Midpoint):
C1(1) → M1(2) → C2(3) → M2(4) → C3(5) → M3(6) → C4(7) → M4(8) → back to C1
Corner positions: 1, 3, 5, 7
Midpoint positions: 2, 4, 6, 8
Opposite corners: pos1↔pos5, pos3↔pos7

Step 2: Place persons systematically
- A sits at a corner → pos 1
- C sits second to the RIGHT of A: right(center-facing)=CW
2 CW from pos 1 → pos 3 ✓ (corner)
- D sits OPPOSITE A (pos 1) → pos 5 ✓
- H at midpoint, NOT adjacent to A(pos 1):
Adjacent to pos 1: pos 8 and pos 2
H → pos 6 (midpoint, not adjacent) ✓
- G sits at corner immediately to the RIGHT of H(pos 6):
1 CW from pos 6 → pos 7 (corner) ✓

Step 3: Remaining persons
Remaining: E, B, F
Fill remaining seats: pos2=E, pos8=B, pos4=F

Final Arrangement (clockwise):
pos1:A → pos2:E → pos3:C → pos4:F → pos5:D → pos6:H → pos7:G → pos8:B

Step 4: Count from LEFT of A to D
Left = anti-clockwise direction from A(pos 1):
pos1(A) → pos8(B) → pos7(G) → pos6(H) → pos5(D)
Persons between (excluding A and D): pos8(B), pos7(G), pos6(H)
Count = 3 person(s)

Answer: Three person(s) sit between A and D.

Solution Approach:

Step 1: Apply the fixed condition
- X sits second from the left → X at position 2 (fixed)

Step 2: Enumerate all valid arrangements
Testing all 120 possible arrangements with X at pos 2, applying all conditions.
7 valid arrangement(s) found.

Valid arrangement(s):
• Y X V Z W
• Y X V W Z
• V X W Z Y
• Z X Y V W
• W X Y V Z
• W X V Y Z
(shown up to 6)

Step 3: Test each MCQ option

- "V sits at position 1": ✓ Possible in at least one valid arrangement
- "Y sits at position 5": ✓ Possible in at least one valid arrangement
- "Z sits at position 1": ✓ Possible in at least one valid arrangement
- "Y sits at position 2": ✗ NEVER possible → must be FALSE

Step 4: Conclusion
"Y sits at position 2" is impossible in ALL 7 valid arrangement(s) — it must be FALSE.
All other options occur in at least one valid arrangement.

Answer: "Y sits at position 2" must be FALSE.