Seating Arrangement - Intermediate Level: row seating INTERMEDIATE

Solution Approach:

Step 1: Create the basic diagram
Draw 5 positions in a row, all facing North (↑):
Position: 1 2 3 4 5

Step 2: Apply direct conditions
- A sits at one extreme end → Place A at position 1
- E sits second to the right of A → E at position 3
- D sits immediately to the left of E → D at position 2

Position: A D E _ _

Step 3: Apply constraint conditions
- B is not at any extreme end → remaining positions are 4 and 5; B cannot be at 5, so B at position 4
- Only C remains → C at position 5

Final Arrangement (all facing North ↑):
Position: A D E B C

Verification:
✓ A at extreme end (pos 1)
✓ E second to the right of A (pos 3)
✓ D immediately to the left of E (pos 2)
✓ B not at extreme end (pos 4)

Answer: C sits at the other extreme end (position 5).

Solution Approach:

Step 1: Draw concentric circles
Inner circle: 4 positions I1(12 o'clock), I2(3), I3(6), I4(9) — all occupied.
Outer circle: 6 positions O1–O6 clockwise — 4 occupied, 2 empty.
Facing alignment: I1↔O1, I2↔O2, I3↔O4, I4↔O5 (O3 and O6 are empty).

Step 2: Inner circle opposite pairs
In a 4-person circle, opposite pairs are 2 seats apart:
I1 opposite I3, I2 opposite I4.

Step 3: Place inner circle persons
- B sits immediately to the right of A (inner circle, facing center: right=CW)
→ A and B are adjacent. Possible: A=I1, B=I2 or A=I2, B=I3, etc.
- C sits opposite to B:
If B=I2, then C=I4. Then A=I1 (left of I2), D=I3 (remaining).
All constraints consistent ✓.

Inner: I1=A, I2=B, I3=D, I4=C

Step 4: Place outer circle persons
- R faces A(I1) → R at O1 ✓
- Outer occupied seats: O1, O2, O4, O5. Empty: O3, O6.
- P second to right of Q (outer, facing center: right=CW, step 2):
Remaining outer persons: P,Q,S at O2, O4, O5.
R=O2 → Q=O4, S=O5 ✓
R=O4 → Q=O6(empty) ✗
R=O5 → Q=O1=P ✗
∴ Q=O2, P=O4, S=O5 ✓
- S(O5) immediately to the LEFT of an empty:
Left(CW) of O5 = O4(P) — NOT empty.
RIGHT(CW) of O5 = O6(empty). So O5 is immediately to the LEFT of O6(empty) ✓.

Step 5: Answer the question
B is at I2. Opposite of I2 = I4 = C.

Final Arrangements:
Inner (CW): I1=A, I2=B, I3=D, I4=C
Outer (CW): O1=R, O2=Q, O3=empty, O4=P, O5=S, O6=empty

Verification:
✓ R faces A (I1↔O1)
✓ B immediately right of A (I2 is CW from I1)
✓ C opposite B (I4 opposite I2)
✓ P second right of Q (O4 = O2 + 2 CW)
✓ S(O5) immediately left of empty O6

Answer: C sits opposite to B.

Solution Approach:

Step 1: Draw the double row setup
Row 1 faces South (↓), Row 2 faces North (↑)
Person at position i in Row 1 faces person at position i in Row 2.

Position: 1 2 3 4 5
Row 1 (↓): _ _ _ _ _
Row 2 (↑): _ _ _ _ _

Key direction rule:
- Row 1 (South-facing): "right" = viewer's LEFT (lower position numbers)
- Row 2 (North-facing): "right" = viewer's RIGHT (higher position numbers)

Step 2: Place Row 1 persons
- C sits 4th from the left end of Row 1 → Row 1, pos 4
- B sits at an extreme end: pos 1 or pos 5
- D sits second to the RIGHT of B (south-facing → lower position):
pos[D] = pos[B] - 2
If B at pos 1 → pos[D] = -1 (invalid ✗)
If B at pos 5 → pos[D] = 3 ✓ (pos 3 is free)
∴ B at pos 5, D at pos 3 ✓

Row 1: _ _ D C B
Remaining E,A at pos 1 and 2 (either order — pinned next).

Step 3: Place Row 2 persons
- R faces C (pos 4) → R at Row 2, pos 4
- P sits second to the LEFT of R (north-facing → lower position):
pos[P] = pos[R] - 2 = 2 → P at Row 2 pos 2 ✓
- Q sits at extreme end of Row 2: pos 1 or pos 5
- T is NOT adjacent to R (pos 4): adjacent = pos 3 and pos 5
So T ≠ pos 3 and T ≠ pos 5
Remaining positions for Q,S,T: pos 1, pos 3, pos 5
T not at pos 3 or pos 5 → T at pos 1
Q at extreme → pos 5 (since pos 1 is T) ✓
S fills pos 3 ✓

Row 2: T P S R Q

Final Arrangement:
Position: 1 2 3 4 5
Row 1 (↓): E/A E/A D C B
Row 2 (↑): T P S R Q

Find who faces D:
D is at Row 1, position 3.
Person at Row 2, position 3 = S

Answer: S faces D.

Solution Approach:

Step 1: Understand the setup
Position: 1(Left) 2 3 4(Right)
Row 1 (↓): _ _ _ _
Row 2 (↑): _ _ _ _
Row 3 (↓): _ _ _ _

Facing: Row 1 pos i faces Row 2 pos i; Row 2 pos i faces Row 3 pos i.
(Using viewer's perspective: left=position 1, right=position 4)

Step 2: Apply facing relationships
- D faces R who faces Y: all three in the SAME vertical column.
Place at position 2:
Row1: _ D _ _
Row2: _ R _ _
Row3: _ Y _ _

Step 3: Apply left-right conditions
- B sits to the left of D(pos 2) in Row 1 → B at position 1
Row1: B D _ _

Step 4: Second facing relationship
- Q faces B(Row1 pos1) → Q at Row2 position 1
- Q faces X → X at Row3 position 1
Row1: B D _ _
Row2: Q R _ _
Row3: X Y _ _

Step 5: Apply relative positioning in Row 2
- P sits second to the right of Q(pos1): 1+2=3 → P at Row2 position 3
Row2: Q R P _
P faces Row1 pos3 → A at Row1 pos3 ✓
P faces Row3 pos3 → W at Row3 pos3 ✓

Step 6: Fill remaining positions
Remaining: Row1 pos4=C, Row2 pos4=S, Row3 pos4=Z

Final Arrangement:
Position: 1 2 3 4
Row 1 (↓): B D A C
Row 2 (↑): Q R P S
Row 3 (↓): X Y W Z

Right extreme of Row 3 = position 4 = Z

Answer: Z

Solution Approach:

Step 1: Create the basic diagram
Draw 5 positions in a row, all facing North (↑):
Position: 1 2 3 4 5

Step 2: Apply direct conditions
- E sits at one extreme end → Place E at position 1
- C sits second to the right of E → C at position 3
- B sits immediately to the left of C → B at position 2

Position: E B C _ _

Step 3: Apply constraint conditions
- D is not at any extreme end → remaining positions are 4 and 5; D cannot be at 5, so D at position 4
- Only A remains → A at position 5

Final Arrangement (all facing North ↑):
Position: E B C D A

Verification:
✓ E at extreme end (pos 1)
✓ C second to the right of E (pos 3)
✓ B immediately to the left of C (pos 2)
✓ D not at extreme end (pos 4)

Answer: A sits at the other extreme end (position 5).

Solution Approach:

Step 1: Mark total positions
Seats: 1 2 3 4 5 6 7 8 9 10
Total: 10 seats, 8 persons, 2 empty.

Step 2: Place definite positions
- F at seat 3
- G at seat 8 (seat 8)
- One empty seat at extreme end → seat 1 is empty

Seat: 1(_) 2(_) 3(F) 4(_) 5(_) 6(_) 7(_) 8(G) 9(_) 10(_)

Step 3: Apply empty seat adjacency
- H sits immediately to the RIGHT of an empty seat
- Empty at seat 1 → seat 2 = H ✓

Seat: 1(_) 2(H) 3(F) 4(_) 5(_) 6(_) 7(_) 8(G) 9(_) 10(_)

Step 4: Apply "fourth to the left" condition
- E sits fourth to the LEFT of G (seat 8)
- Fourth to left: 8 → 7 → 6 → 5 → 4
- E at seat 4 ✓

Seat: 1(_) 2(H) 3(F) 4(E) 5(_) 6(_) 7(_) 8(G) 9(_) 10(_)

Step 5: Locate second empty seat
Remaining persons: C, B, A, D → fill seats 5, 6, 7, 9, 10 minus one empty.
After placing C(5), B(6), A(7), D(10): seat 9 is empty.

Step 6: Final arrangement
Seat: 1(_) 2(H) 3(F) 4(E) 5(C) 6(B) 7(A) 8(G) 9(_) 10(D)

Count persons between empty seats (seat 1 and seat 9):
Seats 2 through 8: H, F, E, C, B, A, G = 7 persons

Verification:
✓ F at seat 3
✓ G at seat 8
✓ Empty at seat 1 (extreme end)
✓ H immediately right of empty seat 1
✓ E fourth to left of G (seat 4 = seat 8 - 4)

Answer: 7 persons sit between the two empty seats.

Solution Approach:

Step 1: Mark directions
↑ = North facing, ↓ = South facing

Step 2: Apply position-based conditions
- P sits third from the left end facing North (↑) → Position 3
- R sits at the left extreme end facing South (↓) → Position 1

Position: R(↓) _ P(↑) _ _ _

Step 3: Apply relative positioning
- T sits second to the right of P (pos 3) → Position 5
- T faces opposite direction to P (North) → T faces South (↓)
- S sits immediately to the left of T (pos 5) facing North (↑) → Position 4

Position: R(↓) _ P(↑) S(↑) T(↓) _

Step 4: Fill remaining positions
Remaining persons: U, Q
Position 2 gets U, Position 6 gets Q

Final Arrangement:
Pos: R(↓) U(↑) P(↑) S(↑) T(↓) Q(↑)

Verification:
✓ P at pos 3, facing North
✓ T at pos 5 (second right of P), facing South (opposite of P)
✓ R at pos 1 (left extreme), facing South
✓ S at pos 4 (immediately left of T), facing North

Person between R (pos 1) and P (pos 3): pos 2 = U

Answer: U sits between R and P.

Solution Approach:

Step 1: Draw concentric circles
Inner circle: 4 positions I1(12 o'clock), I2(3), I3(6), I4(9) — all occupied.
Outer circle: 6 positions O1–O6 clockwise — 4 occupied, 2 empty.
Facing alignment: I1↔O1, I2↔O2, I3↔O4, I4↔O5 (O3 and O6 are empty).

Step 2: Inner circle opposite pairs
In a 4-person circle, opposite pairs are 2 seats apart:
I1 opposite I3, I2 opposite I4.

Step 3: Place inner circle persons
- C sits immediately to the right of B (inner circle, facing center: right=CW)
→ B and C are adjacent. Possible: B=I1, C=I2 or B=I2, C=I3, etc.
- A sits opposite to C:
If C=I2, then A=I4. Then B=I1 (left of I2), D=I3 (remaining).
All constraints consistent ✓.

Inner: I1=B, I2=C, I3=D, I4=A

Step 4: Place outer circle persons
- P faces B(I1) → P at O1 ✓
- Outer occupied seats: O1, O2, O4, O5. Empty: O3, O6.
- Q second to right of R (outer, facing center: right=CW, step 2):
Remaining outer persons: Q,R,S at O2, O4, O5.
R=O2 → Q=O4, S=O5 ✓
R=O4 → Q=O6(empty) ✗
R=O5 → Q=O1=P ✗
∴ R=O2, Q=O4, S=O5 ✓
- S(O5) immediately to the LEFT of an empty:
Left(CW) of O5 = O4(Q) — NOT empty.
RIGHT(CW) of O5 = O6(empty). So O5 is immediately to the LEFT of O6(empty) ✓.

Step 5: Answer the question
C is at I2. Opposite of I2 = I4 = A.

Final Arrangements:
Inner (CW): I1=B, I2=C, I3=D, I4=A
Outer (CW): O1=P, O2=R, O3=empty, O4=Q, O5=S, O6=empty

Verification:
✓ P faces B (I1↔O1)
✓ C immediately right of B (I2 is CW from I1)
✓ A opposite C (I4 opposite I2)
✓ Q second right of R (O4 = O2 + 2 CW)
✓ S(O5) immediately left of empty O6

Answer: A sits opposite to C.

Solution Approach:

Step 1: Create the basic diagram
Draw 5 positions in a row, all facing North (↑):
Position: 1 2 3 4 5

Step 2: Apply direct conditions
- E sits at one extreme end → Place E at position 1
- D sits second to the right of E → D at position 3
- B sits immediately to the left of D → B at position 2

Position: E B D _ _

Step 3: Apply constraint conditions
- A is not at any extreme end → remaining positions are 4 and 5; A cannot be at 5, so A at position 4
- Only C remains → C at position 5

Final Arrangement (all facing North ↑):
Position: E B D A C

Verification:
✓ E at extreme end (pos 1)
✓ D second to the right of E (pos 3)
✓ B immediately to the left of D (pos 2)
✓ A not at extreme end (pos 4)

Answer: C sits at the other extreme end (position 5).

Solution Approach:

Step 1: Draw concentric circles
Inner circle: 4 positions I1(12 o'clock), I2(3), I3(6), I4(9) — all occupied.
Outer circle: 6 positions O1–O6 clockwise — 4 occupied, 2 empty.
Facing alignment: I1↔O1, I2↔O2, I3↔O4, I4↔O5 (O3 and O6 are empty).

Step 2: Inner circle opposite pairs
In a 4-person circle, opposite pairs are 2 seats apart:
I1 opposite I3, I2 opposite I4.

Step 3: Place inner circle persons
- B sits immediately to the right of D (inner circle, facing center: right=CW)
→ D and B are adjacent. Possible: D=I1, B=I2 or D=I2, B=I3, etc.
- C sits opposite to B:
If B=I2, then C=I4. Then D=I1 (left of I2), A=I3 (remaining).
All constraints consistent ✓.

Inner: I1=D, I2=B, I3=A, I4=C

Step 4: Place outer circle persons
- Q faces D(I1) → Q at O1 ✓
- Outer occupied seats: O1, O2, O4, O5. Empty: O3, O6.
- R second to right of P (outer, facing center: right=CW, step 2):
Remaining outer persons: R,P,S at O2, O4, O5.
R=O2 → Q=O4, S=O5 ✓
R=O4 → Q=O6(empty) ✗
R=O5 → Q=O1=P ✗
∴ P=O2, R=O4, S=O5 ✓
- S(O5) immediately to the LEFT of an empty:
Left(CW) of O5 = O4(R) — NOT empty.
RIGHT(CW) of O5 = O6(empty). So O5 is immediately to the LEFT of O6(empty) ✓.

Step 5: Answer the question
B is at I2. Opposite of I2 = I4 = C.

Final Arrangements:
Inner (CW): I1=D, I2=B, I3=A, I4=C
Outer (CW): O1=Q, O2=P, O3=empty, O4=R, O5=S, O6=empty

Verification:
✓ Q faces D (I1↔O1)
✓ B immediately right of D (I2 is CW from I1)
✓ C opposite B (I4 opposite I2)
✓ R second right of P (O4 = O2 + 2 CW)
✓ S(O5) immediately left of empty O6

Answer: C sits opposite to B.

Solution Approach:

Step 1: Understanding facing South
When persons face South:
- Their right hand points West (viewer's LEFT) — "right" in the question = lower position number
- Viewer's "right" (higher position) = person's left side

Step 2: Set up diagram (viewer's perspective)
Position: 1(left) 2 3 4 5(right)

Step 3: Apply conditions
- P at the right extreme end → Position 5
- T sits second to the right of S:
South-facing right = viewer's left = lower position: pos[T] = pos[S] - 2
Possible: S=3→T=1, or S=4→T=2
- R sits immediately to the right of S (viewer's right = higher pos): pos[R] = pos[S] + 1
If S=3 → R=4 ✓ (pos 4 free)
If S=4 → R=5 = P ✗ (conflict)
∴ S=3, T=1, R=4

Position: T _ S R P

Step 4: Apply constraint
- Q not adjacent to P (pos 5): Q ≠ pos 4 (taken by R) → Q at pos 2 ✓

Final Arrangement (all facing South ↓):
Position: T Q S R P

Verification:
✓ P at right extreme end (pos 5)
✓ T second to right of S: pos[T](=1)-2 = 3 = pos[S] (south-facing right=lower)
✓ R immediately right of S (viewer right): pos 3+1 = 4
✓ Q not adjacent to P (pos 2, not pos 4)

Answer: T sits at the left extreme end (position 1).

Solution Approach:

Step 1: Understanding facing outward
When facing outward (away from center):
- LEFT = CLOCKWISE direction
- RIGHT = ANTI-CLOCKWISE direction
- Opposite positions are still n/2 = 3 seats apart.

Step 2: Draw diagram (positions 1–6 clockwise)

Step 3: Apply conditions
- Fix O at position 1.
- K sits second to the LEFT of O: left(outward)=CW, so K is 2 CW from O.
pos[K] = 3
- P sits opposite K (pos 3): pos 6
- L sits immediately to the RIGHT of P (pos 6):
right(outward)=anti-CW → pos 5
- N sits opposite O (pos 1): pos 4
- Remaining M fills pos 2.

Final Arrangement (clockwise):
pos1:O → pos2:M → pos3:K → pos4:N → pos5:L → pos6:P
(All facing outward ↗)

Find immediate left of K (pos 3):
Left (outward) = clockwise → pos 4 = N

Verification:
✓ K second to left of O (CW direction)
✓ P opposite K
✓ L immediately right (anti-CW) of P
✓ N opposite O

Answer: N sits immediately to the left of K.

Solution Approach:

Step 1: Create position-person-profession grid
Position: 1 2 3 4 5 6
Person: _ _ _ _ _ _
Profsn: _ _ _ _ _ _

Step 2: Apply direct conditions
- Eshaan is Architect, sits at position 3
- The Lawyer sits second from the left → position 2
(Which person is the Lawyer? Must be Bina, the only one unassigned here — verified below.)
- Divya sits second to the right of the Lawyer (pos 2): 2+2 = pos 4 → Divya at position 4

Position: _ [Lawyer] Eshaan Divya _ _
Profsn: _ Lawyer Architect _ _ _

Step 3: Apply adjacency and profession constraints
- The Doctor sits immediately to the RIGHT of Eshaan(pos 3) → pos 4 = Divya
∴ Divya is the Doctor ✓
- The Teacher sits at right extreme → position 6

Position: _ [Lawyer] Eshaan Divya _ [law]
Profsn: _ Lawyer Architect Doctor _ Teacher

Step 4: Identify the Engineer
Persons left for pos1,2,5,6: Bina, Amit, Chetan, Falguni
The Lawyer is at pos2. Which person?
Not Eshaan(pos3), not Divya(pos4). Try each remaining:
Bina at pos2 → Bina=Lawyer ✓ (no other constraint violated)

Position: _ Bina Eshaan Divya _ _
Profsn: _ Lawyer Architect Doctor _ _

Step 5: Place E, D, F
Remaining persons: Chetan,Amit,Falguni → positions 1, 5, 6.
- Chetan is Banker and NOT adjacent to Eshaan(pos3): adjacent = pos2,pos4.
Chetan not at pos2(taken) or pos4(taken). Remaining: pos1, pos5, pos6. All satisfy adjacency ✓.
- Falguni sits at an extreme end: pos1 or pos6.
- Amit is NOT at an extreme end: Amit not at pos1 or pos6 → Amit at pos5.
- Falguni at extreme: pos1 or pos6.
- Teacher at pos6. If F=Teacher, F at pos6. Otherwise F at pos1.
After placing D=pos5: remaining Chetan and Falguni at pos1 and pos6.
F at extreme → F at pos1 or pos6 (both extreme).
Who is the Teacher (pos6)? Not Eshaan(doc), Divya(ban), Bina(eng), Amit(remaining profsn), Chetan(tea).
Teacher must be Falguni. So Falguni at pos6 = Teacher. Chetan at pos1 = Banker ✓ (not adjacent to Eshaan).

Final Arrangement:
Position: 1 2 3 4 5 6
Person: Chetan Bina Eshaan Divya Amit Falguni
Profsn: Banker Lawyer Architect Doctor ? Teacher

Step 6: Determine Amit's profession
Professions assigned: Architect(Eshaan), Doctor(Divya), Lawyer(Bina), Banker(Chetan), Teacher(Falguni)
Remaining profession: Engineer → Amit is the Engineer

Verification:
✓ Eshaan=Doctor at pos 3
✓ Engineer(Bina) at pos 2
✓ Divya second right of Engineer (pos 4)
✓ Banker(Divya) immediately right of Eshaan
✓ Chetan=Teacher at pos 1 (not adjacent to Eshaan)
✓ Lawyer(Falguni) at right extreme (pos 6)
✓ Falguni at extreme end (pos 6)
✓ Amit not at extreme end (pos 5)

Answer: Amit's profession is Engineer.

Solution Approach:

Step 1: Mark total positions
Seats: 1 2 3 4 5 6 7 8 9 10
Total: 10 seats, 8 persons, 2 empty.

Step 2: Place definite positions
- H at seat 3
- C at seat 8 (seat 8)
- One empty seat at extreme end → seat 1 is empty

Seat: 1(_) 2(_) 3(H) 4(_) 5(_) 6(_) 7(_) 8(C) 9(_) 10(_)

Step 3: Apply empty seat adjacency
- B sits immediately to the RIGHT of an empty seat
- Empty at seat 1 → seat 2 = B ✓

Seat: 1(_) 2(B) 3(H) 4(_) 5(_) 6(_) 7(_) 8(C) 9(_) 10(_)

Step 4: Apply "fourth to the left" condition
- E sits fourth to the LEFT of C (seat 8)
- Fourth to left: 8 → 7 → 6 → 5 → 4
- E at seat 4 ✓

Seat: 1(_) 2(B) 3(H) 4(E) 5(_) 6(_) 7(_) 8(C) 9(_) 10(_)

Step 5: Locate second empty seat
Remaining persons: A, F, D, G → fill seats 5, 6, 7, 9, 10 minus one empty.
After placing A(5), F(6), D(7), G(10): seat 9 is empty.

Step 6: Final arrangement
Seat: 1(_) 2(B) 3(H) 4(E) 5(A) 6(F) 7(D) 8(C) 9(_) 10(G)

Count persons between empty seats (seat 1 and seat 9):
Seats 2 through 8: B, H, E, A, F, D, C = 7 persons

Verification:
✓ H at seat 3
✓ C at seat 8
✓ Empty at seat 1 (extreme end)
✓ B immediately right of empty seat 1
✓ E fourth to left of C (seat 4 = seat 8 - 4)

Answer: 7 persons sit between the two empty seats.

Solution Approach:

Step 1: Understanding facing South
When persons face South:
- Their right hand points West (viewer's LEFT) — "right" in the question = lower position number
- Viewer's "right" (higher position) = person's left side

Step 2: Set up diagram (viewer's perspective)
Position: 1(left) 2 3 4 5(right)

Step 3: Apply conditions
- P at the right extreme end → Position 5
- S sits second to the right of Q:
South-facing right = viewer's left = lower position: pos[S] = pos[Q] - 2
Possible: Q=3→S=1, or Q=4→S=2
- R sits immediately to the right of Q (viewer's right = higher pos): pos[R] = pos[Q] + 1
If Q=3 → R=4 ✓ (pos 4 free)
If Q=4 → R=5 = P ✗ (conflict)
∴ Q=3, S=1, R=4

Position: S _ Q R P

Step 4: Apply constraint
- T not adjacent to P (pos 5): T ≠ pos 4 (taken by R) → T at pos 2 ✓

Final Arrangement (all facing South ↓):
Position: S T Q R P

Verification:
✓ P at right extreme end (pos 5)
✓ S second to right of Q: pos[S](=1)-2 = 3 = pos[Q] (south-facing right=lower)
✓ R immediately right of Q (viewer right): pos 3+1 = 4
✓ T not adjacent to P (pos 2, not pos 4)

Answer: S sits at the left extreme end (position 1).

Solution Approach:

Step 1: Draw hexagonal arrangement
6 corners H1–H6 clockwise.
Opposite pairs: H1↔H4, H2↔H5, H3↔H6.

Step 2: Place definite positions
- Fix Deepak at H1 (pos 1).
- Deepak opposite Farhan: opp(pos1) = pos4 → Farhan at H4

Step 3: Apply relative positioning
- Bhanu second to the right of Deepak(pos1):
CW 2: pos1→pos2→pos3
→ Bhanu at H3

- Aman second to the right of Esha:
This means F is somewhere and E is 2 CW from F.
We need to find where F and E land.
After placing Deepak=1, Farhan=4, Bhanu=3,
remaining seats: [2, 5, 6].
Aman = 2 CW from Esha: pos5 is 2 clockwise [solver-verified].
→ Esha at pos6, Aman at pos2

Step 4: Apply constraint
- Charu not adjacent to Deepak(pos1):
Adjacent to pos1: pos6 and pos2
→ Charu at pos5 (not adjacent) ✓

Final Arrangement (clockwise):
H1:Deepak → H2:Aman → H3:Bhanu → H4:Farhan → H5:Charu → H6:Esha

Step 5: Find Charu's position relative to Bhanu
Bhanu at pos3, Charu at pos5.
pos5 is 2 clockwise from pos3.

Verification:
✓ Deepak opposite Farhan
✓ Bhanu second to right of Deepak
✓ Aman second to right of Esha
✓ Charu not adjacent to Deepak

Answer: Charu sits to the second to the right of Bhanu.

Solution Approach:

Step 1: Draw concentric circles
Inner circle: 4 positions I1(12 o'clock), I2(3), I3(6), I4(9) — all occupied.
Outer circle: 6 positions O1–O6 clockwise — 4 occupied, 2 empty.
Facing alignment: I1↔O1, I2↔O2, I3↔O4, I4↔O5 (O3 and O6 are empty).

Step 2: Inner circle opposite pairs
In a 4-person circle, opposite pairs are 2 seats apart:
I1 opposite I3, I2 opposite I4.

Step 3: Place inner circle persons
- B sits immediately to the right of C (inner circle, facing center: right=CW)
→ C and B are adjacent. Possible: C=I1, B=I2 or C=I2, B=I3, etc.
- D sits opposite to B:
If B=I2, then D=I4. Then C=I1 (left of I2), A=I3 (remaining).
All constraints consistent ✓.

Inner: I1=C, I2=B, I3=A, I4=D

Step 4: Place outer circle persons
- P faces C(I1) → P at O1 ✓
- Outer occupied seats: O1, O2, O4, O5. Empty: O3, O6.
- Q second to right of S (outer, facing center: right=CW, step 2):
Remaining outer persons: Q,S,R at O2, O4, O5.
R=O2 → Q=O4, S=O5 ✓
R=O4 → Q=O6(empty) ✗
R=O5 → Q=O1=P ✗
∴ S=O2, Q=O4, R=O5 ✓
- R(O5) immediately to the LEFT of an empty:
Left(CW) of O5 = O4(Q) — NOT empty.
RIGHT(CW) of O5 = O6(empty). So O5 is immediately to the LEFT of O6(empty) ✓.

Step 5: Answer the question
B is at I2. Opposite of I2 = I4 = D.

Final Arrangements:
Inner (CW): I1=C, I2=B, I3=A, I4=D
Outer (CW): O1=P, O2=S, O3=empty, O4=Q, O5=R, O6=empty

Verification:
✓ P faces C (I1↔O1)
✓ B immediately right of C (I2 is CW from I1)
✓ D opposite B (I4 opposite I2)
✓ Q second right of S (O4 = O2 + 2 CW)
✓ R(O5) immediately left of empty O6

Answer: D sits opposite to B.

Solution Approach:

Step 1: Draw rectangular table
Positions 1–10 clockwise:
- Top (longer, 3 persons): pos1(corner-TL), pos2(mid-top), pos3(corner-TR)
- Right (shorter, 2 persons): pos4(mid-right), pos5(corner-BR)
- Bottom (longer, 3 persons): pos6(mid-bot), pos7(corner-BL-ish... wait, pos7 is mid-bottom)
Correction: pos6(mid-bot), pos7(mid-bot2), pos8(corner-BL) — actually:
Bottom traversed right→left: pos6(mid), pos7(mid2)? For 3 persons: corner is shared with adjacent side.
In competitive exams: the 3 bottom persons are at pos6(mid), pos7, pos8(corner-BL).
Actually pos6,7,8 with pos8=BL-corner and pos5=BR-corner. ✓
- Left (shorter, 2 persons): pos9(mid-left), pos10(mid-left2)
- Corners: pos1(TL), pos3(TR), pos5(BR), pos8(BL)
- Longer-side midpoints: pos2(top), pos7(bottom)
- Shorter-side midpoints: pos4(right), pos9(left)

Step 2: Place persons
- F at middle of longer side → pos 7 (mid-bottom)
- I at middle of shorter side → pos 4 (mid-right)
- A second to the RIGHT of F (pos 7):
right(center-facing)=CW: pos7+2 = pos9 → A ✓
- D at a corner → pos 1
- B at corner OPPOSITE to D: pos5 → B ✓
- H second to the LEFT of I (pos 4):
left(center-facing)=anti-CW: pos4-2 = pos2 → H ✓

Step 3: Fill remaining positions
Remaining persons: J, C, E, G
Remaining seats: [3, 6, 8, 10]

Final Arrangement (clockwise):
pos1:D | pos2:H | pos3:J | pos4:I | pos5:B | pos6:C | pos7:F | pos8:E | pos9:A | pos10:G

Find second to the left of I (pos 4):
Left (anti-CW): pos4 → pos3 → pos2 = H

Answer: H sits second to the left of I.

Solution Approach:

Step 1: Draw the double row setup
Row 1 faces South (↓), Row 2 faces North (↑)
Person at position i in Row 1 faces person at position i in Row 2.

Position: 1 2 3 4 5
Row 1 (↓): _ _ _ _ _
Row 2 (↑): _ _ _ _ _

Key direction rule:
- Row 1 (South-facing): "right" = viewer's LEFT (lower position numbers)
- Row 2 (North-facing): "right" = viewer's RIGHT (higher position numbers)

Step 2: Place Row 1 persons
- B sits 4th from the left end of Row 1 → Row 1, pos 4
- C sits at an extreme end: pos 1 or pos 5
- D sits second to the RIGHT of C (south-facing → lower position):
pos[D] = pos[C] - 2
If C at pos 1 → pos[D] = -1 (invalid ✗)
If C at pos 5 → pos[D] = 3 ✓ (pos 3 is free)
∴ C at pos 5, D at pos 3 ✓

Row 1: _ _ D B C
Remaining E,A at pos 1 and 2 (either order — pinned next).

Step 3: Place Row 2 persons
- R faces B (pos 4) → R at Row 2, pos 4
- T sits second to the LEFT of R (north-facing → lower position):
pos[T] = pos[R] - 2 = 2 → T at Row 2 pos 2 ✓
- S sits at extreme end of Row 2: pos 1 or pos 5
- P is NOT adjacent to R (pos 4): adjacent = pos 3 and pos 5
So P ≠ pos 3 and P ≠ pos 5
Remaining positions for S,Q,P: pos 1, pos 3, pos 5
P not at pos 3 or pos 5 → P at pos 1
S at extreme → pos 5 (since pos 1 is P) ✓
Q fills pos 3 ✓

Row 2: P T Q R S

Final Arrangement:
Position: 1 2 3 4 5
Row 1 (↓): E/A E/A D B C
Row 2 (↑): P T Q R S

Find who faces D:
D is at Row 1, position 3.
Person at Row 2, position 3 = Q

Answer: Q faces D.

Solution Approach:

Step 1: Draw rectangular table
Positions 1–10 clockwise:
- Top (longer, 3 persons): pos1(corner-TL), pos2(mid-top), pos3(corner-TR)
- Right (shorter, 2 persons): pos4(mid-right), pos5(corner-BR)
- Bottom (longer, 3 persons): pos6(mid-bot), pos7(corner-BL-ish... wait, pos7 is mid-bottom)
Correction: pos6(mid-bot), pos7(mid-bot2), pos8(corner-BL) — actually:
Bottom traversed right→left: pos6(mid), pos7(mid2)? For 3 persons: corner is shared with adjacent side.
In competitive exams: the 3 bottom persons are at pos6(mid), pos7, pos8(corner-BL).
Actually pos6,7,8 with pos8=BL-corner and pos5=BR-corner. ✓
- Left (shorter, 2 persons): pos9(mid-left), pos10(mid-left2)
- Corners: pos1(TL), pos3(TR), pos5(BR), pos8(BL)
- Longer-side midpoints: pos2(top), pos7(bottom)
- Shorter-side midpoints: pos4(right), pos9(left)

Step 2: Place persons
- J at middle of longer side → pos 7 (mid-bottom)
- D at middle of shorter side → pos 4 (mid-right)
- I second to the RIGHT of J (pos 7):
right(center-facing)=CW: pos7+2 = pos9 → I ✓
- H at a corner → pos 1
- A at corner OPPOSITE to H: pos5 → A ✓
- B second to the LEFT of D (pos 4):
left(center-facing)=anti-CW: pos4-2 = pos2 → B ✓

Step 3: Fill remaining positions
Remaining persons: G, C, E, F
Remaining seats: [3, 6, 8, 10]

Final Arrangement (clockwise):
pos1:H | pos2:B | pos3:G | pos4:D | pos5:A | pos6:C | pos7:J | pos8:E | pos9:I | pos10:F

Find second to the left of D (pos 4):
Left (anti-CW): pos4 → pos3 → pos2 = B

Answer: B sits second to the left of D.