Question 1
Ten persons D, I, G, A, F, H, E, J, C and B are sitting around a rectangular table.
Three persons sit on each longer side, two on each shorter side, all facing the center.
D sits at the middle of a longer side. I sits at the middle of a shorter side.
G sits second to the right of D. F sits at a corner and A sits at the corner opposite to F.
Who sits second to the left of I?
Solution Approach:
Step 1: Draw rectangular table
Positions 1β10 clockwise:
- Top (longer, 3 persons): pos1(corner-TL), pos2(mid-top), pos3(corner-TR)
- Right (shorter, 2 persons): pos4(mid-right), pos5(corner-BR)
- Bottom (longer, 3 persons): pos6(mid-bot), pos7(corner-BL-ish... wait, pos7 is mid-bottom)
Correction: pos6(mid-bot), pos7(mid-bot2), pos8(corner-BL) β actually:
Bottom traversed rightβleft: pos6(mid), pos7(mid2)? For 3 persons: corner is shared with adjacent side.
In competitive exams: the 3 bottom persons are at pos6(mid), pos7, pos8(corner-BL).
Actually pos6,7,8 with pos8=BL-corner and pos5=BR-corner. β
- Left (shorter, 2 persons): pos9(mid-left), pos10(mid-left2)
- Corners: pos1(TL), pos3(TR), pos5(BR), pos8(BL)
- Longer-side midpoints: pos2(top), pos7(bottom)
- Shorter-side midpoints: pos4(right), pos9(left)
Step 2: Place persons
- D at middle of longer side β pos 7 (mid-bottom)
- I at middle of shorter side β pos 4 (mid-right)
- G second to the RIGHT of D (pos 7):
right(center-facing)=CW: pos7+2 = pos9 β G β
- F at a corner β pos 1
- A at corner OPPOSITE to F: pos5 β A β
- H second to the LEFT of I (pos 4):
left(center-facing)=anti-CW: pos4-2 = pos2 β H β
Step 3: Fill remaining positions
Remaining persons: E, J, C, B
Remaining seats: [3, 6, 8, 10]
Final Arrangement (clockwise):
pos1:F | pos2:H | pos3:E | pos4:I | pos5:A | pos6:J | pos7:D | pos8:C | pos9:G | pos10:B
Find second to the left of I (pos 4):
Left (anti-CW): pos4 β pos3 β pos2 = H
Answer: H sits second to the left of I.
Step 1: Draw rectangular table
Positions 1β10 clockwise:
- Top (longer, 3 persons): pos1(corner-TL), pos2(mid-top), pos3(corner-TR)
- Right (shorter, 2 persons): pos4(mid-right), pos5(corner-BR)
- Bottom (longer, 3 persons): pos6(mid-bot), pos7(corner-BL-ish... wait, pos7 is mid-bottom)
Correction: pos6(mid-bot), pos7(mid-bot2), pos8(corner-BL) β actually:
Bottom traversed rightβleft: pos6(mid), pos7(mid2)? For 3 persons: corner is shared with adjacent side.
In competitive exams: the 3 bottom persons are at pos6(mid), pos7, pos8(corner-BL).
Actually pos6,7,8 with pos8=BL-corner and pos5=BR-corner. β
- Left (shorter, 2 persons): pos9(mid-left), pos10(mid-left2)
- Corners: pos1(TL), pos3(TR), pos5(BR), pos8(BL)
- Longer-side midpoints: pos2(top), pos7(bottom)
- Shorter-side midpoints: pos4(right), pos9(left)
Step 2: Place persons
- D at middle of longer side β pos 7 (mid-bottom)
- I at middle of shorter side β pos 4 (mid-right)
- G second to the RIGHT of D (pos 7):
right(center-facing)=CW: pos7+2 = pos9 β G β
- F at a corner β pos 1
- A at corner OPPOSITE to F: pos5 β A β
- H second to the LEFT of I (pos 4):
left(center-facing)=anti-CW: pos4-2 = pos2 β H β
Step 3: Fill remaining positions
Remaining persons: E, J, C, B
Remaining seats: [3, 6, 8, 10]
Final Arrangement (clockwise):
pos1:F | pos2:H | pos3:E | pos4:I | pos5:A | pos6:J | pos7:D | pos8:C | pos9:G | pos10:B
Find second to the left of I (pos 4):
Left (anti-CW): pos4 β pos3 β pos2 = H
Answer: H sits second to the left of I.