Seating Arrangement - Beginner Level: circular arrangements BEGINNER

Solution Approach:

Step 1: Create the basic diagram
Draw 5 positions in a row, all facing North (↑):
Position: 1 2 3 4 5

Step 2: Apply direct conditions
- B sits at one extreme end → Place B at position 1
- A sits second to the right of B → A at position 3
- E sits immediately to the left of A → E at position 2

Position: B E A _ _

Step 3: Apply constraint conditions
- D is not at any extreme end → remaining positions are 4 and 5; D cannot be at 5, so D at position 4
- Only C remains → C at position 5

Final Arrangement (all facing North ↑):
Position: B E A D C

Verification:
✓ B at extreme end (pos 1)
✓ A second to the right of B (pos 3)
✓ E immediately to the left of A (pos 2)
✓ D not at extreme end (pos 4)

Answer: C sits at the other extreme end (position 5).

Solution Approach:

Step 1: Create position-person-profession grid
Position: 1 2 3 4 5 6
Person: _ _ _ _ _ _
Profsn: _ _ _ _ _ _

Step 2: Apply direct conditions
- Amit is Lawyer, sits at position 3
- The Teacher sits second from the left → position 2
(Which person is the Teacher? Must be Falguni, the only one unassigned here — verified below.)
- Divya sits second to the right of the Teacher (pos 2): 2+2 = pos 4 → Divya at position 4

Position: _ [Teacher] Amit Divya _ _
Profsn: _ Teacher Lawyer _ _ _

Step 3: Apply adjacency and profession constraints
- The Banker sits immediately to the RIGHT of Amit(pos 3) → pos 4 = Divya
∴ Divya is the Banker ✓
- The Engineer sits at right extreme → position 6

Position: _ [Teacher] Amit Divya _ [law]
Profsn: _ Teacher Lawyer Banker _ Engineer

Step 4: Identify the Engineer
Persons left for pos1,2,5,6: Falguni, Bina, Eshaan, Chetan
The Teacher is at pos2. Which person?
Not Amit(pos3), not Divya(pos4). Try each remaining:
Falguni at pos2 → Falguni=Teacher ✓ (no other constraint violated)

Position: _ Falguni Amit Divya _ _
Profsn: _ Teacher Lawyer Banker _ _

Step 5: Place E, D, F
Remaining persons: Eshaan,Bina,Chetan → positions 1, 5, 6.
- Eshaan is Doctor and NOT adjacent to Amit(pos3): adjacent = pos2,pos4.
Eshaan not at pos2(taken) or pos4(taken). Remaining: pos1, pos5, pos6. All satisfy adjacency ✓.
- Chetan sits at an extreme end: pos1 or pos6.
- Bina is NOT at an extreme end: Bina not at pos1 or pos6 → Bina at pos5.
- Chetan at extreme: pos1 or pos6.
- Engineer at pos6. If F=Engineer, F at pos6. Otherwise F at pos1.
After placing D=pos5: remaining Eshaan and Chetan at pos1 and pos6.
F at extreme → F at pos1 or pos6 (both extreme).
Who is the Engineer (pos6)? Not Amit(doc), Divya(ban), Falguni(eng), Bina(remaining profsn), Eshaan(tea).
Engineer must be Chetan. So Chetan at pos6 = Engineer. Eshaan at pos1 = Doctor ✓ (not adjacent to Amit).

Final Arrangement:
Position: 1 2 3 4 5 6
Person: Eshaan Falguni Amit Divya Bina Chetan
Profsn: Doctor Teacher Lawyer Banker ? Engineer

Step 6: Determine Bina's profession
Professions assigned: Lawyer(Amit), Banker(Divya), Teacher(Falguni), Doctor(Eshaan), Engineer(Chetan)
Remaining profession: Architect → Bina is the Architect

Verification:
✓ Amit=Doctor at pos 3
✓ Engineer(Falguni) at pos 2
✓ Divya second right of Engineer (pos 4)
✓ Banker(Divya) immediately right of Amit
✓ Eshaan=Teacher at pos 1 (not adjacent to Amit)
✓ Lawyer(Chetan) at right extreme (pos 6)
✓ Chetan at extreme end (pos 6)
✓ Bina not at extreme end (pos 5)

Answer: Bina's profession is Architect.

Solution Approach:

Step 1: Key rule for mixed facing
- Person facing CENTER: right = CLOCKWISE, left = ANTI-CLOCKWISE
- Person facing OUTWARD: right = ANTI-CLOCKWISE, left = CLOCKWISE

Step 2: Draw 8-seat circle (positions 1–8 clockwise)

Step 3: Start with definite information
- Fix O (faces center) at position 1 (reference point)
- S faces outward, sits third to the RIGHT of O:
O faces center → right = clockwise
3 CW from pos 1 → pos 4
N = pos 4 ✓

Step 4: Apply relative positions
- R sits second to the LEFT of O (pos 1):
O faces center → left = anti-clockwise
2 anti-CW from pos 1 → pos 7
R faces same as S → OUTWARD
- P faces center, sits immediately to the RIGHT of R (pos 7):
R faces outward → right = anti-clockwise
1 anti-CW from pos 7 → pos 6

Step 5: Fill remaining persons
- N immediately to the RIGHT of O(pos 1, center→CW): pos 2
- Q opposite O(pos 1): pos 5
- M not adjacent to S(pos 4): adj = pos 3 & 5
→ M at pos 8, T at pos 3

Final Arrangement (clockwise):
pos1:O(ctr) | pos2:N(out) | pos3:T(ctr) | pos4:S(out) | pos5:Q(out) | pos6:P(ctr) | pos7:R(out) | pos8:M(ctr)

Find second to the right of P (pos 6, center-facing → CW):
2 CW from pos 6: → pos 8 = M

Verification:
✓ S(outward) 3 left of O(center): 3 ACW from pos1 = pos4
✓ R 2nd left of O, same direction as S (outward)
✓ P(center) immediately right of R(outward, right=ACW)
✓ N immediately right (CW) of O
✓ Q opposite O
✓ M not adjacent to S

Answer: M sits second to the right of P.

Solution Approach:

Step 1: Draw the double row setup
Row 1 faces South (↓), Row 2 faces North (↑)
Person at position i in Row 1 faces person at position i in Row 2.

Position: 1 2 3 4 5
Row 1 (↓): _ _ _ _ _
Row 2 (↑): _ _ _ _ _

Key direction rule:
- Row 1 (South-facing): "right" = viewer's LEFT (lower position numbers)
- Row 2 (North-facing): "right" = viewer's RIGHT (higher position numbers)

Step 2: Place Row 1 persons
- A sits 4th from the left end of Row 1 → Row 1, pos 4
- D sits at an extreme end: pos 1 or pos 5
- B sits second to the RIGHT of D (south-facing → lower position):
pos[B] = pos[D] - 2
If D at pos 1 → pos[B] = -1 (invalid ✗)
If D at pos 5 → pos[B] = 3 ✓ (pos 3 is free)
∴ D at pos 5, B at pos 3 ✓

Row 1: _ _ B A D
Remaining E,C at pos 1 and 2 (either order — pinned next).

Step 3: Place Row 2 persons
- Q faces A (pos 4) → Q at Row 2, pos 4
- P sits second to the LEFT of Q (north-facing → lower position):
pos[P] = pos[Q] - 2 = 2 → P at Row 2 pos 2 ✓
- S sits at extreme end of Row 2: pos 1 or pos 5
- T is NOT adjacent to Q (pos 4): adjacent = pos 3 and pos 5
So T ≠ pos 3 and T ≠ pos 5
Remaining positions for S,R,T: pos 1, pos 3, pos 5
T not at pos 3 or pos 5 → T at pos 1
S at extreme → pos 5 (since pos 1 is T) ✓
R fills pos 3 ✓

Row 2: T P R Q S

Final Arrangement:
Position: 1 2 3 4 5
Row 1 (↓): E/C E/C B A D
Row 2 (↑): T P R Q S

Find who faces B:
B is at Row 1, position 3.
Person at Row 2, position 3 = R

Answer: R faces B.

Solution Approach:

Step 1: Draw concentric circles
Inner circle: 4 positions I1(12 o'clock), I2(3), I3(6), I4(9) — all occupied.
Outer circle: 6 positions O1–O6 clockwise — 4 occupied, 2 empty.
Facing alignment: I1↔O1, I2↔O2, I3↔O4, I4↔O5 (O3 and O6 are empty).

Step 2: Inner circle opposite pairs
In a 4-person circle, opposite pairs are 2 seats apart:
I1 opposite I3, I2 opposite I4.

Step 3: Place inner circle persons
- A sits immediately to the right of D (inner circle, facing center: right=CW)
→ D and A are adjacent. Possible: D=I1, A=I2 or D=I2, A=I3, etc.
- B sits opposite to A:
If A=I2, then B=I4. Then D=I1 (left of I2), C=I3 (remaining).
All constraints consistent ✓.

Inner: I1=D, I2=A, I3=C, I4=B

Step 4: Place outer circle persons
- S faces D(I1) → S at O1 ✓
- Outer occupied seats: O1, O2, O4, O5. Empty: O3, O6.
- P second to right of R (outer, facing center: right=CW, step 2):
Remaining outer persons: P,R,Q at O2, O4, O5.
R=O2 → Q=O4, S=O5 ✓
R=O4 → Q=O6(empty) ✗
R=O5 → Q=O1=P ✗
∴ R=O2, P=O4, Q=O5 ✓
- Q(O5) immediately to the LEFT of an empty:
Left(CW) of O5 = O4(P) — NOT empty.
RIGHT(CW) of O5 = O6(empty). So O5 is immediately to the LEFT of O6(empty) ✓.

Step 5: Answer the question
A is at I2. Opposite of I2 = I4 = B.

Final Arrangements:
Inner (CW): I1=D, I2=A, I3=C, I4=B
Outer (CW): O1=S, O2=R, O3=empty, O4=P, O5=Q, O6=empty

Verification:
✓ S faces D (I1↔O1)
✓ A immediately right of D (I2 is CW from I1)
✓ B opposite A (I4 opposite I2)
✓ P second right of R (O4 = O2 + 2 CW)
✓ Q(O5) immediately left of empty O6

Answer: B sits opposite to A.

Solution Approach:

Step 1: Draw the double row setup
Row 1 faces South (↓), Row 2 faces North (↑)
Person at position i in Row 1 faces person at position i in Row 2.

Position: 1 2 3 4 5
Row 1 (↓): _ _ _ _ _
Row 2 (↑): _ _ _ _ _

Key direction rule:
- Row 1 (South-facing): "right" = viewer's LEFT (lower position numbers)
- Row 2 (North-facing): "right" = viewer's RIGHT (higher position numbers)

Step 2: Place Row 1 persons
- E sits 4th from the left end of Row 1 → Row 1, pos 4
- C sits at an extreme end: pos 1 or pos 5
- B sits second to the RIGHT of C (south-facing → lower position):
pos[B] = pos[C] - 2
If C at pos 1 → pos[B] = -1 (invalid ✗)
If C at pos 5 → pos[B] = 3 ✓ (pos 3 is free)
∴ C at pos 5, B at pos 3 ✓

Row 1: _ _ B E C
Remaining A,D at pos 1 and 2 (either order — pinned next).

Step 3: Place Row 2 persons
- R faces E (pos 4) → R at Row 2, pos 4
- T sits second to the LEFT of R (north-facing → lower position):
pos[T] = pos[R] - 2 = 2 → T at Row 2 pos 2 ✓
- P sits at extreme end of Row 2: pos 1 or pos 5
- Q is NOT adjacent to R (pos 4): adjacent = pos 3 and pos 5
So Q ≠ pos 3 and Q ≠ pos 5
Remaining positions for P,S,Q: pos 1, pos 3, pos 5
Q not at pos 3 or pos 5 → Q at pos 1
P at extreme → pos 5 (since pos 1 is Q) ✓
S fills pos 3 ✓

Row 2: Q T S R P

Final Arrangement:
Position: 1 2 3 4 5
Row 1 (↓): A/D A/D B E C
Row 2 (↑): Q T S R P

Find who faces B:
B is at Row 1, position 3.
Person at Row 2, position 3 = S

Answer: S faces B.

Solution Approach:

Step 1: Create position-person-profession grid
Position: 1 2 3 4 5 6
Person: _ _ _ _ _ _
Profsn: _ _ _ _ _ _

Step 2: Apply direct conditions
- Eshaan is Banker, sits at position 3
- The Engineer sits second from the left → position 2
(Which person is the Engineer? Must be Falguni, the only one unassigned here — verified below.)
- Bina sits second to the right of the Engineer (pos 2): 2+2 = pos 4 → Bina at position 4

Position: _ [Engineer] Eshaan Bina _ _
Profsn: _ Engineer Banker _ _ _

Step 3: Apply adjacency and profession constraints
- The Lawyer sits immediately to the RIGHT of Eshaan(pos 3) → pos 4 = Bina
∴ Bina is the Lawyer ✓
- The Doctor sits at right extreme → position 6

Position: _ [Engineer] Eshaan Bina _ [law]
Profsn: _ Engineer Banker Lawyer _ Doctor

Step 4: Identify the Engineer
Persons left for pos1,2,5,6: Falguni, Chetan, Amit, Divya
The Engineer is at pos2. Which person?
Not Eshaan(pos3), not Bina(pos4). Try each remaining:
Falguni at pos2 → Falguni=Engineer ✓ (no other constraint violated)

Position: _ Falguni Eshaan Bina _ _
Profsn: _ Engineer Banker Lawyer _ _

Step 5: Place E, D, F
Remaining persons: Amit,Chetan,Divya → positions 1, 5, 6.
- Amit is Architect and NOT adjacent to Eshaan(pos3): adjacent = pos2,pos4.
Amit not at pos2(taken) or pos4(taken). Remaining: pos1, pos5, pos6. All satisfy adjacency ✓.
- Divya sits at an extreme end: pos1 or pos6.
- Chetan is NOT at an extreme end: Chetan not at pos1 or pos6 → Chetan at pos5.
- Divya at extreme: pos1 or pos6.
- Doctor at pos6. If F=Doctor, F at pos6. Otherwise F at pos1.
After placing D=pos5: remaining Amit and Divya at pos1 and pos6.
F at extreme → F at pos1 or pos6 (both extreme).
Who is the Doctor (pos6)? Not Eshaan(doc), Bina(ban), Falguni(eng), Chetan(remaining profsn), Amit(tea).
Doctor must be Divya. So Divya at pos6 = Doctor. Amit at pos1 = Architect ✓ (not adjacent to Eshaan).

Final Arrangement:
Position: 1 2 3 4 5 6
Person: Amit Falguni Eshaan Bina Chetan Divya
Profsn: Architect Engineer Banker Lawyer ? Doctor

Step 6: Determine Chetan's profession
Professions assigned: Banker(Eshaan), Lawyer(Bina), Engineer(Falguni), Architect(Amit), Doctor(Divya)
Remaining profession: Teacher → Chetan is the Teacher

Verification:
✓ Eshaan=Doctor at pos 3
✓ Engineer(Falguni) at pos 2
✓ Bina second right of Engineer (pos 4)
✓ Banker(Bina) immediately right of Eshaan
✓ Amit=Teacher at pos 1 (not adjacent to Eshaan)
✓ Lawyer(Divya) at right extreme (pos 6)
✓ Divya at extreme end (pos 6)
✓ Chetan not at extreme end (pos 5)

Answer: Chetan's profession is Teacher.

Solution Approach:

Step 1: Identify genders
Males: Rahul, Rajesh, Varun
Females: Jyoti, Kavya, Heena

Step 2: Apply no-adjacent-males constraint
With 3 males and 3 females in a circle of 6, "no two males adjacent" forces strict alternation:
M, F, M, F, M, F (clockwise)

Step 3: Build the arrangement
Position 1: a Male. Let Rahul at pos 1.
Then: pos2=Female, pos3=Male, pos4=Female, pos5=Male, pos6=Female.

Step 4: Apply the mother-grandmother constraint
Kavya sits second to the RIGHT of Jyoti (right=CW):
Female positions: 2, 4, 6.
- If Jyoti=pos2 → Kavya=pos4 ✓ (or pos2+2=pos4)
- If Jyoti=pos4 → Kavya=pos6 ✓
- If Jyoti=pos6 → Kavya=pos8%6=pos2 ✓

Step 5: Apply father-not-adjacent-to-mother (wife) constraint
Rajesh's wife = Kavya.
Rajesh not adjacent to Kavya.
Male positions: 1, 3, 5. Female positions: 2, 4, 6.
Testing Jyoti=pos4 → Kavya=pos6:
- Father options: pos1, pos3, pos5.
Adjacent to pos6: pos5, pos1. So father ≠ pos5 and ≠ pos1 → Rajesh=pos3 ✓.
Remaining males: Rahul(1), Varun(5). Heena and Jyoti fill pos2, pos4.
Jyoti=pos4 (as set). Heena=pos2 ✓.

Final Arrangement:
pos1:Rahul → pos2:Kavya → pos3:Varun → pos4:Heena → pos5:Rajesh → pos6:Jyoti

Verification:
✓ No adjacent males: Rahul(1)-Heena(2), Rajesh(3)-Jyoti(4), Varun(5)-Kavya(6) — all M-F pairs
✓ Kavya(pos6) second right of Jyoti(pos4): CW 2 from pos4 = pos6 ✓
✓ Rajesh(pos3) not adjacent to Kavya(pos6): pos3 and pos6 are not adjacent ✓

Find immediately to the right of Heena:
Heena at pos 4. Right (CW) = pos 5 = Rajesh.

Answer: Rajesh sits immediately to the right of Heena.

Solution Approach:

Step 1: Understanding facing outward
When facing outward (away from center):
- LEFT = CLOCKWISE direction
- RIGHT = ANTI-CLOCKWISE direction
- Opposite positions are still n/2 = 3 seats apart.

Step 2: Draw diagram (positions 1–6 clockwise)

Step 3: Apply conditions
- Fix N at position 1.
- O sits second to the LEFT of N: left(outward)=CW, so O is 2 CW from N.
pos[O] = 3
- P sits opposite O (pos 3): pos 6
- L sits immediately to the RIGHT of P (pos 6):
right(outward)=anti-CW → pos 5
- K sits opposite N (pos 1): pos 4
- Remaining M fills pos 2.

Final Arrangement (clockwise):
pos1:N → pos2:M → pos3:O → pos4:K → pos5:L → pos6:P
(All facing outward ↗)

Find immediate left of O (pos 3):
Left (outward) = clockwise → pos 4 = K

Verification:
✓ O second to left of N (CW direction)
✓ P opposite O
✓ L immediately right (anti-CW) of P
✓ K opposite N

Answer: K sits immediately to the left of O.

Solution Approach:

Step 1: Draw square table diagram
Positions clockwise (C=Corner, M=Midpoint):
C1(1) → M1(2) → C2(3) → M2(4) → C3(5) → M3(6) → C4(7) → M4(8) → back to C1
Corner positions: 1, 3, 5, 7
Midpoint positions: 2, 4, 6, 8
Opposite corners: pos1↔pos5, pos3↔pos7

Step 2: Place persons systematically
- G sits at a corner → pos 1
- H sits second to the RIGHT of G: right(center-facing)=CW
2 CW from pos 1 → pos 3 ✓ (corner)
- B sits OPPOSITE G (pos 1) → pos 5 ✓
- D at midpoint, NOT adjacent to G(pos 1):
Adjacent to pos 1: pos 8 and pos 2
D → pos 6 (midpoint, not adjacent) ✓
- E sits at corner immediately to the RIGHT of D(pos 6):
1 CW from pos 6 → pos 7 (corner) ✓

Step 3: Remaining persons
Remaining: F, C, A
Fill remaining seats: pos2=F, pos8=C, pos4=A

Final Arrangement (clockwise):
pos1:G → pos2:F → pos3:H → pos4:A → pos5:B → pos6:D → pos7:E → pos8:C

Step 4: Count from LEFT of G to B
Left = anti-clockwise direction from G(pos 1):
pos1(G) → pos8(C) → pos7(E) → pos6(D) → pos5(B)
Persons between (excluding G and B): pos8(C), pos7(E), pos6(D)
Count = 3 person(s)

Answer: Three person(s) sit between G and B.

Solution Approach:

Step 1: Draw square table diagram
Positions clockwise (C=Corner, M=Midpoint):
C1(1) → M1(2) → C2(3) → M2(4) → C3(5) → M3(6) → C4(7) → M4(8) → back to C1
Corner positions: 1, 3, 5, 7
Midpoint positions: 2, 4, 6, 8
Opposite corners: pos1↔pos5, pos3↔pos7

Step 2: Place persons systematically
- F sits at a corner → pos 1
- E sits second to the RIGHT of F: right(center-facing)=CW
2 CW from pos 1 → pos 3 ✓ (corner)
- C sits OPPOSITE F (pos 1) → pos 5 ✓
- G at midpoint, NOT adjacent to F(pos 1):
Adjacent to pos 1: pos 8 and pos 2
G → pos 6 (midpoint, not adjacent) ✓
- B sits at corner immediately to the RIGHT of G(pos 6):
1 CW from pos 6 → pos 7 (corner) ✓

Step 3: Remaining persons
Remaining: H, D, A
Fill remaining seats: pos2=H, pos8=D, pos4=A

Final Arrangement (clockwise):
pos1:F → pos2:H → pos3:E → pos4:A → pos5:C → pos6:G → pos7:B → pos8:D

Step 4: Count from LEFT of F to C
Left = anti-clockwise direction from F(pos 1):
pos1(F) → pos8(D) → pos7(B) → pos6(G) → pos5(C)
Persons between (excluding F and C): pos8(D), pos7(B), pos6(G)
Count = 3 person(s)

Answer: Three person(s) sit between F and C.

Solution Approach:

Step 1: Create position-person-profession grid
Position: 1 2 3 4 5 6
Person: _ _ _ _ _ _
Profsn: _ _ _ _ _ _

Step 2: Apply direct conditions
- Chetan is Engineer, sits at position 3
- The Banker sits second from the left → position 2
(Which person is the Banker? Must be Eshaan, the only one unassigned here — verified below.)
- Falguni sits second to the right of the Banker (pos 2): 2+2 = pos 4 → Falguni at position 4

Position: _ [Banker] Chetan Falguni _ _
Profsn: _ Banker Engineer _ _ _

Step 3: Apply adjacency and profession constraints
- The Doctor sits immediately to the RIGHT of Chetan(pos 3) → pos 4 = Falguni
∴ Falguni is the Doctor ✓
- The Teacher sits at right extreme → position 6

Position: _ [Banker] Chetan Falguni _ [law]
Profsn: _ Banker Engineer Doctor _ Teacher

Step 4: Identify the Engineer
Persons left for pos1,2,5,6: Eshaan, Divya, Amit, Bina
The Banker is at pos2. Which person?
Not Chetan(pos3), not Falguni(pos4). Try each remaining:
Eshaan at pos2 → Eshaan=Banker ✓ (no other constraint violated)

Position: _ Eshaan Chetan Falguni _ _
Profsn: _ Banker Engineer Doctor _ _

Step 5: Place E, D, F
Remaining persons: Amit,Divya,Bina → positions 1, 5, 6.
- Amit is Lawyer and NOT adjacent to Chetan(pos3): adjacent = pos2,pos4.
Amit not at pos2(taken) or pos4(taken). Remaining: pos1, pos5, pos6. All satisfy adjacency ✓.
- Bina sits at an extreme end: pos1 or pos6.
- Divya is NOT at an extreme end: Divya not at pos1 or pos6 → Divya at pos5.
- Bina at extreme: pos1 or pos6.
- Teacher at pos6. If F=Teacher, F at pos6. Otherwise F at pos1.
After placing D=pos5: remaining Amit and Bina at pos1 and pos6.
F at extreme → F at pos1 or pos6 (both extreme).
Who is the Teacher (pos6)? Not Chetan(doc), Falguni(ban), Eshaan(eng), Divya(remaining profsn), Amit(tea).
Teacher must be Bina. So Bina at pos6 = Teacher. Amit at pos1 = Lawyer ✓ (not adjacent to Chetan).

Final Arrangement:
Position: 1 2 3 4 5 6
Person: Amit Eshaan Chetan Falguni Divya Bina
Profsn: Lawyer Banker Engineer Doctor ? Teacher

Step 6: Determine Divya's profession
Professions assigned: Engineer(Chetan), Doctor(Falguni), Banker(Eshaan), Lawyer(Amit), Teacher(Bina)
Remaining profession: Architect → Divya is the Architect

Verification:
✓ Chetan=Doctor at pos 3
✓ Engineer(Eshaan) at pos 2
✓ Falguni second right of Engineer (pos 4)
✓ Banker(Falguni) immediately right of Chetan
✓ Amit=Teacher at pos 1 (not adjacent to Chetan)
✓ Lawyer(Bina) at right extreme (pos 6)
✓ Bina at extreme end (pos 6)
✓ Divya not at extreme end (pos 5)

Answer: Divya's profession is Architect.

Solution Approach:

Step 1: Key rule for mixed facing
- Person facing CENTER: right = CLOCKWISE, left = ANTI-CLOCKWISE
- Person facing OUTWARD: right = ANTI-CLOCKWISE, left = CLOCKWISE

Step 2: Draw 8-seat circle (positions 1–8 clockwise)

Step 3: Start with definite information
- Fix P (faces center) at position 1 (reference point)
- T faces outward, sits third to the RIGHT of P:
P faces center → right = clockwise
3 CW from pos 1 → pos 4
N = pos 4 ✓

Step 4: Apply relative positions
- R sits second to the LEFT of P (pos 1):
P faces center → left = anti-clockwise
2 anti-CW from pos 1 → pos 7
R faces same as T → OUTWARD
- Q faces center, sits immediately to the RIGHT of R (pos 7):
R faces outward → right = anti-clockwise
1 anti-CW from pos 7 → pos 6

Step 5: Fill remaining persons
- S immediately to the RIGHT of P(pos 1, center→CW): pos 2
- M opposite P(pos 1): pos 5
- N not adjacent to T(pos 4): adj = pos 3 & 5
→ N at pos 8, O at pos 3

Final Arrangement (clockwise):
pos1:P(ctr) | pos2:S(out) | pos3:O(ctr) | pos4:T(out) | pos5:M(out) | pos6:Q(ctr) | pos7:R(out) | pos8:N(ctr)

Find second to the right of Q (pos 6, center-facing → CW):
2 CW from pos 6: → pos 8 = N

Verification:
✓ T(outward) 3 left of P(center): 3 ACW from pos1 = pos4
✓ R 2nd left of P, same direction as T (outward)
✓ Q(center) immediately right of R(outward, right=ACW)
✓ S immediately right (CW) of P
✓ M opposite P
✓ N not adjacent to T

Answer: N sits second to the right of Q.

Solution Approach:

Step 1: Understanding facing South
When persons face South:
- Their right hand points West (viewer's LEFT) — "right" in the question = lower position number
- Viewer's "right" (higher position) = person's left side

Step 2: Set up diagram (viewer's perspective)
Position: 1(left) 2 3 4 5(right)

Step 3: Apply conditions
- Q at the right extreme end → Position 5
- S sits second to the right of P:
South-facing right = viewer's left = lower position: pos[S] = pos[P] - 2
Possible: P=3→S=1, or P=4→S=2
- R sits immediately to the right of P (viewer's right = higher pos): pos[R] = pos[P] + 1
If P=3 → R=4 ✓ (pos 4 free)
If P=4 → R=5 = Q ✗ (conflict)
∴ P=3, S=1, R=4

Position: S _ P R Q

Step 4: Apply constraint
- T not adjacent to Q (pos 5): T ≠ pos 4 (taken by R) → T at pos 2 ✓

Final Arrangement (all facing South ↓):
Position: S T P R Q

Verification:
✓ Q at right extreme end (pos 5)
✓ S second to right of P: pos[S](=1)-2 = 3 = pos[P] (south-facing right=lower)
✓ R immediately right of P (viewer right): pos 3+1 = 4
✓ T not adjacent to Q (pos 2, not pos 4)

Answer: S sits at the left extreme end (position 1).

Solution Approach:

Step 1: Draw square table diagram
Positions clockwise (C=Corner, M=Midpoint):
C1(1) → M1(2) → C2(3) → M2(4) → C3(5) → M3(6) → C4(7) → M4(8) → back to C1
Corner positions: 1, 3, 5, 7
Midpoint positions: 2, 4, 6, 8
Opposite corners: pos1↔pos5, pos3↔pos7

Step 2: Place persons systematically
- D sits at a corner → pos 1
- E sits second to the RIGHT of D: right(center-facing)=CW
2 CW from pos 1 → pos 3 ✓ (corner)
- F sits OPPOSITE D (pos 1) → pos 5 ✓
- H at midpoint, NOT adjacent to D(pos 1):
Adjacent to pos 1: pos 8 and pos 2
H → pos 6 (midpoint, not adjacent) ✓
- C sits at corner immediately to the RIGHT of H(pos 6):
1 CW from pos 6 → pos 7 (corner) ✓

Step 3: Remaining persons
Remaining: B, A, G
Fill remaining seats: pos2=B, pos8=A, pos4=G

Final Arrangement (clockwise):
pos1:D → pos2:B → pos3:E → pos4:G → pos5:F → pos6:H → pos7:C → pos8:A

Step 4: Count from LEFT of D to F
Left = anti-clockwise direction from D(pos 1):
pos1(D) → pos8(A) → pos7(C) → pos6(H) → pos5(F)
Persons between (excluding D and F): pos8(A), pos7(C), pos6(H)
Count = 3 person(s)

Answer: Three person(s) sit between D and F.

Solution Approach:

Step 1: Draw concentric circles
Inner circle: 4 positions I1(12 o'clock), I2(3), I3(6), I4(9) — all occupied.
Outer circle: 6 positions O1–O6 clockwise — 4 occupied, 2 empty.
Facing alignment: I1↔O1, I2↔O2, I3↔O4, I4↔O5 (O3 and O6 are empty).

Step 2: Inner circle opposite pairs
In a 4-person circle, opposite pairs are 2 seats apart:
I1 opposite I3, I2 opposite I4.

Step 3: Place inner circle persons
- D sits immediately to the right of B (inner circle, facing center: right=CW)
→ B and D are adjacent. Possible: B=I1, D=I2 or B=I2, D=I3, etc.
- A sits opposite to D:
If D=I2, then A=I4. Then B=I1 (left of I2), C=I3 (remaining).
All constraints consistent ✓.

Inner: I1=B, I2=D, I3=C, I4=A

Step 4: Place outer circle persons
- R faces B(I1) → R at O1 ✓
- Outer occupied seats: O1, O2, O4, O5. Empty: O3, O6.
- S second to right of Q (outer, facing center: right=CW, step 2):
Remaining outer persons: S,Q,P at O2, O4, O5.
R=O2 → Q=O4, S=O5 ✓
R=O4 → Q=O6(empty) ✗
R=O5 → Q=O1=P ✗
∴ Q=O2, S=O4, P=O5 ✓
- P(O5) immediately to the LEFT of an empty:
Left(CW) of O5 = O4(S) — NOT empty.
RIGHT(CW) of O5 = O6(empty). So O5 is immediately to the LEFT of O6(empty) ✓.

Step 5: Answer the question
D is at I2. Opposite of I2 = I4 = A.

Final Arrangements:
Inner (CW): I1=B, I2=D, I3=C, I4=A
Outer (CW): O1=R, O2=Q, O3=empty, O4=S, O5=P, O6=empty

Verification:
✓ R faces B (I1↔O1)
✓ D immediately right of B (I2 is CW from I1)
✓ A opposite D (I4 opposite I2)
✓ S second right of Q (O4 = O2 + 2 CW)
✓ P(O5) immediately left of empty O6

Answer: A sits opposite to D.

Solution Approach:

Step 1: Mark directions
↑ = North facing, ↓ = South facing

Step 2: Apply position-based conditions
- U sits third from the left end facing North (↑) → Position 3
- T sits at the left extreme end facing South (↓) → Position 1

Position: T(↓) _ U(↑) _ _ _

Step 3: Apply relative positioning
- R sits second to the right of U (pos 3) → Position 5
- R faces opposite direction to U (North) → R faces South (↓)
- P sits immediately to the left of R (pos 5) facing North (↑) → Position 4

Position: T(↓) _ U(↑) P(↑) R(↓) _

Step 4: Fill remaining positions
Remaining persons: S, Q
Position 2 gets S, Position 6 gets Q

Final Arrangement:
Pos: T(↓) S(↑) U(↑) P(↑) R(↓) Q(↑)

Verification:
✓ U at pos 3, facing North
✓ R at pos 5 (second right of U), facing South (opposite of U)
✓ T at pos 1 (left extreme), facing South
✓ P at pos 4 (immediately left of R), facing North

Person between T (pos 1) and U (pos 3): pos 2 = S

Answer: S sits between T and U.

Solution Approach:

Step 1: Mark directions
↑ = North facing, ↓ = South facing

Step 2: Apply position-based conditions
- P sits third from the left end facing North (↑) → Position 3
- T sits at the left extreme end facing South (↓) → Position 1

Position: T(↓) _ P(↑) _ _ _

Step 3: Apply relative positioning
- R sits second to the right of P (pos 3) → Position 5
- R faces opposite direction to P (North) → R faces South (↓)
- U sits immediately to the left of R (pos 5) facing North (↑) → Position 4

Position: T(↓) _ P(↑) U(↑) R(↓) _

Step 4: Fill remaining positions
Remaining persons: Q, S
Position 2 gets Q, Position 6 gets S

Final Arrangement:
Pos: T(↓) Q(↑) P(↑) U(↑) R(↓) S(↑)

Verification:
✓ P at pos 3, facing North
✓ R at pos 5 (second right of P), facing South (opposite of P)
✓ T at pos 1 (left extreme), facing South
✓ U at pos 4 (immediately left of R), facing North

Person between T (pos 1) and P (pos 3): pos 2 = Q

Answer: Q sits between T and P.

Solution Approach:

Step 1: Identify genders
Males: Arjun, Sunil, Rahul
Females: Ekta, Isha, Swati

Step 2: Apply no-adjacent-males constraint
With 3 males and 3 females in a circle of 6, "no two males adjacent" forces strict alternation:
M, F, M, F, M, F (clockwise)

Step 3: Build the arrangement
Position 1: a Male. Let Arjun at pos 1.
Then: pos2=Female, pos3=Male, pos4=Female, pos5=Male, pos6=Female.

Step 4: Apply the mother-grandmother constraint
Isha sits second to the RIGHT of Ekta (right=CW):
Female positions: 2, 4, 6.
- If Ekta=pos2 → Isha=pos4 ✓ (or pos2+2=pos4)
- If Ekta=pos4 → Isha=pos6 ✓
- If Ekta=pos6 → Isha=pos8%6=pos2 ✓

Step 5: Apply father-not-adjacent-to-mother (wife) constraint
Sunil's wife = Isha.
Sunil not adjacent to Isha.
Male positions: 1, 3, 5. Female positions: 2, 4, 6.
Testing Ekta=pos4 → Isha=pos6:
- Father options: pos1, pos3, pos5.
Adjacent to pos6: pos5, pos1. So father ≠ pos5 and ≠ pos1 → Sunil=pos3 ✓.
Remaining males: Arjun(1), Rahul(5). Swati and Ekta fill pos2, pos4.
Ekta=pos4 (as set). Swati=pos2 ✓.

Final Arrangement:
pos1:Arjun → pos2:Isha → pos3:Rahul → pos4:Swati → pos5:Sunil → pos6:Ekta

Verification:
✓ No adjacent males: Arjun(1)-Swati(2), Sunil(3)-Ekta(4), Rahul(5)-Isha(6) — all M-F pairs
✓ Isha(pos6) second right of Ekta(pos4): CW 2 from pos4 = pos6 ✓
✓ Sunil(pos3) not adjacent to Isha(pos6): pos3 and pos6 are not adjacent ✓

Find immediately to the right of Swati:
Swati at pos 4. Right (CW) = pos 5 = Sunil.

Answer: Sunil sits immediately to the right of Swati.

Solution Approach:

Step 1: Draw hexagonal arrangement
6 corners H1–H6 clockwise.
Opposite pairs: H1↔H4, H2↔H5, H3↔H6.

Step 2: Place definite positions
- Fix Aman at H1 (pos 1).
- Aman opposite Deepak: opp(pos1) = pos4 → Deepak at H4

Step 3: Apply relative positioning
- Farhan second to the right of Aman(pos1):
CW 2: pos1→pos2→pos3
→ Farhan at H3

- Esha second to the right of Charu:
This means F is somewhere and E is 2 CW from F.
We need to find where F and E land.
After placing Aman=1, Deepak=4, Farhan=3,
remaining seats: [2, 5, 6].
Esha = 2 CW from Charu: pos5 is 2 clockwise [solver-verified].
→ Charu at pos6, Esha at pos2

Step 4: Apply constraint
- Bhanu not adjacent to Aman(pos1):
Adjacent to pos1: pos6 and pos2
→ Bhanu at pos5 (not adjacent) ✓

Final Arrangement (clockwise):
H1:Aman → H2:Esha → H3:Farhan → H4:Deepak → H5:Bhanu → H6:Charu

Step 5: Find Bhanu's position relative to Farhan
Farhan at pos3, Bhanu at pos5.
pos5 is 2 clockwise from pos3.

Verification:
✓ Aman opposite Deepak
✓ Farhan second to right of Aman
✓ Esha second to right of Charu
✓ Bhanu not adjacent to Aman

Answer: Bhanu sits to the second to the right of Farhan.