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Worksheet 3 of 30 (10% complete)
Question 1
In a family of four: Kishore, Sneha, Zane, Vijay. The eldest is 41, youngest is 14. The average age is 29. What is the sum of the ages of the other two members?
Total sum = 29 × 4 = 116 Eldest + youngest = 41 + 14 = 55 Sum of other two = 116 - 55 = 61
Question 2
Darpan and Giridhar are twins. If Darpan is 23 years old now, how old was Giridhar 7 years ago?
Twins have the same age. 7 years ago, both were 23 - 7 = 16
Question 3
If Ram were 7 years younger, she would be 2/5 of Parvathy's age 5 years from now. If Ram is 7 years younger than Parvathy, find Ram's present age.
Four people: Shweta, Neeraj, Jude, Matteo
Given:
1. The sum of all four ages is 148
2. Shweta + Neeraj = 54
3. Matteo is 6 years older than Jude
4. Neeraj is 33 years old
Find Jude's age.
Step 1: From clue 4, Neeraj = 33
Step 2: Using clue 2, we can find the other person in that pair
Step 3: Using clue 3 and clue 1, we can determine all ages
9 years ago, the ratio of Revathi's age to Sanjay's age was 8:3. Currently, the ratio is 5:2. Find Revathi's present age.
Let present ages be 5k and 2k 9 years ago: (5k-9)/(2k-9) = 8/3 Solving gives k = 9, so Revathi = 45
Question 6
In a family, Jagdish : Vrijesh = 7:4 and Vrijesh : Chaman = 4:1. The sum of their ages is 48. Find Vrijesh's age.
Let common ratio for Vrijesh be 4 Then Jagdish:Vrijesh:Chaman = 7:4:1 Sum of ratios = 12 Each unit = 48 ÷ 12 = 4 Vrijesh's age = 4 × 4 = 16
Question 7
Wyatt is twice as old as Prerna was 6 years ago. The difference between their ages is 23 years. How old is Wyatt?
Let Prerna's current age = x Then 6 years ago, Prerna was (x - 6) Wyatt = 2(x - 6) = 2x - 12 Difference: Wyatt - x = (2x - 12) - x = x - 12 Given difference = 23 So x - 12 = 23 → x = 35 = 35 Then Wyatt = 2(35 - 6) = 58
Question 8
Four people: Rowan, Emilia, Leon, Benjamin
Given:
1. The sum of all four ages is 124
2. Rowan + Emilia = 44
3. Benjamin is 6 years older than Leon
4. Emilia is 25 years old
Find Benjamin's age.
Step 1: From clue 4, Emilia = 25
Step 2: Using clue 2, we can find the other person in that pair
Step 3: Using clue 3 and clue 1, we can determine all ages
Tournament participants: Ingrid, Kamini, Hari, Chetan
Given the following clues:
1. Ingrid is younger than Kamini
2. Kamini is younger than Hari
3. Hari is younger than Chetan
4. Each person is exactly 4 years older than the person immediately younger than them.
5. Kamini is 26 years old.
Determine Chetan's age.
Step 1: From clues 1-3, the age order from youngest to oldest is: Ingrid → Kamini → Hari → Chetan
Step 2: From clue 4, each consecutive person differs by exactly 4 years. So if youngest = x, then: Ingrid=x, Kamini=x+4, Hari=x+8, Chetan=x+12
Step 3: From clue 5, Kamini (the 2nd) = 26 Therefore, x + 4 = 26 Solving: x = 26 - 4 = 22
Step 4: All ages are: • Ingrid = 22 • Kamini = 26 • Hari = 30 • Chetan = 34
Step 5: Chetan is the 4th (oldest). Therefore, Chetan = 34
Question 10
If Shailesh were 11 years younger, she would be 3/11 of Aish's age 7 years from now. If Shailesh is 11 years younger than Aish, find Shailesh's present age.
Currently, Maverick is 4/9 of Tucker's age. After 12 years, Maverick will be 1/2 of Tucker's age. Find Maverick's present age.
Let Tucker = x, then Maverick = 4/9x After 12 years: 4/9x + 12 = 1/2(x + 12) Solving gives x = 81, so Maverick = 36
Question 12
If Kavita were 3 years younger, she would be 3/5 of Hudson's age 6 years from now. If Kavita is 9 years younger than Hudson, find Kavita's present age.
Gabriel is 26 years old and Om is 27 years old. What will be their combined age after 9 years?
Gabriel will be 26 + 9 = 35 Om will be 27 + 9 = 36 Combined = 35 + 36 = 71
Question 14
Rachit is 2 times as old as Prasanna. 6 years ago, the sum of their ages was 51. How old is Prasanna now?
Let Prasanna = x, then Rachit = 2x 6 years ago: (2x - 6) + (x - 6) = 51 (2+1)x - 12 = 51 (3)x = 63 x = 21
Question 15
7 years ago, the ratio of Caroline's age to Sloane's age was 4:1. Currently, the ratio is 5:2. Find Caroline's present age.
Let present ages be 5k and 2k 7 years ago: (5k-7)/(2k-7) = 4/1 Solving gives k = 7, so Caroline = 35
Question 16
In a family of four: Vinod, Neelam, Ankur, Rishabh. The youngest is 12 and the eldest is 36. The other two members are 31 and 33. What is the average age of the family?
Sum of all ages = 12 + 31 + 33 + 36 = 112 Average = 112 ÷ 4 = 28
Question 17
Ines and Lily are twins. If Ines is 25 years old now, how old was Lily 4 years ago?
Twins have the same age. 4 years ago, both were 25 - 4 = 21
Question 18
6 years ago, the ratio of Dev's age to Simran's age was 5:2. Currently, the ratio is 4:1. Find Dev's present age.
Let present ages be 4k and 1k 6 years ago: (4k-6)/(1k-6) = 5/2 Solving gives k = 9, so Dev = 36
Question 19
The ratio of Mridul's age to Nirmala's age is 2:9. After 26 years, the ratio will become 3:13. Find Mridul's present age.
Let Mridul = 2k, Nirmala = 9k After 26 years: (2k+26)/(9k+26) = 3/13 Solving gives k = 12, so Mridul = 24
Question 20
When Sarika was born, Shlok was 10 years old. The sum of their present ages is 56. Find Sarika's age when Sarika was half of Shlok's age (this will happen 13 years ago).
Let Sarika's current age = 23, Shlok's current age = 33 Given: When Sarika was born (0 years old), Shlok was 10 years old. Therefore, Shlok is always 10 years older than Sarika. So 33 = 23 + 10 ✓
Condition: Find t such that Sarika's age = ½ of Shlok's age Equation: 23 + t = ½(33 + t) Multiply both sides by 2: 223 + 2t = 33 + t Simplify: 223 + 2t - t = 33 223 + t = 33 t = 33 - 223 t = 33 - 46 = -13
At that time, Sarika's age = 23 + -13 = 10 Verification: When Sarika is 10, Shlok is 20 = 20 Check: Is 10 = ½ × 20? ½ × 20 = 10.0 ✓
Note: Mathematically, this always equals the age difference (10) because: event_age = current_a + t = current_a + (current_b - 2·current_a) = current_b - current_a = age_diff