hypothetical_count_change - Intermediate Level: tricky scenarios handling hypothetical_count_change INTERMEDIATE

First, solve the original puzzle:
- If Leena is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Leena and Ravi same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Leena=T, Farhan=T, Ravi=L

Now, hypothetically assume Leena is liar instead of truth-teller.
Then we need to re-solve:
- Leena liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Leena truth - contradicts Leena liar.
- If 2 liars, then Farhan and Ravi are liars. Then Farhan liar says 'Leena and Ravi same type' - Leena liar, Ravi liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Farhan liar says 'Leena and Ravi same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Leena is liar.
Thus, if we hypothetically assume Leena is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Rohan is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Rohan and Kiran same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Rohan=T, Rahul=T, Kiran=L

Now, hypothetically assume Rohan is liar instead of truth-teller.
Then we need to re-solve:
- Rohan liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Rohan truth - contradicts Rohan liar.
- If 2 liars, then Rahul and Kiran are liars. Then Rahul liar says 'Rohan and Kiran same type' - Rohan liar, Kiran liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Rahul liar says 'Rohan and Kiran same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Rohan is liar.
Thus, if we hypothetically assume Rohan is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Amit is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Amit and Sunil same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Amit=T, Divya=T, Sunil=L

Now, hypothetically assume Amit is liar instead of truth-teller.
Then we need to re-solve:
- Amit liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Amit truth - contradicts Amit liar.
- If 2 liars, then Divya and Sunil are liars. Then Divya liar says 'Amit and Sunil same type' - Amit liar, Sunil liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Divya liar says 'Amit and Sunil same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Amit is liar.
Thus, if we hypothetically assume Amit is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Kiran is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Kiran and Sanjay same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Kiran=T, Amit=T, Sanjay=L

Now, hypothetically assume Kiran is liar instead of truth-teller.
Then we need to re-solve:
- Kiran liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Kiran truth - contradicts Kiran liar.
- If 2 liars, then Amit and Sanjay are liars. Then Amit liar says 'Kiran and Sanjay same type' - Kiran liar, Sanjay liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Amit liar says 'Kiran and Sanjay same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Kiran is liar.
Thus, if we hypothetically assume Kiran is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Pooja is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Pooja and Kiran same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Pooja=T, Anita=T, Kiran=L

Now, hypothetically assume Pooja is liar instead of truth-teller.
Then we need to re-solve:
- Pooja liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Pooja truth - contradicts Pooja liar.
- If 2 liars, then Anita and Kiran are liars. Then Anita liar says 'Pooja and Kiran same type' - Pooja liar, Kiran liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Anita liar says 'Pooja and Kiran same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Pooja is liar.
Thus, if we hypothetically assume Pooja is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Amit is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Amit and Rahul same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Amit=T, Pooja=T, Rahul=L

Now, hypothetically assume Amit is liar instead of truth-teller.
Then we need to re-solve:
- Amit liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Amit truth - contradicts Amit liar.
- If 2 liars, then Pooja and Rahul are liars. Then Pooja liar says 'Amit and Rahul same type' - Amit liar, Rahul liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Pooja liar says 'Amit and Rahul same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Amit is liar.
Thus, if we hypothetically assume Amit is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Harsha is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Harsha and Neha same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Harsha=T, Sanjay=T, Neha=L

Now, hypothetically assume Harsha is liar instead of truth-teller.
Then we need to re-solve:
- Harsha liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Harsha truth - contradicts Harsha liar.
- If 2 liars, then Sanjay and Neha are liars. Then Sanjay liar says 'Harsha and Neha same type' - Harsha liar, Neha liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Sanjay liar says 'Harsha and Neha same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Harsha is liar.
Thus, if we hypothetically assume Harsha is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Divya is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Divya and Amit same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Divya=T, Pooja=T, Amit=L

Now, hypothetically assume Divya is liar instead of truth-teller.
Then we need to re-solve:
- Divya liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Divya truth - contradicts Divya liar.
- If 2 liars, then Pooja and Amit are liars. Then Pooja liar says 'Divya and Amit same type' - Divya liar, Amit liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Pooja liar says 'Divya and Amit same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Divya is liar.
Thus, if we hypothetically assume Divya is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Meera is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Meera and Gaurav same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Meera=T, Rohan=T, Gaurav=L

Now, hypothetically assume Meera is liar instead of truth-teller.
Then we need to re-solve:
- Meera liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Meera truth - contradicts Meera liar.
- If 2 liars, then Rohan and Gaurav are liars. Then Rohan liar says 'Meera and Gaurav same type' - Meera liar, Gaurav liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Rohan liar says 'Meera and Gaurav same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Meera is liar.
Thus, if we hypothetically assume Meera is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Ravi is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Ravi and Gaurav same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Ravi=T, Rohan=T, Gaurav=L

Now, hypothetically assume Ravi is liar instead of truth-teller.
Then we need to re-solve:
- Ravi liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Ravi truth - contradicts Ravi liar.
- If 2 liars, then Rohan and Gaurav are liars. Then Rohan liar says 'Ravi and Gaurav same type' - Ravi liar, Gaurav liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Rohan liar says 'Ravi and Gaurav same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Ravi is liar.
Thus, if we hypothetically assume Ravi is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Meera is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Meera and Amit same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Meera=T, Pooja=T, Amit=L

Now, hypothetically assume Meera is liar instead of truth-teller.
Then we need to re-solve:
- Meera liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Meera truth - contradicts Meera liar.
- If 2 liars, then Pooja and Amit are liars. Then Pooja liar says 'Meera and Amit same type' - Meera liar, Amit liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Pooja liar says 'Meera and Amit same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Meera is liar.
Thus, if we hypothetically assume Meera is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Divya is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Divya and Leena same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Divya=T, Rohan=T, Leena=L

Now, hypothetically assume Divya is liar instead of truth-teller.
Then we need to re-solve:
- Divya liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Divya truth - contradicts Divya liar.
- If 2 liars, then Rohan and Leena are liars. Then Rohan liar says 'Divya and Leena same type' - Divya liar, Leena liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Rohan liar says 'Divya and Leena same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Divya is liar.
Thus, if we hypothetically assume Divya is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Manoj is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Manoj and Priya same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Manoj=T, Ravi=T, Priya=L

Now, hypothetically assume Manoj is liar instead of truth-teller.
Then we need to re-solve:
- Manoj liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Manoj truth - contradicts Manoj liar.
- If 2 liars, then Ravi and Priya are liars. Then Ravi liar says 'Manoj and Priya same type' - Manoj liar, Priya liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Ravi liar says 'Manoj and Priya same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Manoj is liar.
Thus, if we hypothetically assume Manoj is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Sunil is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Sunil and Divya same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Sunil=T, Neha=T, Divya=L

Now, hypothetically assume Sunil is liar instead of truth-teller.
Then we need to re-solve:
- Sunil liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Sunil truth - contradicts Sunil liar.
- If 2 liars, then Neha and Divya are liars. Then Neha liar says 'Sunil and Divya same type' - Sunil liar, Divya liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Neha liar says 'Sunil and Divya same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Sunil is liar.
Thus, if we hypothetically assume Sunil is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Pooja is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Pooja and Harsha same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Pooja=T, Divya=T, Harsha=L

Now, hypothetically assume Pooja is liar instead of truth-teller.
Then we need to re-solve:
- Pooja liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Pooja truth - contradicts Pooja liar.
- If 2 liars, then Divya and Harsha are liars. Then Divya liar says 'Pooja and Harsha same type' - Pooja liar, Harsha liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Divya liar says 'Pooja and Harsha same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Pooja is liar.
Thus, if we hypothetically assume Pooja is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Farhan is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Farhan and Divya same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Farhan=T, Pooja=T, Divya=L

Now, hypothetically assume Farhan is liar instead of truth-teller.
Then we need to re-solve:
- Farhan liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Farhan truth - contradicts Farhan liar.
- If 2 liars, then Pooja and Divya are liars. Then Pooja liar says 'Farhan and Divya same type' - Farhan liar, Divya liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Pooja liar says 'Farhan and Divya same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Farhan is liar.
Thus, if we hypothetically assume Farhan is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Anita is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Anita and Sunil same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Anita=T, Neha=T, Sunil=L

Now, hypothetically assume Anita is liar instead of truth-teller.
Then we need to re-solve:
- Anita liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Anita truth - contradicts Anita liar.
- If 2 liars, then Neha and Sunil are liars. Then Neha liar says 'Anita and Sunil same type' - Anita liar, Sunil liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Neha liar says 'Anita and Sunil same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Anita is liar.
Thus, if we hypothetically assume Anita is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Divya is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Divya and Gaurav same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Divya=T, Deepa=T, Gaurav=L

Now, hypothetically assume Divya is liar instead of truth-teller.
Then we need to re-solve:
- Divya liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Divya truth - contradicts Divya liar.
- If 2 liars, then Deepa and Gaurav are liars. Then Deepa liar says 'Divya and Gaurav same type' - Divya liar, Gaurav liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Deepa liar says 'Divya and Gaurav same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Divya is liar.
Thus, if we hypothetically assume Divya is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Harsha is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Harsha and Amit same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Harsha=T, Manoj=T, Amit=L

Now, hypothetically assume Harsha is liar instead of truth-teller.
Then we need to re-solve:
- Harsha liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Harsha truth - contradicts Harsha liar.
- If 2 liars, then Manoj and Amit are liars. Then Manoj liar says 'Harsha and Amit same type' - Harsha liar, Amit liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Manoj liar says 'Harsha and Amit same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Harsha is liar.
Thus, if we hypothetically assume Harsha is liar, there would be ZERO truth-tellers.

First, solve the original puzzle:
- If Gaurav is truth-teller -> exactly one liar -> p2 and p3 are truth-tellers.
Then p2 (truth) says 'Gaurav and Farhan same type' - true (both truth) - consistent.
p3 (truth) says 'at least one truth-teller' - true - consistent.
Solution: Gaurav=T, Harsha=T, Farhan=L

Now, hypothetically assume Gaurav is liar instead of truth-teller.
Then we need to re-solve:
- Gaurav liar -> statement 1 false -> number of liars is NOT exactly one -> 0, 2, or 3 liars.
- If 0 liars, all truth-tellers. Then Gaurav truth - contradicts Gaurav liar.
- If 2 liars, then Harsha and Farhan are liars. Then Harsha liar says 'Gaurav and Farhan same type' - Gaurav liar, Farhan liar -> same type -> true statement, but liar can't make true - contradiction.
- If 3 liars, all are liars. Then Harsha liar says 'Gaurav and Farhan same type' - both liars -> same -> true statement - contradiction.
- Therefore, no consistent assignment exists when Gaurav is liar.
Thus, if we hypothetically assume Gaurav is liar, there would be ZERO truth-tellers.