Seating Arrangement - Beginner-Intermediate Level: opposite positions BEGINNER-INTERMEDIATE

Solution Approach:

Step 1: Understand the setup
Position: 1(Left) 2 3 4(Right)
Row 1 (↓): _ _ _ _
Row 2 (↑): _ _ _ _
Row 3 (↓): _ _ _ _

Facing: Row 1 pos i faces Row 2 pos i; Row 2 pos i faces Row 3 pos i.
(Using viewer's perspective: left=position 1, right=position 4)

Step 2: Apply facing relationships
- D faces Q who faces Z: all three in the SAME vertical column.
Place at position 2:
Row1: _ D _ _
Row2: _ Q _ _
Row3: _ Z _ _

Step 3: Apply left-right conditions
- C sits to the left of D(pos 2) in Row 1 → C at position 1
Row1: C D _ _

Step 4: Second facing relationship
- S faces C(Row1 pos1) → S at Row2 position 1
- S faces X → X at Row3 position 1
Row1: C D _ _
Row2: S Q _ _
Row3: X Z _ _

Step 5: Apply relative positioning in Row 2
- R sits second to the right of S(pos1): 1+2=3 → R at Row2 position 3
Row2: S Q R _
R faces Row1 pos3 → B at Row1 pos3 ✓
R faces Row3 pos3 → W at Row3 pos3 ✓

Step 6: Fill remaining positions
Remaining: Row1 pos4=A, Row2 pos4=P, Row3 pos4=Y

Final Arrangement:
Position: 1 2 3 4
Row 1 (↓): C D B A
Row 2 (↑): S Q R P
Row 3 (↓): X Z W Y

Right extreme of Row 3 = position 4 = Y

Answer: Y

Solution Approach:

Step 1: Draw square table diagram
Positions clockwise (C=Corner, M=Midpoint):
C1(1) → M1(2) → C2(3) → M2(4) → C3(5) → M3(6) → C4(7) → M4(8) → back to C1
Corner positions: 1, 3, 5, 7
Midpoint positions: 2, 4, 6, 8
Opposite corners: pos1↔pos5, pos3↔pos7

Step 2: Place persons systematically
- E sits at a corner → pos 1
- G sits second to the RIGHT of E: right(center-facing)=CW
2 CW from pos 1 → pos 3 ✓ (corner)
- B sits OPPOSITE E (pos 1) → pos 5 ✓
- H at midpoint, NOT adjacent to E(pos 1):
Adjacent to pos 1: pos 8 and pos 2
H → pos 6 (midpoint, not adjacent) ✓
- C sits at corner immediately to the RIGHT of H(pos 6):
1 CW from pos 6 → pos 7 (corner) ✓

Step 3: Remaining persons
Remaining: A, D, F
Fill remaining seats: pos2=A, pos8=D, pos4=F

Final Arrangement (clockwise):
pos1:E → pos2:A → pos3:G → pos4:F → pos5:B → pos6:H → pos7:C → pos8:D

Step 4: Count from LEFT of E to B
Left = anti-clockwise direction from E(pos 1):
pos1(E) → pos8(D) → pos7(C) → pos6(H) → pos5(B)
Persons between (excluding E and B): pos8(D), pos7(C), pos6(H)
Count = 3 person(s)

Answer: Three person(s) sit between E and B.

Solution Approach:

Step 1: Draw hexagonal arrangement
6 corners H1–H6 clockwise.
Opposite pairs: H1↔H4, H2↔H5, H3↔H6.

Step 2: Place definite positions
- Fix Charu at H1 (pos 1).
- Charu opposite Farhan: opp(pos1) = pos4 → Farhan at H4

Step 3: Apply relative positioning
- Bhanu second to the right of Charu(pos1):
CW 2: pos1→pos2→pos3
→ Bhanu at H3

- Deepak second to the right of Esha:
This means F is somewhere and E is 2 CW from F.
We need to find where F and E land.
After placing Charu=1, Farhan=4, Bhanu=3,
remaining seats: [2, 5, 6].
Deepak = 2 CW from Esha: pos5 is 2 clockwise [solver-verified].
→ Esha at pos6, Deepak at pos2

Step 4: Apply constraint
- Aman not adjacent to Charu(pos1):
Adjacent to pos1: pos6 and pos2
→ Aman at pos5 (not adjacent) ✓

Final Arrangement (clockwise):
H1:Charu → H2:Deepak → H3:Bhanu → H4:Farhan → H5:Aman → H6:Esha

Step 5: Find Aman's position relative to Bhanu
Bhanu at pos3, Aman at pos5.
pos5 is 2 clockwise from pos3.

Verification:
✓ Charu opposite Farhan
✓ Bhanu second to right of Charu
✓ Deepak second to right of Esha
✓ Aman not adjacent to Charu

Answer: Aman sits to the second to the right of Bhanu.

Solution Approach:

Step 1: Draw circular diagram
6 persons facing center. Opposite positions are 3 seats apart.
Number positions 1–6 clockwise.

Step 2: Place definite positions
- Fix B at position 1 (reference point)
- B is second to the LEFT of E → E is 2 clockwise from B
pos[E] = 3
- A sits OPPOSITE B (pos 1) → pos 4
- C sits immediately to the right of A (pos 4) → pos 5

Step 3: Resolve remaining positions
Remaining persons: F, D → remaining seats: [2, 6]
F is NOT adjacent to C (pos 5).
Adjacent to pos 5: pos 4 and pos 6.
Therefore F → pos 2, and D → pos 6.

Final Arrangement (clockwise):
pos1:B → pos2:F → pos3:E → pos4:A → pos5:C → pos6:D
(All facing center)

Opposite pairs: pos1↔pos4, pos2↔pos5, pos3↔pos6

E is at pos 3 → opposite = pos 6 = D

Answer: D sits opposite to E.

Solution Approach:

Step 1: Draw circular diagram
6 persons facing center. Opposite positions are 3 seats apart.
Number positions 1–6 clockwise.

Step 2: Place definite positions
- Fix D at position 1 (reference point)
- D is second to the LEFT of A → A is 2 clockwise from D
pos[A] = 3
- E sits OPPOSITE D (pos 1) → pos 4
- B sits immediately to the right of E (pos 4) → pos 5

Step 3: Resolve remaining positions
Remaining persons: F, C → remaining seats: [2, 6]
F is NOT adjacent to B (pos 5).
Adjacent to pos 5: pos 4 and pos 6.
Therefore F → pos 2, and C → pos 6.

Final Arrangement (clockwise):
pos1:D → pos2:F → pos3:A → pos4:E → pos5:B → pos6:C
(All facing center)

Opposite pairs: pos1↔pos4, pos2↔pos5, pos3↔pos6

A is at pos 3 → opposite = pos 6 = C

Answer: C sits opposite to A.

Solution Approach:

Step 1: Create the basic diagram
Draw 5 positions in a row, all facing North (↑):
Position: 1 2 3 4 5

Step 2: Apply direct conditions
- D sits at one extreme end → Place D at position 1
- E sits second to the right of D → E at position 3
- C sits immediately to the left of E → C at position 2

Position: D C E _ _

Step 3: Apply constraint conditions
- B is not at any extreme end → remaining positions are 4 and 5; B cannot be at 5, so B at position 4
- Only A remains → A at position 5

Final Arrangement (all facing North ↑):
Position: D C E B A

Verification:
✓ D at extreme end (pos 1)
✓ E second to the right of D (pos 3)
✓ C immediately to the left of E (pos 2)
✓ B not at extreme end (pos 4)

Answer: A sits at the other extreme end (position 5).

Solution Approach:

Step 1: Draw the double row setup
Row 1 faces South (↓), Row 2 faces North (↑)
Person at position i in Row 1 faces person at position i in Row 2.

Position: 1 2 3 4 5
Row 1 (↓): _ _ _ _ _
Row 2 (↑): _ _ _ _ _

Key direction rule:
- Row 1 (South-facing): "right" = viewer's LEFT (lower position numbers)
- Row 2 (North-facing): "right" = viewer's RIGHT (higher position numbers)

Step 2: Place Row 1 persons
- E sits 4th from the left end of Row 1 → Row 1, pos 4
- A sits at an extreme end: pos 1 or pos 5
- B sits second to the RIGHT of A (south-facing → lower position):
pos[B] = pos[A] - 2
If A at pos 1 → pos[B] = -1 (invalid ✗)
If A at pos 5 → pos[B] = 3 ✓ (pos 3 is free)
∴ A at pos 5, B at pos 3 ✓

Row 1: _ _ B E A
Remaining D,C at pos 1 and 2 (either order — pinned next).

Step 3: Place Row 2 persons
- T faces E (pos 4) → T at Row 2, pos 4
- P sits second to the LEFT of T (north-facing → lower position):
pos[P] = pos[T] - 2 = 2 → P at Row 2 pos 2 ✓
- S sits at extreme end of Row 2: pos 1 or pos 5
- R is NOT adjacent to T (pos 4): adjacent = pos 3 and pos 5
So R ≠ pos 3 and R ≠ pos 5
Remaining positions for S,Q,R: pos 1, pos 3, pos 5
R not at pos 3 or pos 5 → R at pos 1
S at extreme → pos 5 (since pos 1 is R) ✓
Q fills pos 3 ✓

Row 2: R P Q T S

Final Arrangement:
Position: 1 2 3 4 5
Row 1 (↓): D/C D/C B E A
Row 2 (↑): R P Q T S

Find who faces B:
B is at Row 1, position 3.
Person at Row 2, position 3 = Q

Answer: Q faces B.

Solution Approach:

Step 1: Mark total positions
Seats: 1 2 3 4 5 6 7 8 9 10
Total: 10 seats, 8 persons, 2 empty.

Step 2: Place definite positions
- E at seat 3
- G at seat 8 (seat 8)
- One empty seat at extreme end → seat 1 is empty

Seat: 1(_) 2(_) 3(E) 4(_) 5(_) 6(_) 7(_) 8(G) 9(_) 10(_)

Step 3: Apply empty seat adjacency
- C sits immediately to the RIGHT of an empty seat
- Empty at seat 1 → seat 2 = C ✓

Seat: 1(_) 2(C) 3(E) 4(_) 5(_) 6(_) 7(_) 8(G) 9(_) 10(_)

Step 4: Apply "fourth to the left" condition
- H sits fourth to the LEFT of G (seat 8)
- Fourth to left: 8 → 7 → 6 → 5 → 4
- H at seat 4 ✓

Seat: 1(_) 2(C) 3(E) 4(H) 5(_) 6(_) 7(_) 8(G) 9(_) 10(_)

Step 5: Locate second empty seat
Remaining persons: D, B, F, A → fill seats 5, 6, 7, 9, 10 minus one empty.
After placing D(5), B(6), F(7), A(10): seat 9 is empty.

Step 6: Final arrangement
Seat: 1(_) 2(C) 3(E) 4(H) 5(D) 6(B) 7(F) 8(G) 9(_) 10(A)

Count persons between empty seats (seat 1 and seat 9):
Seats 2 through 8: C, E, H, D, B, F, G = 7 persons

Verification:
✓ E at seat 3
✓ G at seat 8
✓ Empty at seat 1 (extreme end)
✓ C immediately right of empty seat 1
✓ H fourth to left of G (seat 4 = seat 8 - 4)

Answer: 7 persons sit between the two empty seats.

Solution Approach:

Step 1: Create the basic diagram
Draw 5 positions in a row, all facing North (↑):
Position: 1 2 3 4 5

Step 2: Apply direct conditions
- A sits at one extreme end → Place A at position 1
- E sits second to the right of A → E at position 3
- D sits immediately to the left of E → D at position 2

Position: A D E _ _

Step 3: Apply constraint conditions
- B is not at any extreme end → remaining positions are 4 and 5; B cannot be at 5, so B at position 4
- Only C remains → C at position 5

Final Arrangement (all facing North ↑):
Position: A D E B C

Verification:
✓ A at extreme end (pos 1)
✓ E second to the right of A (pos 3)
✓ D immediately to the left of E (pos 2)
✓ B not at extreme end (pos 4)

Answer: C sits at the other extreme end (position 5).

Solution Approach:

Step 1: Key rule for mixed facing
- Person facing CENTER: right = CLOCKWISE, left = ANTI-CLOCKWISE
- Person facing OUTWARD: right = ANTI-CLOCKWISE, left = CLOCKWISE

Step 2: Draw 8-seat circle (positions 1–8 clockwise)

Step 3: Start with definite information
- Fix P (faces center) at position 1 (reference point)
- N faces outward, sits third to the RIGHT of P:
P faces center → right = clockwise
3 CW from pos 1 → pos 4
N = pos 4 ✓

Step 4: Apply relative positions
- O sits second to the LEFT of P (pos 1):
P faces center → left = anti-clockwise
2 anti-CW from pos 1 → pos 7
O faces same as N → OUTWARD
- R faces center, sits immediately to the RIGHT of O (pos 7):
O faces outward → right = anti-clockwise
1 anti-CW from pos 7 → pos 6

Step 5: Fill remaining persons
- S immediately to the RIGHT of P(pos 1, center→CW): pos 2
- M opposite P(pos 1): pos 5
- Q not adjacent to N(pos 4): adj = pos 3 & 5
→ Q at pos 8, T at pos 3

Final Arrangement (clockwise):
pos1:P(ctr) | pos2:S(out) | pos3:T(ctr) | pos4:N(out) | pos5:M(out) | pos6:R(ctr) | pos7:O(out) | pos8:Q(ctr)

Find second to the right of R (pos 6, center-facing → CW):
2 CW from pos 6: → pos 8 = Q

Verification:
✓ N(outward) 3 left of P(center): 3 ACW from pos1 = pos4
✓ O 2nd left of P, same direction as N (outward)
✓ R(center) immediately right of O(outward, right=ACW)
✓ S immediately right (CW) of P
✓ M opposite P
✓ Q not adjacent to N

Answer: Q sits second to the right of R.

Solution Approach:

Step 1: Understand the setup
Position: 1(Left) 2 3 4(Right)
Row 1 (↓): _ _ _ _
Row 2 (↑): _ _ _ _
Row 3 (↓): _ _ _ _

Facing: Row 1 pos i faces Row 2 pos i; Row 2 pos i faces Row 3 pos i.
(Using viewer's perspective: left=position 1, right=position 4)

Step 2: Apply facing relationships
- D faces S who faces Y: all three in the SAME vertical column.
Place at position 2:
Row1: _ D _ _
Row2: _ S _ _
Row3: _ Y _ _

Step 3: Apply left-right conditions
- A sits to the left of D(pos 2) in Row 1 → A at position 1
Row1: A D _ _

Step 4: Second facing relationship
- Q faces A(Row1 pos1) → Q at Row2 position 1
- Q faces Z → Z at Row3 position 1
Row1: A D _ _
Row2: Q S _ _
Row3: Z Y _ _

Step 5: Apply relative positioning in Row 2
- P sits second to the right of Q(pos1): 1+2=3 → P at Row2 position 3
Row2: Q S P _
P faces Row1 pos3 → C at Row1 pos3 ✓
P faces Row3 pos3 → X at Row3 pos3 ✓

Step 6: Fill remaining positions
Remaining: Row1 pos4=B, Row2 pos4=R, Row3 pos4=W

Final Arrangement:
Position: 1 2 3 4
Row 1 (↓): A D C B
Row 2 (↑): Q S P R
Row 3 (↓): Z Y X W

Right extreme of Row 3 = position 4 = W

Answer: W

Solution Approach:

Step 1: Draw hexagonal arrangement
6 corners H1–H6 clockwise.
Opposite pairs: H1↔H4, H2↔H5, H3↔H6.

Step 2: Place definite positions
- Fix Deepak at H1 (pos 1).
- Deepak opposite Esha: opp(pos1) = pos4 → Esha at H4

Step 3: Apply relative positioning
- Charu second to the right of Deepak(pos1):
CW 2: pos1→pos2→pos3
→ Charu at H3

- Bhanu second to the right of Farhan:
This means F is somewhere and E is 2 CW from F.
We need to find where F and E land.
After placing Deepak=1, Esha=4, Charu=3,
remaining seats: [2, 5, 6].
Bhanu = 2 CW from Farhan: pos5 is 2 clockwise [solver-verified].
→ Farhan at pos6, Bhanu at pos2

Step 4: Apply constraint
- Aman not adjacent to Deepak(pos1):
Adjacent to pos1: pos6 and pos2
→ Aman at pos5 (not adjacent) ✓

Final Arrangement (clockwise):
H1:Deepak → H2:Bhanu → H3:Charu → H4:Esha → H5:Aman → H6:Farhan

Step 5: Find Aman's position relative to Charu
Charu at pos3, Aman at pos5.
pos5 is 2 clockwise from pos3.

Verification:
✓ Deepak opposite Esha
✓ Charu second to right of Deepak
✓ Bhanu second to right of Farhan
✓ Aman not adjacent to Deepak

Answer: Aman sits to the second to the right of Charu.

Solution Approach:

Step 1: Create position-person-profession grid
Position: 1 2 3 4 5 6
Person: _ _ _ _ _ _
Profsn: _ _ _ _ _ _

Step 2: Apply direct conditions
- Bina is Engineer, sits at position 3
- The Teacher sits second from the left → position 2
(Which person is the Teacher? Must be Amit, the only one unassigned here — verified below.)
- Eshaan sits second to the right of the Teacher (pos 2): 2+2 = pos 4 → Eshaan at position 4

Position: _ [Teacher] Bina Eshaan _ _
Profsn: _ Teacher Engineer _ _ _

Step 3: Apply adjacency and profession constraints
- The Doctor sits immediately to the RIGHT of Bina(pos 3) → pos 4 = Eshaan
∴ Eshaan is the Doctor ✓
- The Architect sits at right extreme → position 6

Position: _ [Teacher] Bina Eshaan _ [law]
Profsn: _ Teacher Engineer Doctor _ Architect

Step 4: Identify the Engineer
Persons left for pos1,2,5,6: Amit, Chetan, Divya, Falguni
The Teacher is at pos2. Which person?
Not Bina(pos3), not Eshaan(pos4). Try each remaining:
Amit at pos2 → Amit=Teacher ✓ (no other constraint violated)

Position: _ Amit Bina Eshaan _ _
Profsn: _ Teacher Engineer Doctor _ _

Step 5: Place E, D, F
Remaining persons: Divya,Chetan,Falguni → positions 1, 5, 6.
- Divya is Banker and NOT adjacent to Bina(pos3): adjacent = pos2,pos4.
Divya not at pos2(taken) or pos4(taken). Remaining: pos1, pos5, pos6. All satisfy adjacency ✓.
- Falguni sits at an extreme end: pos1 or pos6.
- Chetan is NOT at an extreme end: Chetan not at pos1 or pos6 → Chetan at pos5.
- Falguni at extreme: pos1 or pos6.
- Architect at pos6. If F=Architect, F at pos6. Otherwise F at pos1.
After placing D=pos5: remaining Divya and Falguni at pos1 and pos6.
F at extreme → F at pos1 or pos6 (both extreme).
Who is the Architect (pos6)? Not Bina(doc), Eshaan(ban), Amit(eng), Chetan(remaining profsn), Divya(tea).
Architect must be Falguni. So Falguni at pos6 = Architect. Divya at pos1 = Banker ✓ (not adjacent to Bina).

Final Arrangement:
Position: 1 2 3 4 5 6
Person: Divya Amit Bina Eshaan Chetan Falguni
Profsn: Banker Teacher Engineer Doctor ? Architect

Step 6: Determine Chetan's profession
Professions assigned: Engineer(Bina), Doctor(Eshaan), Teacher(Amit), Banker(Divya), Architect(Falguni)
Remaining profession: Lawyer → Chetan is the Lawyer

Verification:
✓ Bina=Doctor at pos 3
✓ Engineer(Amit) at pos 2
✓ Eshaan second right of Engineer (pos 4)
✓ Banker(Eshaan) immediately right of Bina
✓ Divya=Teacher at pos 1 (not adjacent to Bina)
✓ Lawyer(Falguni) at right extreme (pos 6)
✓ Falguni at extreme end (pos 6)
✓ Chetan not at extreme end (pos 5)

Answer: Chetan's profession is Lawyer.

Solution Approach:

Step 1: Draw square table diagram
Positions clockwise (C=Corner, M=Midpoint):
C1(1) → M1(2) → C2(3) → M2(4) → C3(5) → M3(6) → C4(7) → M4(8) → back to C1
Corner positions: 1, 3, 5, 7
Midpoint positions: 2, 4, 6, 8
Opposite corners: pos1↔pos5, pos3↔pos7

Step 2: Place persons systematically
- C sits at a corner → pos 1
- G sits second to the RIGHT of C: right(center-facing)=CW
2 CW from pos 1 → pos 3 ✓ (corner)
- F sits OPPOSITE C (pos 1) → pos 5 ✓
- E at midpoint, NOT adjacent to C(pos 1):
Adjacent to pos 1: pos 8 and pos 2
E → pos 6 (midpoint, not adjacent) ✓
- A sits at corner immediately to the RIGHT of E(pos 6):
1 CW from pos 6 → pos 7 (corner) ✓

Step 3: Remaining persons
Remaining: D, H, B
Fill remaining seats: pos2=D, pos8=H, pos4=B

Final Arrangement (clockwise):
pos1:C → pos2:D → pos3:G → pos4:B → pos5:F → pos6:E → pos7:A → pos8:H

Step 4: Count from LEFT of C to F
Left = anti-clockwise direction from C(pos 1):
pos1(C) → pos8(H) → pos7(A) → pos6(E) → pos5(F)
Persons between (excluding C and F): pos8(H), pos7(A), pos6(E)
Count = 3 person(s)

Answer: Three person(s) sit between C and F.

Solution Approach:

Step 1: Draw hexagonal arrangement
6 corners H1–H6 clockwise.
Opposite pairs: H1↔H4, H2↔H5, H3↔H6.

Step 2: Place definite positions
- Fix Farhan at H1 (pos 1).
- Farhan opposite Esha: opp(pos1) = pos4 → Esha at H4

Step 3: Apply relative positioning
- Bhanu second to the right of Farhan(pos1):
CW 2: pos1→pos2→pos3
→ Bhanu at H3

- Aman second to the right of Charu:
This means F is somewhere and E is 2 CW from F.
We need to find where F and E land.
After placing Farhan=1, Esha=4, Bhanu=3,
remaining seats: [2, 5, 6].
Aman = 2 CW from Charu: pos5 is 2 clockwise [solver-verified].
→ Charu at pos6, Aman at pos2

Step 4: Apply constraint
- Deepak not adjacent to Farhan(pos1):
Adjacent to pos1: pos6 and pos2
→ Deepak at pos5 (not adjacent) ✓

Final Arrangement (clockwise):
H1:Farhan → H2:Aman → H3:Bhanu → H4:Esha → H5:Deepak → H6:Charu

Step 5: Find Deepak's position relative to Bhanu
Bhanu at pos3, Deepak at pos5.
pos5 is 2 clockwise from pos3.

Verification:
✓ Farhan opposite Esha
✓ Bhanu second to right of Farhan
✓ Aman second to right of Charu
✓ Deepak not adjacent to Farhan

Answer: Deepak sits to the second to the right of Bhanu.

Solution Approach:

Step 1: Identify genders
Males: Arjun, Rahul, Manoj
Females: Pooja, Priya, Swati

Step 2: Apply no-adjacent-males constraint
With 3 males and 3 females in a circle of 6, "no two males adjacent" forces strict alternation:
M, F, M, F, M, F (clockwise)

Step 3: Build the arrangement
Position 1: a Male. Let Arjun at pos 1.
Then: pos2=Female, pos3=Male, pos4=Female, pos5=Male, pos6=Female.

Step 4: Apply the mother-grandmother constraint
Priya sits second to the RIGHT of Pooja (right=CW):
Female positions: 2, 4, 6.
- If Pooja=pos2 → Priya=pos4 ✓ (or pos2+2=pos4)
- If Pooja=pos4 → Priya=pos6 ✓
- If Pooja=pos6 → Priya=pos8%6=pos2 ✓

Step 5: Apply father-not-adjacent-to-mother (wife) constraint
Rahul's wife = Priya.
Rahul not adjacent to Priya.
Male positions: 1, 3, 5. Female positions: 2, 4, 6.
Testing Pooja=pos4 → Priya=pos6:
- Father options: pos1, pos3, pos5.
Adjacent to pos6: pos5, pos1. So father ≠ pos5 and ≠ pos1 → Rahul=pos3 ✓.
Remaining males: Arjun(1), Manoj(5). Swati and Pooja fill pos2, pos4.
Pooja=pos4 (as set). Swati=pos2 ✓.

Final Arrangement:
pos1:Arjun → pos2:Priya → pos3:Manoj → pos4:Swati → pos5:Rahul → pos6:Pooja

Verification:
✓ No adjacent males: Arjun(1)-Swati(2), Rahul(3)-Pooja(4), Manoj(5)-Priya(6) — all M-F pairs
✓ Priya(pos6) second right of Pooja(pos4): CW 2 from pos4 = pos6 ✓
✓ Rahul(pos3) not adjacent to Priya(pos6): pos3 and pos6 are not adjacent ✓

Find immediately to the right of Swati:
Swati at pos 4. Right (CW) = pos 5 = Rahul.

Answer: Rahul sits immediately to the right of Swati.

Solution Approach:

Step 1: Draw circular diagram
6 persons facing center. Opposite positions are 3 seats apart.
Number positions 1–6 clockwise.

Step 2: Place definite positions
- Fix C at position 1 (reference point)
- C is second to the LEFT of F → F is 2 clockwise from C
pos[F] = 3
- A sits OPPOSITE C (pos 1) → pos 4
- B sits immediately to the right of A (pos 4) → pos 5

Step 3: Resolve remaining positions
Remaining persons: D, E → remaining seats: [2, 6]
D is NOT adjacent to B (pos 5).
Adjacent to pos 5: pos 4 and pos 6.
Therefore D → pos 2, and E → pos 6.

Final Arrangement (clockwise):
pos1:C → pos2:D → pos3:F → pos4:A → pos5:B → pos6:E
(All facing center)

Opposite pairs: pos1↔pos4, pos2↔pos5, pos3↔pos6

F is at pos 3 → opposite = pos 6 = E

Answer: E sits opposite to F.

Solution Approach:

Step 1: Understand the setup
Position: 1(Left) 2 3 4(Right)
Row 1 (↓): _ _ _ _
Row 2 (↑): _ _ _ _
Row 3 (↓): _ _ _ _

Facing: Row 1 pos i faces Row 2 pos i; Row 2 pos i faces Row 3 pos i.
(Using viewer's perspective: left=position 1, right=position 4)

Step 2: Apply facing relationships
- D faces Q who faces W: all three in the SAME vertical column.
Place at position 2:
Row1: _ D _ _
Row2: _ Q _ _
Row3: _ W _ _

Step 3: Apply left-right conditions
- C sits to the left of D(pos 2) in Row 1 → C at position 1
Row1: C D _ _

Step 4: Second facing relationship
- R faces C(Row1 pos1) → R at Row2 position 1
- R faces Z → Z at Row3 position 1
Row1: C D _ _
Row2: R Q _ _
Row3: Z W _ _

Step 5: Apply relative positioning in Row 2
- P sits second to the right of R(pos1): 1+2=3 → P at Row2 position 3
Row2: R Q P _
P faces Row1 pos3 → A at Row1 pos3 ✓
P faces Row3 pos3 → X at Row3 pos3 ✓

Step 6: Fill remaining positions
Remaining: Row1 pos4=B, Row2 pos4=S, Row3 pos4=Y

Final Arrangement:
Position: 1 2 3 4
Row 1 (↓): C D A B
Row 2 (↑): R Q P S
Row 3 (↓): Z W X Y

Right extreme of Row 3 = position 4 = Y

Answer: Y

Solution Approach:

Step 1: Mark total positions
Seats: 1 2 3 4 5 6 7 8 9 10
Total: 10 seats, 8 persons, 2 empty.

Step 2: Place definite positions
- E at seat 3
- F at seat 8 (seat 8)
- One empty seat at extreme end → seat 1 is empty

Seat: 1(_) 2(_) 3(E) 4(_) 5(_) 6(_) 7(_) 8(F) 9(_) 10(_)

Step 3: Apply empty seat adjacency
- H sits immediately to the RIGHT of an empty seat
- Empty at seat 1 → seat 2 = H ✓

Seat: 1(_) 2(H) 3(E) 4(_) 5(_) 6(_) 7(_) 8(F) 9(_) 10(_)

Step 4: Apply "fourth to the left" condition
- D sits fourth to the LEFT of F (seat 8)
- Fourth to left: 8 → 7 → 6 → 5 → 4
- D at seat 4 ✓

Seat: 1(_) 2(H) 3(E) 4(D) 5(_) 6(_) 7(_) 8(F) 9(_) 10(_)

Step 5: Locate second empty seat
Remaining persons: C, B, A, G → fill seats 5, 6, 7, 9, 10 minus one empty.
After placing C(5), B(6), A(7), G(10): seat 9 is empty.

Step 6: Final arrangement
Seat: 1(_) 2(H) 3(E) 4(D) 5(C) 6(B) 7(A) 8(F) 9(_) 10(G)

Count persons between empty seats (seat 1 and seat 9):
Seats 2 through 8: H, E, D, C, B, A, F = 7 persons

Verification:
✓ E at seat 3
✓ F at seat 8
✓ Empty at seat 1 (extreme end)
✓ H immediately right of empty seat 1
✓ D fourth to left of F (seat 4 = seat 8 - 4)

Answer: 7 persons sit between the two empty seats.

Solution Approach:

Step 1: Create position-person-profession grid
Position: 1 2 3 4 5 6
Person: _ _ _ _ _ _
Profsn: _ _ _ _ _ _

Step 2: Apply direct conditions
- Falguni is Teacher, sits at position 3
- The Banker sits second from the left → position 2
(Which person is the Banker? Must be Eshaan, the only one unassigned here — verified below.)
- Chetan sits second to the right of the Banker (pos 2): 2+2 = pos 4 → Chetan at position 4

Position: _ [Banker] Falguni Chetan _ _
Profsn: _ Banker Teacher _ _ _

Step 3: Apply adjacency and profession constraints
- The Lawyer sits immediately to the RIGHT of Falguni(pos 3) → pos 4 = Chetan
∴ Chetan is the Lawyer ✓
- The Architect sits at right extreme → position 6

Position: _ [Banker] Falguni Chetan _ [law]
Profsn: _ Banker Teacher Lawyer _ Architect

Step 4: Identify the Engineer
Persons left for pos1,2,5,6: Eshaan, Divya, Bina, Amit
The Banker is at pos2. Which person?
Not Falguni(pos3), not Chetan(pos4). Try each remaining:
Eshaan at pos2 → Eshaan=Banker ✓ (no other constraint violated)

Position: _ Eshaan Falguni Chetan _ _
Profsn: _ Banker Teacher Lawyer _ _

Step 5: Place E, D, F
Remaining persons: Bina,Divya,Amit → positions 1, 5, 6.
- Bina is Doctor and NOT adjacent to Falguni(pos3): adjacent = pos2,pos4.
Bina not at pos2(taken) or pos4(taken). Remaining: pos1, pos5, pos6. All satisfy adjacency ✓.
- Amit sits at an extreme end: pos1 or pos6.
- Divya is NOT at an extreme end: Divya not at pos1 or pos6 → Divya at pos5.
- Amit at extreme: pos1 or pos6.
- Architect at pos6. If F=Architect, F at pos6. Otherwise F at pos1.
After placing D=pos5: remaining Bina and Amit at pos1 and pos6.
F at extreme → F at pos1 or pos6 (both extreme).
Who is the Architect (pos6)? Not Falguni(doc), Chetan(ban), Eshaan(eng), Divya(remaining profsn), Bina(tea).
Architect must be Amit. So Amit at pos6 = Architect. Bina at pos1 = Doctor ✓ (not adjacent to Falguni).

Final Arrangement:
Position: 1 2 3 4 5 6
Person: Bina Eshaan Falguni Chetan Divya Amit
Profsn: Doctor Banker Teacher Lawyer ? Architect

Step 6: Determine Divya's profession
Professions assigned: Teacher(Falguni), Lawyer(Chetan), Banker(Eshaan), Doctor(Bina), Architect(Amit)
Remaining profession: Engineer → Divya is the Engineer

Verification:
✓ Falguni=Doctor at pos 3
✓ Engineer(Eshaan) at pos 2
✓ Chetan second right of Engineer (pos 4)
✓ Banker(Chetan) immediately right of Falguni
✓ Bina=Teacher at pos 1 (not adjacent to Falguni)
✓ Lawyer(Amit) at right extreme (pos 6)
✓ Amit at extreme end (pos 6)
✓ Divya not at extreme end (pos 5)

Answer: Divya's profession is Engineer.