Seating Arrangement - Beginner Level: position puzzles BEGINNER

Solution Approach:

Step 1: Draw concentric circles
Inner circle: 4 positions I1(12 o'clock), I2(3), I3(6), I4(9) — all occupied.
Outer circle: 6 positions O1–O6 clockwise — 4 occupied, 2 empty.
Facing alignment: I1↔O1, I2↔O2, I3↔O4, I4↔O5 (O3 and O6 are empty).

Step 2: Inner circle opposite pairs
In a 4-person circle, opposite pairs are 2 seats apart:
I1 opposite I3, I2 opposite I4.

Step 3: Place inner circle persons
- B sits immediately to the right of D (inner circle, facing center: right=CW)
→ D and B are adjacent. Possible: D=I1, B=I2 or D=I2, B=I3, etc.
- A sits opposite to B:
If B=I2, then A=I4. Then D=I1 (left of I2), C=I3 (remaining).
All constraints consistent ✓.

Inner: I1=D, I2=B, I3=C, I4=A

Step 4: Place outer circle persons
- P faces D(I1) → P at O1 ✓
- Outer occupied seats: O1, O2, O4, O5. Empty: O3, O6.
- R second to right of Q (outer, facing center: right=CW, step 2):
Remaining outer persons: R,Q,S at O2, O4, O5.
R=O2 → Q=O4, S=O5 ✓
R=O4 → Q=O6(empty) ✗
R=O5 → Q=O1=P ✗
∴ Q=O2, R=O4, S=O5 ✓
- S(O5) immediately to the LEFT of an empty:
Left(CW) of O5 = O4(R) — NOT empty.
RIGHT(CW) of O5 = O6(empty). So O5 is immediately to the LEFT of O6(empty) ✓.

Step 5: Answer the question
B is at I2. Opposite of I2 = I4 = A.

Final Arrangements:
Inner (CW): I1=D, I2=B, I3=C, I4=A
Outer (CW): O1=P, O2=Q, O3=empty, O4=R, O5=S, O6=empty

Verification:
✓ P faces D (I1↔O1)
✓ B immediately right of D (I2 is CW from I1)
✓ A opposite B (I4 opposite I2)
✓ R second right of Q (O4 = O2 + 2 CW)
✓ S(O5) immediately left of empty O6

Answer: A sits opposite to B.

Solution Approach:

Step 1: Mark total positions
Seats: 1 2 3 4 5 6 7 8 9 10
Total: 10 seats, 8 persons, 2 empty.

Step 2: Place definite positions
- A at seat 3
- F at seat 8 (seat 8)
- One empty seat at extreme end → seat 1 is empty

Seat: 1(_) 2(_) 3(A) 4(_) 5(_) 6(_) 7(_) 8(F) 9(_) 10(_)

Step 3: Apply empty seat adjacency
- D sits immediately to the RIGHT of an empty seat
- Empty at seat 1 → seat 2 = D ✓

Seat: 1(_) 2(D) 3(A) 4(_) 5(_) 6(_) 7(_) 8(F) 9(_) 10(_)

Step 4: Apply "fourth to the left" condition
- E sits fourth to the LEFT of F (seat 8)
- Fourth to left: 8 → 7 → 6 → 5 → 4
- E at seat 4 ✓

Seat: 1(_) 2(D) 3(A) 4(E) 5(_) 6(_) 7(_) 8(F) 9(_) 10(_)

Step 5: Locate second empty seat
Remaining persons: H, C, G, B → fill seats 5, 6, 7, 9, 10 minus one empty.
After placing H(5), C(6), G(7), B(10): seat 9 is empty.

Step 6: Final arrangement
Seat: 1(_) 2(D) 3(A) 4(E) 5(H) 6(C) 7(G) 8(F) 9(_) 10(B)

Count persons between empty seats (seat 1 and seat 9):
Seats 2 through 8: D, A, E, H, C, G, F = 7 persons

Verification:
✓ A at seat 3
✓ F at seat 8
✓ Empty at seat 1 (extreme end)
✓ D immediately right of empty seat 1
✓ E fourth to left of F (seat 4 = seat 8 - 4)

Answer: 7 persons sit between the two empty seats.

Solution Approach:

Step 1: Draw the double row setup
Row 1 faces South (↓), Row 2 faces North (↑)
Person at position i in Row 1 faces person at position i in Row 2.

Position: 1 2 3 4 5
Row 1 (↓): _ _ _ _ _
Row 2 (↑): _ _ _ _ _

Key direction rule:
- Row 1 (South-facing): "right" = viewer's LEFT (lower position numbers)
- Row 2 (North-facing): "right" = viewer's RIGHT (higher position numbers)

Step 2: Place Row 1 persons
- C sits 4th from the left end of Row 1 → Row 1, pos 4
- E sits at an extreme end: pos 1 or pos 5
- D sits second to the RIGHT of E (south-facing → lower position):
pos[D] = pos[E] - 2
If E at pos 1 → pos[D] = -1 (invalid ✗)
If E at pos 5 → pos[D] = 3 ✓ (pos 3 is free)
∴ E at pos 5, D at pos 3 ✓

Row 1: _ _ D C E
Remaining B,A at pos 1 and 2 (either order — pinned next).

Step 3: Place Row 2 persons
- T faces C (pos 4) → T at Row 2, pos 4
- Q sits second to the LEFT of T (north-facing → lower position):
pos[Q] = pos[T] - 2 = 2 → Q at Row 2 pos 2 ✓
- P sits at extreme end of Row 2: pos 1 or pos 5
- R is NOT adjacent to T (pos 4): adjacent = pos 3 and pos 5
So R ≠ pos 3 and R ≠ pos 5
Remaining positions for P,S,R: pos 1, pos 3, pos 5
R not at pos 3 or pos 5 → R at pos 1
P at extreme → pos 5 (since pos 1 is R) ✓
S fills pos 3 ✓

Row 2: R Q S T P

Final Arrangement:
Position: 1 2 3 4 5
Row 1 (↓): B/A B/A D C E
Row 2 (↑): R Q S T P

Find who faces D:
D is at Row 1, position 3.
Person at Row 2, position 3 = S

Answer: S faces D.

Solution Approach:

Step 1: Draw the double row setup
Row 1 faces South (↓), Row 2 faces North (↑)
Person at position i in Row 1 faces person at position i in Row 2.

Position: 1 2 3 4 5
Row 1 (↓): _ _ _ _ _
Row 2 (↑): _ _ _ _ _

Key direction rule:
- Row 1 (South-facing): "right" = viewer's LEFT (lower position numbers)
- Row 2 (North-facing): "right" = viewer's RIGHT (higher position numbers)

Step 2: Place Row 1 persons
- E sits 4th from the left end of Row 1 → Row 1, pos 4
- B sits at an extreme end: pos 1 or pos 5
- C sits second to the RIGHT of B (south-facing → lower position):
pos[C] = pos[B] - 2
If B at pos 1 → pos[C] = -1 (invalid ✗)
If B at pos 5 → pos[C] = 3 ✓ (pos 3 is free)
∴ B at pos 5, C at pos 3 ✓

Row 1: _ _ C E B
Remaining A,D at pos 1 and 2 (either order — pinned next).

Step 3: Place Row 2 persons
- S faces E (pos 4) → S at Row 2, pos 4
- P sits second to the LEFT of S (north-facing → lower position):
pos[P] = pos[S] - 2 = 2 → P at Row 2 pos 2 ✓
- T sits at extreme end of Row 2: pos 1 or pos 5
- R is NOT adjacent to S (pos 4): adjacent = pos 3 and pos 5
So R ≠ pos 3 and R ≠ pos 5
Remaining positions for T,Q,R: pos 1, pos 3, pos 5
R not at pos 3 or pos 5 → R at pos 1
T at extreme → pos 5 (since pos 1 is R) ✓
Q fills pos 3 ✓

Row 2: R P Q S T

Final Arrangement:
Position: 1 2 3 4 5
Row 1 (↓): A/D A/D C E B
Row 2 (↑): R P Q S T

Find who faces C:
C is at Row 1, position 3.
Person at Row 2, position 3 = Q

Answer: Q faces C.

Solution Approach:

Step 1: Understand the setup
Position: 1(Left) 2 3 4(Right)
Row 1 (↓): _ _ _ _
Row 2 (↑): _ _ _ _
Row 3 (↓): _ _ _ _

Facing: Row 1 pos i faces Row 2 pos i; Row 2 pos i faces Row 3 pos i.
(Using viewer's perspective: left=position 1, right=position 4)

Step 2: Apply facing relationships
- D faces Q who faces Z: all three in the SAME vertical column.
Place at position 2:
Row1: _ D _ _
Row2: _ Q _ _
Row3: _ Z _ _

Step 3: Apply left-right conditions
- A sits to the left of D(pos 2) in Row 1 → A at position 1
Row1: A D _ _

Step 4: Second facing relationship
- R faces A(Row1 pos1) → R at Row2 position 1
- R faces W → W at Row3 position 1
Row1: A D _ _
Row2: R Q _ _
Row3: W Z _ _

Step 5: Apply relative positioning in Row 2
- P sits second to the right of R(pos1): 1+2=3 → P at Row2 position 3
Row2: R Q P _
P faces Row1 pos3 → B at Row1 pos3 ✓
P faces Row3 pos3 → X at Row3 pos3 ✓

Step 6: Fill remaining positions
Remaining: Row1 pos4=C, Row2 pos4=S, Row3 pos4=Y

Final Arrangement:
Position: 1 2 3 4
Row 1 (↓): A D B C
Row 2 (↑): R Q P S
Row 3 (↓): W Z X Y

Right extreme of Row 3 = position 4 = Y

Answer: Y

Solution Approach:

Step 1: Apply the fixed condition
- V sits second from the left → V at position 2 (fixed)

Step 2: Enumerate all valid arrangements
Testing all 120 possible arrangements with V at pos 2, applying all conditions.
7 valid arrangement(s) found.

Valid arrangement(s):
• X V W Y Z
• X V W Z Y
• W V Z Y X
• Y V X W Z
• Z V X W Y
• Z V W X Y
(shown up to 6)

Step 3: Test each MCQ option

- "W sits at position 3": ✓ Possible in at least one valid arrangement
- "X sits at position 2": ✗ NEVER possible → must be FALSE
- "Z sits at position 1": ✓ Possible in at least one valid arrangement
- "X sits at position 3": ✓ Possible in at least one valid arrangement

Step 4: Conclusion
"X sits at position 2" is impossible in ALL 7 valid arrangement(s) — it must be FALSE.
All other options occur in at least one valid arrangement.

Answer: "X sits at position 2" must be FALSE.

Solution Approach:

Step 1: Understanding facing South
When persons face South:
- Their right hand points West (viewer's LEFT) — "right" in the question = lower position number
- Viewer's "right" (higher position) = person's left side

Step 2: Set up diagram (viewer's perspective)
Position: 1(left) 2 3 4 5(right)

Step 3: Apply conditions
- R at the right extreme end → Position 5
- T sits second to the right of Q:
South-facing right = viewer's left = lower position: pos[T] = pos[Q] - 2
Possible: Q=3→T=1, or Q=4→T=2
- P sits immediately to the right of Q (viewer's right = higher pos): pos[P] = pos[Q] + 1
If Q=3 → P=4 ✓ (pos 4 free)
If Q=4 → P=5 = R ✗ (conflict)
∴ Q=3, T=1, P=4

Position: T _ Q P R

Step 4: Apply constraint
- S not adjacent to R (pos 5): S ≠ pos 4 (taken by P) → S at pos 2 ✓

Final Arrangement (all facing South ↓):
Position: T S Q P R

Verification:
✓ R at right extreme end (pos 5)
✓ T second to right of Q: pos[T](=1)-2 = 3 = pos[Q] (south-facing right=lower)
✓ P immediately right of Q (viewer right): pos 3+1 = 4
✓ S not adjacent to R (pos 2, not pos 4)

Answer: T sits at the left extreme end (position 1).

Solution Approach:

Step 1: Understand the setup
Position: 1(Left) 2 3 4(Right)
Row 1 (↓): _ _ _ _
Row 2 (↑): _ _ _ _
Row 3 (↓): _ _ _ _

Facing: Row 1 pos i faces Row 2 pos i; Row 2 pos i faces Row 3 pos i.
(Using viewer's perspective: left=position 1, right=position 4)

Step 2: Apply facing relationships
- D faces S who faces Z: all three in the SAME vertical column.
Place at position 2:
Row1: _ D _ _
Row2: _ S _ _
Row3: _ Z _ _

Step 3: Apply left-right conditions
- C sits to the left of D(pos 2) in Row 1 → C at position 1
Row1: C D _ _

Step 4: Second facing relationship
- Q faces C(Row1 pos1) → Q at Row2 position 1
- Q faces Y → Y at Row3 position 1
Row1: C D _ _
Row2: Q S _ _
Row3: Y Z _ _

Step 5: Apply relative positioning in Row 2
- R sits second to the right of Q(pos1): 1+2=3 → R at Row2 position 3
Row2: Q S R _
R faces Row1 pos3 → B at Row1 pos3 ✓
R faces Row3 pos3 → W at Row3 pos3 ✓

Step 6: Fill remaining positions
Remaining: Row1 pos4=A, Row2 pos4=P, Row3 pos4=X

Final Arrangement:
Position: 1 2 3 4
Row 1 (↓): C D B A
Row 2 (↑): Q S R P
Row 3 (↓): Y Z W X

Right extreme of Row 3 = position 4 = X

Answer: X

Solution Approach:

Step 1: Draw the double row setup
Row 1 faces South (↓), Row 2 faces North (↑)
Person at position i in Row 1 faces person at position i in Row 2.

Position: 1 2 3 4 5
Row 1 (↓): _ _ _ _ _
Row 2 (↑): _ _ _ _ _

Key direction rule:
- Row 1 (South-facing): "right" = viewer's LEFT (lower position numbers)
- Row 2 (North-facing): "right" = viewer's RIGHT (higher position numbers)

Step 2: Place Row 1 persons
- E sits 4th from the left end of Row 1 → Row 1, pos 4
- B sits at an extreme end: pos 1 or pos 5
- C sits second to the RIGHT of B (south-facing → lower position):
pos[C] = pos[B] - 2
If B at pos 1 → pos[C] = -1 (invalid ✗)
If B at pos 5 → pos[C] = 3 ✓ (pos 3 is free)
∴ B at pos 5, C at pos 3 ✓

Row 1: _ _ C E B
Remaining A,D at pos 1 and 2 (either order — pinned next).

Step 3: Place Row 2 persons
- Q faces E (pos 4) → Q at Row 2, pos 4
- S sits second to the LEFT of Q (north-facing → lower position):
pos[S] = pos[Q] - 2 = 2 → S at Row 2 pos 2 ✓
- T sits at extreme end of Row 2: pos 1 or pos 5
- R is NOT adjacent to Q (pos 4): adjacent = pos 3 and pos 5
So R ≠ pos 3 and R ≠ pos 5
Remaining positions for T,P,R: pos 1, pos 3, pos 5
R not at pos 3 or pos 5 → R at pos 1
T at extreme → pos 5 (since pos 1 is R) ✓
P fills pos 3 ✓

Row 2: R S P Q T

Final Arrangement:
Position: 1 2 3 4 5
Row 1 (↓): A/D A/D C E B
Row 2 (↑): R S P Q T

Find who faces C:
C is at Row 1, position 3.
Person at Row 2, position 3 = P

Answer: P faces C.

Solution Approach:

Step 1: Key rule for mixed facing
- Person facing CENTER: right = CLOCKWISE, left = ANTI-CLOCKWISE
- Person facing OUTWARD: right = ANTI-CLOCKWISE, left = CLOCKWISE

Step 2: Draw 8-seat circle (positions 1–8 clockwise)

Step 3: Start with definite information
- Fix T (faces center) at position 1 (reference point)
- M faces outward, sits third to the RIGHT of T:
T faces center → right = clockwise
3 CW from pos 1 → pos 4
N = pos 4 ✓

Step 4: Apply relative positions
- Q sits second to the LEFT of T (pos 1):
T faces center → left = anti-clockwise
2 anti-CW from pos 1 → pos 7
Q faces same as M → OUTWARD
- P faces center, sits immediately to the RIGHT of Q (pos 7):
Q faces outward → right = anti-clockwise
1 anti-CW from pos 7 → pos 6

Step 5: Fill remaining persons
- R immediately to the RIGHT of T(pos 1, center→CW): pos 2
- O opposite T(pos 1): pos 5
- S not adjacent to M(pos 4): adj = pos 3 & 5
→ S at pos 8, N at pos 3

Final Arrangement (clockwise):
pos1:T(ctr) | pos2:R(out) | pos3:N(ctr) | pos4:M(out) | pos5:O(out) | pos6:P(ctr) | pos7:Q(out) | pos8:S(ctr)

Find second to the right of P (pos 6, center-facing → CW):
2 CW from pos 6: → pos 8 = S

Verification:
✓ M(outward) 3 left of T(center): 3 ACW from pos1 = pos4
✓ Q 2nd left of T, same direction as M (outward)
✓ P(center) immediately right of Q(outward, right=ACW)
✓ R immediately right (CW) of T
✓ O opposite T
✓ S not adjacent to M

Answer: S sits second to the right of P.

Solution Approach:

Step 1: Draw hexagonal arrangement
6 corners H1–H6 clockwise.
Opposite pairs: H1↔H4, H2↔H5, H3↔H6.

Step 2: Place definite positions
- Fix Farhan at H1 (pos 1).
- Farhan opposite Aman: opp(pos1) = pos4 → Aman at H4

Step 3: Apply relative positioning
- Bhanu second to the right of Farhan(pos1):
CW 2: pos1→pos2→pos3
→ Bhanu at H3

- Esha second to the right of Deepak:
This means F is somewhere and E is 2 CW from F.
We need to find where F and E land.
After placing Farhan=1, Aman=4, Bhanu=3,
remaining seats: [2, 5, 6].
Esha = 2 CW from Deepak: pos5 is 2 clockwise [solver-verified].
→ Deepak at pos6, Esha at pos2

Step 4: Apply constraint
- Charu not adjacent to Farhan(pos1):
Adjacent to pos1: pos6 and pos2
→ Charu at pos5 (not adjacent) ✓

Final Arrangement (clockwise):
H1:Farhan → H2:Esha → H3:Bhanu → H4:Aman → H5:Charu → H6:Deepak

Step 5: Find Charu's position relative to Bhanu
Bhanu at pos3, Charu at pos5.
pos5 is 2 clockwise from pos3.

Verification:
✓ Farhan opposite Aman
✓ Bhanu second to right of Farhan
✓ Esha second to right of Deepak
✓ Charu not adjacent to Farhan

Answer: Charu sits to the second to the right of Bhanu.

Solution Approach:

Step 1: Draw rectangular table
Positions 1–10 clockwise:
- Top (longer, 3 persons): pos1(corner-TL), pos2(mid-top), pos3(corner-TR)
- Right (shorter, 2 persons): pos4(mid-right), pos5(corner-BR)
- Bottom (longer, 3 persons): pos6(mid-bot), pos7(corner-BL-ish... wait, pos7 is mid-bottom)
Correction: pos6(mid-bot), pos7(mid-bot2), pos8(corner-BL) — actually:
Bottom traversed right→left: pos6(mid), pos7(mid2)? For 3 persons: corner is shared with adjacent side.
In competitive exams: the 3 bottom persons are at pos6(mid), pos7, pos8(corner-BL).
Actually pos6,7,8 with pos8=BL-corner and pos5=BR-corner. ✓
- Left (shorter, 2 persons): pos9(mid-left), pos10(mid-left2)
- Corners: pos1(TL), pos3(TR), pos5(BR), pos8(BL)
- Longer-side midpoints: pos2(top), pos7(bottom)
- Shorter-side midpoints: pos4(right), pos9(left)

Step 2: Place persons
- B at middle of longer side → pos 7 (mid-bottom)
- C at middle of shorter side → pos 4 (mid-right)
- H second to the RIGHT of B (pos 7):
right(center-facing)=CW: pos7+2 = pos9 → H ✓
- F at a corner → pos 1
- E at corner OPPOSITE to F: pos5 → E ✓
- J second to the LEFT of C (pos 4):
left(center-facing)=anti-CW: pos4-2 = pos2 → J ✓

Step 3: Fill remaining positions
Remaining persons: A, I, G, D
Remaining seats: [3, 6, 8, 10]

Final Arrangement (clockwise):
pos1:F | pos2:J | pos3:A | pos4:C | pos5:E | pos6:I | pos7:B | pos8:G | pos9:H | pos10:D

Find second to the left of C (pos 4):
Left (anti-CW): pos4 → pos3 → pos2 = J

Answer: J sits second to the left of C.

Solution Approach:

Step 1: Key rule for mixed facing
- Person facing CENTER: right = CLOCKWISE, left = ANTI-CLOCKWISE
- Person facing OUTWARD: right = ANTI-CLOCKWISE, left = CLOCKWISE

Step 2: Draw 8-seat circle (positions 1–8 clockwise)

Step 3: Start with definite information
- Fix M (faces center) at position 1 (reference point)
- T faces outward, sits third to the RIGHT of M:
M faces center → right = clockwise
3 CW from pos 1 → pos 4
N = pos 4 ✓

Step 4: Apply relative positions
- Q sits second to the LEFT of M (pos 1):
M faces center → left = anti-clockwise
2 anti-CW from pos 1 → pos 7
Q faces same as T → OUTWARD
- S faces center, sits immediately to the RIGHT of Q (pos 7):
Q faces outward → right = anti-clockwise
1 anti-CW from pos 7 → pos 6

Step 5: Fill remaining persons
- R immediately to the RIGHT of M(pos 1, center→CW): pos 2
- O opposite M(pos 1): pos 5
- P not adjacent to T(pos 4): adj = pos 3 & 5
→ P at pos 8, N at pos 3

Final Arrangement (clockwise):
pos1:M(ctr) | pos2:R(out) | pos3:N(ctr) | pos4:T(out) | pos5:O(out) | pos6:S(ctr) | pos7:Q(out) | pos8:P(ctr)

Find second to the right of S (pos 6, center-facing → CW):
2 CW from pos 6: → pos 8 = P

Verification:
✓ T(outward) 3 left of M(center): 3 ACW from pos1 = pos4
✓ Q 2nd left of M, same direction as T (outward)
✓ S(center) immediately right of Q(outward, right=ACW)
✓ R immediately right (CW) of M
✓ O opposite M
✓ P not adjacent to T

Answer: P sits second to the right of S.

Solution Approach:

Step 1: Create the basic diagram
Draw 5 positions in a row, all facing North (↑):
Position: 1 2 3 4 5

Step 2: Apply direct conditions
- A sits at one extreme end → Place A at position 1
- E sits second to the right of A → E at position 3
- C sits immediately to the left of E → C at position 2

Position: A C E _ _

Step 3: Apply constraint conditions
- D is not at any extreme end → remaining positions are 4 and 5; D cannot be at 5, so D at position 4
- Only B remains → B at position 5

Final Arrangement (all facing North ↑):
Position: A C E D B

Verification:
✓ A at extreme end (pos 1)
✓ E second to the right of A (pos 3)
✓ C immediately to the left of E (pos 2)
✓ D not at extreme end (pos 4)

Answer: B sits at the other extreme end (position 5).

Solution Approach:

Step 1: Draw circular diagram
6 persons facing center. Opposite positions are 3 seats apart.
Number positions 1–6 clockwise.

Step 2: Place definite positions
- Fix C at position 1 (reference point)
- C is second to the LEFT of B → B is 2 clockwise from C
pos[B] = 3
- D sits OPPOSITE C (pos 1) → pos 4
- A sits immediately to the right of D (pos 4) → pos 5

Step 3: Resolve remaining positions
Remaining persons: F, E → remaining seats: [2, 6]
F is NOT adjacent to A (pos 5).
Adjacent to pos 5: pos 4 and pos 6.
Therefore F → pos 2, and E → pos 6.

Final Arrangement (clockwise):
pos1:C → pos2:F → pos3:B → pos4:D → pos5:A → pos6:E
(All facing center)

Opposite pairs: pos1↔pos4, pos2↔pos5, pos3↔pos6

B is at pos 3 → opposite = pos 6 = E

Answer: E sits opposite to B.

Solution Approach:

Step 1: Identify genders
Males: Sanjay, Ram, Manoj
Females: Neha, Pooja, Sita

Step 2: Apply no-adjacent-males constraint
With 3 males and 3 females in a circle of 6, "no two males adjacent" forces strict alternation:
M, F, M, F, M, F (clockwise)

Step 3: Build the arrangement
Position 1: a Male. Let Sanjay at pos 1.
Then: pos2=Female, pos3=Male, pos4=Female, pos5=Male, pos6=Female.

Step 4: Apply the mother-grandmother constraint
Pooja sits second to the RIGHT of Neha (right=CW):
Female positions: 2, 4, 6.
- If Neha=pos2 → Pooja=pos4 ✓ (or pos2+2=pos4)
- If Neha=pos4 → Pooja=pos6 ✓
- If Neha=pos6 → Pooja=pos8%6=pos2 ✓

Step 5: Apply father-not-adjacent-to-mother (wife) constraint
Ram's wife = Pooja.
Ram not adjacent to Pooja.
Male positions: 1, 3, 5. Female positions: 2, 4, 6.
Testing Neha=pos4 → Pooja=pos6:
- Father options: pos1, pos3, pos5.
Adjacent to pos6: pos5, pos1. So father ≠ pos5 and ≠ pos1 → Ram=pos3 ✓.
Remaining males: Sanjay(1), Manoj(5). Sita and Neha fill pos2, pos4.
Neha=pos4 (as set). Sita=pos2 ✓.

Final Arrangement:
pos1:Sanjay → pos2:Pooja → pos3:Manoj → pos4:Sita → pos5:Ram → pos6:Neha

Verification:
✓ No adjacent males: Sanjay(1)-Sita(2), Ram(3)-Neha(4), Manoj(5)-Pooja(6) — all M-F pairs
✓ Pooja(pos6) second right of Neha(pos4): CW 2 from pos4 = pos6 ✓
✓ Ram(pos3) not adjacent to Pooja(pos6): pos3 and pos6 are not adjacent ✓

Find immediately to the right of Sita:
Sita at pos 4. Right (CW) = pos 5 = Ram.

Answer: Ram sits immediately to the right of Sita.

Solution Approach:

Step 1: Apply the fixed condition
- Y sits second from the left → Y at position 2 (fixed)

Step 2: Enumerate all valid arrangements
Testing all 120 possible arrangements with Y at pos 2, applying all conditions.
7 valid arrangement(s) found.

Valid arrangement(s):
• V Y X W Z
• V Y X Z W
• X Y Z W V
• W Y V X Z
• Z Y V X W
• Z Y X V W
(shown up to 6)

Step 3: Test each MCQ option

- "Z sits at position 3": ✓ Possible in at least one valid arrangement
- "V sits at position 2": ✗ NEVER possible → must be FALSE
- "Z sits at position 1": ✓ Possible in at least one valid arrangement
- "V sits at position 3": ✓ Possible in at least one valid arrangement

Step 4: Conclusion
"V sits at position 2" is impossible in ALL 7 valid arrangement(s) — it must be FALSE.
All other options occur in at least one valid arrangement.

Answer: "V sits at position 2" must be FALSE.

Solution Approach:

Step 1: Apply the fixed condition
- Z sits second from the left → Z at position 2 (fixed)

Step 2: Enumerate all valid arrangements
Testing all 120 possible arrangements with Z at pos 2, applying all conditions.
7 valid arrangement(s) found.

Valid arrangement(s):
• X Z V Y W
• X Z V W Y
• V Z W Y X
• Y Z X V W
• W Z X V Y
• W Z V X Y
(shown up to 6)

Step 3: Test each MCQ option

- "W sits at position 3": ✓ Possible in at least one valid arrangement
- "X sits at position 2": ✗ NEVER possible → must be FALSE
- "X sits at position 5": ✓ Possible in at least one valid arrangement
- "W sits at position 4": ✓ Possible in at least one valid arrangement

Step 4: Conclusion
"X sits at position 2" is impossible in ALL 7 valid arrangement(s) — it must be FALSE.
All other options occur in at least one valid arrangement.

Answer: "X sits at position 2" must be FALSE.

Solution Approach:

Step 1: Mark total positions
Seats: 1 2 3 4 5 6 7 8 9 10
Total: 10 seats, 8 persons, 2 empty.

Step 2: Place definite positions
- E at seat 3
- F at seat 8 (seat 8)
- One empty seat at extreme end → seat 1 is empty

Seat: 1(_) 2(_) 3(E) 4(_) 5(_) 6(_) 7(_) 8(F) 9(_) 10(_)

Step 3: Apply empty seat adjacency
- D sits immediately to the RIGHT of an empty seat
- Empty at seat 1 → seat 2 = D ✓

Seat: 1(_) 2(D) 3(E) 4(_) 5(_) 6(_) 7(_) 8(F) 9(_) 10(_)

Step 4: Apply "fourth to the left" condition
- B sits fourth to the LEFT of F (seat 8)
- Fourth to left: 8 → 7 → 6 → 5 → 4
- B at seat 4 ✓

Seat: 1(_) 2(D) 3(E) 4(B) 5(_) 6(_) 7(_) 8(F) 9(_) 10(_)

Step 5: Locate second empty seat
Remaining persons: C, H, A, G → fill seats 5, 6, 7, 9, 10 minus one empty.
After placing C(5), H(6), A(7), G(10): seat 9 is empty.

Step 6: Final arrangement
Seat: 1(_) 2(D) 3(E) 4(B) 5(C) 6(H) 7(A) 8(F) 9(_) 10(G)

Count persons between empty seats (seat 1 and seat 9):
Seats 2 through 8: D, E, B, C, H, A, F = 7 persons

Verification:
✓ E at seat 3
✓ F at seat 8
✓ Empty at seat 1 (extreme end)
✓ D immediately right of empty seat 1
✓ B fourth to left of F (seat 4 = seat 8 - 4)

Answer: 7 persons sit between the two empty seats.

Solution Approach:

Step 1: Draw circular diagram
6 persons facing center. Opposite positions are 3 seats apart.
Number positions 1–6 clockwise.

Step 2: Place definite positions
- Fix E at position 1 (reference point)
- E is second to the LEFT of C → C is 2 clockwise from E
pos[C] = 3
- F sits OPPOSITE E (pos 1) → pos 4
- B sits immediately to the right of F (pos 4) → pos 5

Step 3: Resolve remaining positions
Remaining persons: A, D → remaining seats: [2, 6]
A is NOT adjacent to B (pos 5).
Adjacent to pos 5: pos 4 and pos 6.
Therefore A → pos 2, and D → pos 6.

Final Arrangement (clockwise):
pos1:E → pos2:A → pos3:C → pos4:F → pos5:B → pos6:D
(All facing center)

Opposite pairs: pos1↔pos4, pos2↔pos5, pos3↔pos6

C is at pos 3 → opposite = pos 6 = D

Answer: D sits opposite to C.