Question 1
In how many ways can non-negative integer solutions be given to the equation x1 + x2 + ... + x5 = 11 (where each recipient can receive zero or more)? Or, find the number of the equation x1 + x2 + ... + x5 = 11.
Step-by-Step Solution (Stars and Bars):
Concept: This problem is equivalent to finding the number of non-negative integer solutions to $x_1 + x_2 + \dots + x_{k} = {n}$. This is a distribution problem of identical items ({n} 'stars') into distinct containers ({k} 'bins') using {k-1} separators ('bars').
Formula: The number of solutions is $\text{C}(n + k - 1, k - 1)$.
- $n$ = number of identical items (stars) = {n}
- $k$ = number of distinct recipients (bins) = {k}
Calculation:
Total arrangements = $\text{C}({n} + {k} - 1, {k} - 1)$
= $\text{C}({n + k - 1}, {k - 1})$
= {answer}
Key Distinction:
- Identical Items, Distinct Boxes (Stars and Bars): $\text{C}(n+k-1, k-1)$
- Distinct Items, Distinct Boxes (Distribution): $k^n$
Verification: This method guarantees that all solutions are non-negative ($x_i \ge 0$).
Concept: This problem is equivalent to finding the number of non-negative integer solutions to $x_1 + x_2 + \dots + x_{k} = {n}$. This is a distribution problem of identical items ({n} 'stars') into distinct containers ({k} 'bins') using {k-1} separators ('bars').
Formula: The number of solutions is $\text{C}(n + k - 1, k - 1)$.
- $n$ = number of identical items (stars) = {n}
- $k$ = number of distinct recipients (bins) = {k}
Calculation:
Total arrangements = $\text{C}({n} + {k} - 1, {k} - 1)$
= $\text{C}({n + k - 1}, {k - 1})$
= {answer}
Key Distinction:
- Identical Items, Distinct Boxes (Stars and Bars): $\text{C}(n+k-1, k-1)$
- Distinct Items, Distinct Boxes (Distribution): $k^n$
Verification: This method guarantees that all solutions are non-negative ($x_i \ge 0$).