Question 1
There are 10 points in a plane, of which 4 are collinear. How many triangles can be formed by joining these points?
Step-by-Step Solution:
Concept: Geometrical combination with constraint. Three collinear points cannot form a triangle.
Strategy: Use complementary counting:
Total valid triangles = All possible triangles - Invalid triangles
Given:
- Total points: 10
- Collinear points: 4
Triangle Formation Rule: We need exactly 3 non-collinear points to form a triangle.
Step 1 - Calculate Total Possible Selections:
Selecting any 3 points from 10 points: C(10,3)
C(10,3) = 10! / [3! × 7!] = 120
Step 2 - Calculate Invalid Triangles:
3 collinear points don't form a triangle.
Selecting 3 points from 4 collinear points: C(4,3)
C(4,3) = 4! / [3! × 1!] = 4
Step 3 - Apply Complementary Counting:
Valid triangles = Total selections - Invalid selections
= 120 - 4
= 116
Key Technique: Complementary counting is often easier than direct counting when dealing with restrictions.
Verification: Answer should be less than C(10,3) = 120 since we have a constraint.
Related Concepts:
- For lines from n points: C(n,2) - (collinear points consideration)
- For quadrilaterals: C(n,4) with appropriate constraints
Concept: Geometrical combination with constraint. Three collinear points cannot form a triangle.
Strategy: Use complementary counting:
Total valid triangles = All possible triangles - Invalid triangles
Given:
- Total points: 10
- Collinear points: 4
Triangle Formation Rule: We need exactly 3 non-collinear points to form a triangle.
Step 1 - Calculate Total Possible Selections:
Selecting any 3 points from 10 points: C(10,3)
C(10,3) = 10! / [3! × 7!] = 120
Step 2 - Calculate Invalid Triangles:
3 collinear points don't form a triangle.
Selecting 3 points from 4 collinear points: C(4,3)
C(4,3) = 4! / [3! × 1!] = 4
Step 3 - Apply Complementary Counting:
Valid triangles = Total selections - Invalid selections
= 120 - 4
= 116
Key Technique: Complementary counting is often easier than direct counting when dealing with restrictions.
Verification: Answer should be less than C(10,3) = 120 since we have a constraint.
Related Concepts:
- For lines from n points: C(n,2) - (collinear points consideration)
- For quadrilaterals: C(n,4) with appropriate constraints