Averages and Mixtures

Averages and Mixtures Data Sufficiency problems test your ability to determine if given statements provide enough information to find average values, mixture ratios, or quantities in blends. You must assess sufficiency using weighted average formulas and alligation methods.

10Worksheets
200+Practice Questions
IntermediateDifficulty
2-3 hoursHours to Master

Introduction to Averages and Mixtures

Averages and Mixtures Data Sufficiency problems test your ability to determine if given statements provide enough information to find average values, mixture ratios, or quantities in blends. You must assess sufficiency using weighted average formulas and alligation methods.

Prerequisites

Average = Sum of values / Number of values Weighted average formula Alligation method for mixtures Sum of values = Average × Count
Why This Matters: Averages and Mixtures appear in 1-2 questions in CAT and Banking PO exams. They test weighted average reasoning and sufficiency analysis.

How to Solve Averages and Mixtures Problems

1

Step 1: Identify what is being asked (average, total sum, mixture ratio, etc.)

2

Step 2: Translate each statement into average or mixture equations

3

Step 3: Check if Statement (1) alone gives a unique answer

4

Step 4: Check if Statement (2) alone gives a unique answer

5

Step 5: Combine statements if needed

6

Step 6: Remember: Sum = Average × Count for each group

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Step 7: Select the appropriate DS answer choice

Pro Strategy: Average = Total Sum / Count. If total sum is given, average is found. For weighted average, need sum of each group and count of each group.

Example Problem

Example: What is the average of 5 numbers? Statement (1): Sum of the 5 numbers is 250. Statement (2): The numbers are in arithmetic progression with first term 40. Solution: Step 1: Question asks for average Step 2: Statement (1): Average = 250/5 = 50 → SUFFICIENT alone Step 3: Statement (2): AP with first term 40, but no information about common difference or other terms → NOT sufficient alone Answer: Statement (1) alone is sufficient

Pro Tips & Tricks

  • Total sum + Count → sufficient for average
  • Average + Count → sufficient for total sum
  • Two groups: need total sum of each group (or average and count) to find combined average
  • Weighted average alone without counts → insufficient to find individual group sums
  • Mixture problems: need quantities and concentrations to find final concentration
  • Alligation: need two concentrations and final concentration to find ratio

Shortcut Methods to Solve Faster

Average = Sum / Count
Combined average = (n₁ × A₁ + n₂ × A₂) / (n₁ + n₂)
Alligation ratio = (higher - middle) : (middle - lower)
If all numbers in AP, average = (first + last)/2 = middle term

Common Mistakes to Avoid

Assuming average alone gives total sum (need count too)
Confusing weighted average with simple average
Thinking all numbers in AP means average is known without more info
Forgetting that mixture ratio alone doesn't give absolute quantities

Exam Importance

Averages and Mixtures is an important topic for various competitive exams. Here's how frequently it appears:

CAT
1-2 questions
GMAT
1-2 questions
BANKING PO
1-2 questions
SSC CGL
1-2 questions
INSURANCE
1-2 questions

Ready to Master Averages and Mixtures?

Start with Worksheet 1 and work your way up to expert level! Each worksheet includes:

20 practice questions
Detailed solutions
Step-by-step explanations
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