Question 1
Tournament participants: Gautam, Shiva, Josephine, Jagdish
Given the following clues:
1. Gautam is younger than Shiva
2. Shiva is younger than Josephine
3. Josephine is younger than Jagdish
4. Each person is exactly 5 years older than the person immediately younger than them.
5. Josephine is 30 years old.
Determine Jagdish's age.
Step 1: From clues 1-3, the age order from youngest to oldest is:
Gautam → Shiva → Josephine → Jagdish
Step 2: From clue 4, each consecutive person differs by exactly 5 years.
So if youngest = x, then: Gautam=x, Shiva=x+5, Josephine=x+10, Jagdish=x+15
Step 3: From clue 5, Josephine (the 3rd) = 30
Therefore, x + 10 = 30
Solving: x = 30 - 10 = 20
Step 4: All ages are:
• Gautam = 20
• Shiva = 25
• Josephine = 30
• Jagdish = 35
Step 5: Jagdish is the 4th (oldest).
Therefore, Jagdish = 35
Gautam → Shiva → Josephine → Jagdish
Step 2: From clue 4, each consecutive person differs by exactly 5 years.
So if youngest = x, then: Gautam=x, Shiva=x+5, Josephine=x+10, Jagdish=x+15
Step 3: From clue 5, Josephine (the 3rd) = 30
Therefore, x + 10 = 30
Solving: x = 30 - 10 = 20
Step 4: All ages are:
• Gautam = 20
• Shiva = 25
• Josephine = 30
• Jagdish = 35
Step 5: Jagdish is the 4th (oldest).
Therefore, Jagdish = 35