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Master Staff Shift Fairness - Intermediate-Advanced Level Problems Staff Shift Fairness INTERMEDIATE ADVANCED

Excel in competitive exams with this self assessment worksheet on Staff Shift Fairness. Worksheet 7 of 10 contains 20 intermediate-advanced-level problems. Target your accuracy improvement skills while practicing staff shift fairness shortcut methods, staff shift fairness bank exam questions, and staff shift fairness ssc cgl.

📝 Worksheet 7 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Intermediate Advanced level

What you'll learn in this worksheet:
Your progress through Staff Shift Fairness
Worksheet 7 of 10 (66% complete)

Question 1

A hospital needs to schedule 5 staff for 7 days (Saturday, Sunday, Monday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 3 points
- Bob: 3 points
- Carol: 6 points
- David: 1 points
- Frank: 2 points

4. Fairness gap: 6 - 1 = 5

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 2

A hospital needs to schedule 5 staff for 7 days (Saturday, Friday, Sunday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 3 points
- Bob: 3 points
- Carol: 3 points
- David: 2 points
- Emma: 4 points

4. Fairness gap: 4 - 2 = 2

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 3

A hospital needs to schedule 5 staff for 7 days (Sunday, Tuesday, Wednesday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 3 points
- Bob: 5 points
- Carol: 1 points
- Emma: 1 points
- Frank: 5 points

4. Fairness gap: 5 - 1 = 4

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 4

A hospital needs to schedule 5 staff for 7 days (Wednesday, Monday, Tuesday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 0 points
- Bob: 5 points
- Carol: 2 points
- Emma: 5 points
- Frank: 3 points

4. Fairness gap: 5 - 0 = 5

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 5

A hospital needs to schedule 5 staff for 7 days (Wednesday, Tuesday, Saturday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 1 points
- Bob: 1 points
- Carol: 9 points
- David: 1 points
- Frank: 3 points

4. Fairness gap: 9 - 1 = 8

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 6

A hospital needs to schedule 5 staff for 7 days (Saturday, Thursday, Sunday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 1 points
- Carol: 4 points
- David: 2 points
- Emma: 6 points
- Frank: 2 points

4. Fairness gap: 6 - 1 = 5

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 7

A hospital needs to schedule 5 staff for 7 days (Thursday, Tuesday, Saturday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 4 points
- Bob: 7 points
- Carol: 1 points
- Emma: 0 points
- Frank: 3 points

4. Fairness gap: 7 - 0 = 7

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 8

A hospital needs to schedule 5 staff for 7 days (Friday, Wednesday, Saturday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 4 points
- Bob: 0 points
- David: 3 points
- Emma: 6 points
- Frank: 2 points

4. Fairness gap: 6 - 0 = 6

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 9

A hospital needs to schedule 5 staff for 7 days (Sunday, Friday, Tuesday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 3 points
- Bob: 6 points
- Carol: 0 points
- David: 1 points
- Emma: 5 points

4. Fairness gap: 6 - 0 = 6

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 10

A hospital needs to schedule 5 staff for 7 days (Wednesday, Tuesday, Sunday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 5 points
- Bob: 2 points
- Carol: 4 points
- David: 3 points
- Emma: 1 points

4. Fairness gap: 5 - 1 = 4

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 11

A hospital needs to schedule 5 staff for 7 days (Sunday, Monday, Saturday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 1 points
- Bob: 5 points
- David: 0 points
- Emma: 1 points
- Frank: 8 points

4. Fairness gap: 8 - 0 = 8

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 12

A hospital needs to schedule 5 staff for 7 days (Friday, Saturday, Monday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Bob: 3 points
- Carol: 0 points
- David: 9 points
- Emma: 2 points
- Frank: 1 points

4. Fairness gap: 9 - 0 = 9

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 13

A hospital needs to schedule 5 staff for 7 days (Friday, Saturday, Sunday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 1 points
- Bob: 1 points
- Carol: 5 points
- Emma: 6 points
- Frank: 2 points

4. Fairness gap: 6 - 1 = 5

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 14

A hospital needs to schedule 5 staff for 7 days (Thursday, Wednesday, Monday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Bob: 3 points
- Carol: 4 points
- David: 2 points
- Emma: 5 points
- Frank: 1 points

4. Fairness gap: 5 - 1 = 4

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 15

A hospital needs to schedule 5 staff for 7 days (Monday, Wednesday, Tuesday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 0 points
- Bob: 4 points
- Carol: 3 points
- David: 6 points
- Frank: 2 points

4. Fairness gap: 6 - 0 = 6

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 16

A hospital needs to schedule 5 staff for 7 days (Thursday, Friday, Saturday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 1 points
- Bob: 0 points
- Carol: 5 points
- David: 5 points
- Frank: 4 points

4. Fairness gap: 5 - 0 = 5

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 17

A hospital needs to schedule 5 staff for 7 days (Monday, Sunday, Tuesday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 3 points
- Bob: 3 points
- Carol: 4 points
- Emma: 3 points
- Frank: 2 points

4. Fairness gap: 4 - 2 = 2

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 18

A hospital needs to schedule 5 staff for 7 days (Sunday, Friday, Tuesday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 4 points
- Bob: 5 points
- Carol: 2 points
- Emma: 4 points
- Frank: 0 points

4. Fairness gap: 5 - 0 = 5

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 19

A hospital needs to schedule 5 staff for 7 days (Friday, Sunday, Tuesday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Alice: 2 points
- Bob: 4 points
- Carol: 4 points
- David: 4 points
- Emma: 1 points

4. Fairness gap: 4 - 1 = 3

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.

Question 20

A hospital needs to schedule 5 staff for 7 days (Wednesday, Thursday, Monday...). Each day has 3 shifts: Morning, Evening, Night. Undesirable shifts (higher weight = more undesirable): - Weekend Night: weight 3 - Weekend Evening: weight 2 - Any Night: weight 1 After creating a fair schedule, what is the fairness gap (difference between max and min undesirable weights assigned to any staff)?
Step-by-step solution (Fairness Scheduling):

1. Total shifts to assign:
- 7 days × 3 shifts = 21 shifts
2. Shifts per person: 21 ÷ 5 = 4 with 1 extra shifts
3. Undesirable weight distribution:
- Bob: 7 points
- Carol: 0 points
- David: 4 points
- Emma: 4 points
- Frank: 0 points

4. Fairness gap: 7 - 0 = 7

Key Strategy: Fair scheduling aims to minimize the maximum difference in undesirable shift assignments across all staff.
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