ReasoningAbility.com

Staff Shift Fairness: Worksheet 10 - Expert Practice Staff Shift Fairness EXPERT

Ready to master Staff Shift Fairness? This accuracy focus 👑 worksheet (10/10) presents 20 expert-level challenges. Focus area: application-based learning. Learn to solve staff shift fairness reasoning tricks, handle fast staff shift fairness solving, and perfect staff shift fairness mastery with our step-by-step solutions.

📝 Worksheet 10 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Expert level

What you'll learn in this worksheet:
Your progress through Staff Shift Fairness
Worksheet 10 of 10 (100% complete)

Question 1

A hospital needs to schedule 5 staff for 7 days (Thursday, Monday, Saturday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 1 points
- Bob: 3 points
- Carol: 7 points
- Emma: 3 points
- Frank: 1 points

4. Fairness gap: 7 - 1 = 6

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 2

A hospital needs to schedule 5 staff for 7 days (Friday, Saturday, Thursday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Bob: 5 points
- Carol: 0 points
- David: 5 points
- Emma: 0 points
- Frank: 5 points

4. Fairness gap: 5 - 0 = 5

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 3

A hospital needs to schedule 5 staff for 7 days (Tuesday, Friday, Saturday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 4 points
- Bob: 5 points
- Carol: 2 points
- Emma: 1 points
- Frank: 3 points

4. Fairness gap: 5 - 1 = 4

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 4

A hospital needs to schedule 5 staff for 7 days (Thursday, Monday, Wednesday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 3 points
- Carol: 1 points
- David: 6 points
- Emma: 1 points
- Frank: 4 points

4. Fairness gap: 6 - 1 = 5

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 5

A hospital needs to schedule 5 staff for 7 days (Saturday, Tuesday, Monday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 1 points
- Bob: 0 points
- Carol: 8 points
- David: 4 points
- Emma: 2 points

4. Fairness gap: 8 - 0 = 8

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 6

A hospital needs to schedule 5 staff for 7 days (Friday, Tuesday, Thursday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Bob: 4 points
- Carol: 2 points
- David: 3 points
- Emma: 3 points
- Frank: 3 points

4. Fairness gap: 4 - 2 = 2

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 7

A hospital needs to schedule 5 staff for 7 days (Thursday, Friday, Monday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 3 points
- Bob: 4 points
- Carol: 3 points
- David: 1 points
- Emma: 4 points

4. Fairness gap: 4 - 1 = 3

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 8

A hospital needs to schedule 5 staff for 7 days (Sunday, Friday, Wednesday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 0 points
- Bob: 4 points
- Carol: 3 points
- David: 7 points
- Emma: 1 points

4. Fairness gap: 7 - 0 = 7

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 9

A hospital needs to schedule 5 staff for 7 days (Tuesday, Friday, Saturday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 2 points
- Bob: 4 points
- Carol: 1 points
- David: 5 points
- Frank: 3 points

4. Fairness gap: 5 - 1 = 4

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 10

A hospital needs to schedule 5 staff for 7 days (Sunday, Wednesday, Tuesday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 0 points
- Bob: 2 points
- David: 1 points
- Emma: 7 points
- Frank: 5 points

4. Fairness gap: 7 - 0 = 7

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 11

A hospital needs to schedule 5 staff for 7 days (Friday, Tuesday, Thursday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 3 points
- Bob: 2 points
- David: 4 points
- Emma: 3 points
- Frank: 3 points

4. Fairness gap: 4 - 2 = 2

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 12

A hospital needs to schedule 5 staff for 7 days (Sunday, Thursday, Saturday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 1 points
- Carol: 4 points
- David: 5 points
- Emma: 1 points
- Frank: 4 points

4. Fairness gap: 5 - 1 = 4

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 13

A hospital needs to schedule 5 staff for 7 days (Monday, Saturday, Tuesday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Bob: 1 points
- Carol: 1 points
- David: 9 points
- Emma: 2 points
- Frank: 2 points

4. Fairness gap: 9 - 1 = 8

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 14

A hospital needs to schedule 5 staff for 7 days (Sunday, Friday, Wednesday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 3 points
- Bob: 3 points
- Carol: 4 points
- Emma: 5 points
- Frank: 0 points

4. Fairness gap: 5 - 0 = 5

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 15

A hospital needs to schedule 5 staff for 7 days (Sunday, Monday, Friday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 5 points
- Bob: 3 points
- Carol: 1 points
- David: 1 points
- Emma: 5 points

4. Fairness gap: 5 - 1 = 4

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 16

A hospital needs to schedule 5 staff for 7 days (Tuesday, Friday, Sunday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 2 points
- Carol: 2 points
- David: 5 points
- Emma: 3 points
- Frank: 3 points

4. Fairness gap: 5 - 2 = 3

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 17

A hospital needs to schedule 5 staff for 7 days (Thursday, Tuesday, Saturday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 0 points
- Bob: 6 points
- Carol: 3 points
- David: 2 points
- Frank: 4 points

4. Fairness gap: 6 - 0 = 6

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 18

A hospital needs to schedule 5 staff for 7 days (Wednesday, Thursday, Monday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Bob: 2 points
- Carol: 4 points
- David: 3 points
- Emma: 2 points
- Frank: 4 points

4. Fairness gap: 4 - 2 = 2

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 19

A hospital needs to schedule 5 staff for 7 days (Tuesday, Wednesday, Saturday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 5 points
- Bob: 5 points
- Carol: 2 points
- David: 2 points
- Frank: 1 points

4. Fairness gap: 5 - 1 = 4

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 20

A hospital needs to schedule 5 staff for 7 days (Tuesday, Friday, Saturday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 4 points
- Bob: 1 points
- Carol: 2 points
- David: 3 points
- Frank: 5 points

4. Fairness gap: 5 - 1 = 4

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.
Previous Worksheet