Question 1
Deepti is 4 times as old as Mia. 3 years ago, the sum of their ages was 59. How old is Mia now?
Let Mia = x, then Deepti = 4x
3 years ago: (4x - 3) + (x - 3) = 59
(4+1)x - 6 = 59
(5)x = 65
x = 13
3 years ago: (4x - 3) + (x - 3) = 59
(4+1)x - 6 = 59
(5)x = 65
x = 13