Rank of Word

Rank of a word is its position when all permutations of its letters are arranged in dictionary (alphabetical) order. For example, the word 'MOTHER' has a certain rank among all 6! = 720 permutations of its letters. Ranking requires systematically counting how many words come before the given word.

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Introduction to Rank of Word

Rank of a word is its position when all permutations of its letters are arranged in dictionary (alphabetical) order. For example, the word 'MOTHER' has a certain rank among all 6! = 720 permutations of its letters. Ranking requires systematically counting how many words come before the given word.

Prerequisites

Permutation with identical objects Factorial concept Alphabetical ordering Systematic counting
Why This Matters: Rank of Word problems appear in 1-2 questions in advanced exams like CAT. They test understanding of permutations and systematic counting.

How to Solve Rank of Word Problems

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Step 1: Write the word and sort its letters alphabetically

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Step 2: Initialize rank = 1 (starting position)

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Step 3: For each position from left to right:

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Step 4: Count letters smaller than the current letter that are still available

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Step 5: For each such smaller letter, calculate permutations of remaining letters

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Step 6: Add these counts to rank

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Step 7: Remove the current letter from available letters and move to next position

Pro Strategy: Work from left to right. At each position, count how many letters smaller than the current letter are still available. For each such smaller letter, compute the number of permutations of the remaining letters (using factorial, accounting for repeats). Sum these counts, then add 1 at the end.

Example Problem

Example: Find the rank of the word 'MOTHER' among its permutations. Solution: Step 1: Alphabetical order of letters: E, H, M, O, R, T Step 2: Rank starts at 1 Step 3: Position 1: 'M' - letters before M: E, H (2 letters) - For E: remaining letters (H,M,O,R,T) = 5! = 120 - For H: remaining letters (E,M,O,R,T) = 5! = 120 - Add 240 to rank → rank = 241 Step 4: Remove M, remaining: E,H,O,R,T. Current letter: 'O' - Letters before O: E, H (2 letters) - For each: 4! = 24 → add 48 → rank = 289 Step 5: Remove O, remaining: E,H,R,T. Current letter: 'T' - Letters before T: E, H, R (3 letters) - For each: 3! = 6 → add 18 → rank = 307 Step 6: Remove T, remaining: E,H,R. Current letter: 'H' - Letters before H: E (1 letter) → 2! = 2 → add 2 → rank = 309 Step 7: Remove H, remaining: E,R. Current letter: 'E' - No letters before E → add 0 Step 8: Last letter: 'R' → rank = 309 Answer: 309th

Pro Tips & Tricks

  • Sort the letters alphabetically before starting
  • For repeated letters, divide by factorials of repeated letter counts
  • Rank = 1 + sum of (number of permutations with smaller letter at each position)
  • When a letter repeats, treat identical letters as indistinguishable
  • For words with repeated letters, use n!/(p! × q! × ...) for permutations
  • Double-check the count of smaller letters at each position

Shortcut Methods to Solve Faster

For words with all distinct letters: use factorial for remaining positions
For repeated letters: divide by factorials of repeat counts
Rank of a word = 1 + Σ (smaller letters count × permutations of remaining)
Practice with smaller words to understand the method

Common Mistakes to Avoid

Forgetting to account for repeated letters in permutations
Not starting rank from 1 (some methods start from 0)
Missing smaller letters that are available at each position
Using 6! when letters are not all distinct

Exam Importance

Rank of Word is an important topic for various competitive exams. Here's how frequently it appears:

SSC CGL
0-1 questions
BANKING PO
0-1 questions
RAILWAYS RRB
0-1 questions
CAT
1-2 questions
INSURANCE
0-1 questions

Ready to Master Rank of Word?

Start with Worksheet 1 and work your way up to expert level! Each worksheet includes:

20 practice questions
Detailed solutions
Step-by-step explanations
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